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Lorentz Invariant kT smearing
Timo Alho, Jan Rak and Sami Räsänen Note: This presentation is based on (parts of) Timo Alho’s Research Training report, i.e. erikoistyö, FYSZ470 + some spices
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Motivation: Assume that kT has 2D Gaussian distribution in
Direct gamma - trigger pTt xEz pout kT away-side fragments - associated particles pTa -h: direct gamma does fix Energy scale if no kT Assume that kT has 2D Gaussian distribution in (kTx,kTy) in LAB frame (CMS of pp). How this is reflected to the pTt and pTa, if the back to back momentum of pair is pT at the pair CMS frame?
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Some kinematics Note: only transverse degrees of freedom “active” when y1=y2
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Kinematical limits Solve k2T: Write M2 in LAB and pair CMS
to obtain dot product of transverse vectors and kinematical limits Solve k2T: You need to solve components of kT vector in order to make a change of variables (kTx,kTy) -> (pTt,pTa) => Lorentz transformation from pair CMS to LAB
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Lorentz boost
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Solve kTx and kTy +- signs of momentun vectors partly cancel
Using results from previous slide Then k2Ty = k2T - k2Tx and you get, up to signs Jacobian
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Main result: Where 0 < p2T pTtpTa Normalization is checked by:
analytic integration Mathematica
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“Spices” Probability to have trigger pTt for given pT and <k2T>
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Analytic solution Mathematica is able to calculate
analytically from later form (but not from original). Result:
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Results 1 P(pTt) pT = 2 GeV/c (<k2T>)1/2 = 3 GeV/c pTt
Figure shows from analytic formula + numerical integration of original and modified expressions; all three are the same Is the analytic result nothing but academic curiosity?
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Results 2 Triangles: Monte Carlo simulation
Solid (red) curve: Timo’s formula Dotted line: Gaussian Note: Gaussian only in the limit pT >> (<k2T>)1/2
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Summary & Outlook
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