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Five-Minute Check (over Lesson 6–3) CCSS Then/Now New Vocabulary
Theorem 6.13: Diagonals of a Rectangle Example 1: Real-World Example: Use Properties of Rectangles Example 2: Use Properties of Rectangles and Algebra Theorem 6.14 Example 3: Real-World Example: Proving Rectangle Relationships Example 4: Rectangles and Coordinate Geometry Lesson Menu
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Determine whether the quadrilateral is a parallelogram.
A. Yes, all sides are congruent. B. Yes, all angles are congruent. C. Yes, diagonals bisect each other. D. No, diagonals are not congruent. 5-Minute Check 1
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Determine whether the quadrilateral is a parallelogram.
A. Yes, both pairs of opposite angles are congruent. B. Yes, diagonals are congruent. C. No, all angles are not congruent. D. No, side lengths are not given. 5-Minute Check 2
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Use the Distance Formula to determine if A(3, 7), B(9, 10), C(10, 6), D(4, 3) are the vertices of a parallelogram. A. yes B. no 5-Minute Check 3
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Use the Slope Formula to determine if R(2, 3), S(–1, 2), T(–1, –2), U(2, –2) are the vertices of a parallelogram. A. yes B. no 5-Minute Check 4
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Given that QRST is a parallelogram, which statement is true?
A. mS = 105 B. mT = 105 C. QT ST D. QT QS ___ 5-Minute Check 5
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G.CO.11 Prove theorems about parallelograms.
Content Standards G.CO.11 Prove theorems about parallelograms. G.GPE.4 Use coordinates to prove simple geometric theorems algebraically. Mathematical Practices 3 Construct viable arguments and critique the reasoning of others. 5 Use appropriate tools strategically. CCSS
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Recognize and apply properties of rectangles.
You used properties of parallelograms and determined whether quadrilaterals were parallelograms. Recognize and apply properties of rectangles. Determine whether parallelograms are rectangles. Then/Now
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rectangle Vocabulary
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Concept 1
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Use Properties of Rectangles
CONSTRUCTION A rectangular garden gate is reinforced with diagonal braces to prevent it from sagging. If JK = 12 feet, and LN = 6.5 feet, find KM. Example 1
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JN + LN = JL Segment Addition LN + LN = JL Substitution
Use Properties of Rectangles Since JKLM is a rectangle, it is a parallelogram. The diagonals of a parallelogram bisect each other, so LN = JN. JN + LN = JL Segment Addition LN + LN = JL Substitution 2LN = JL Simplify. 2(6.5) = JL Substitution 13 = JL Simplify. Example 1
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JL KM If a is a rectangle, diagonals are .
Use Properties of Rectangles JL KM If a is a rectangle, diagonals are . JL = KM Definition of congruence 13 = KM Substitution Answer: KM = 13 feet Example 1
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Quadrilateral EFGH is a rectangle
Quadrilateral EFGH is a rectangle. If GH = 6 feet and FH = 15 feet, find GJ. A. 3 feet B. 7.5 feet C. 9 feet D. 12 feet Example 1
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Use Properties of Rectangles and Algebra
Quadrilateral RSTU is a rectangle. If mRTU = 8x + 4 and mSUR = 3x – 2, find x. Example 2
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mSUT + mSUR = 90 Angle Addition mRTU + mSUR = 90 Substitution
Use Properties of Rectangles and Algebra Since RSTU is a rectangle, it has four right angles. So, mTUR = 90. The diagonals of a rectangle bisect each other and are congruent, so PT PU. Since triangle PTU is isosceles, the base angles are congruent, so RTU SUT and mRTU = mSUT. mSUT + mSUR = 90 Angle Addition mRTU + mSUR = 90 Substitution 8x x – 2 = 90 Substitution 11x + 2 = 90 Add like terms. Example 2
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11x = 88 Subtract 2 from each side. x = 8 Divide each side by 11.
Use Properties of Rectangles and Algebra 11x = 88 Subtract 2 from each side. x = 8 Divide each side by 11. Answer: x = 8 Example 2
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Quadrilateral EFGH is a rectangle
Quadrilateral EFGH is a rectangle. If mFGE = 6x – 5 and mHFE = 4x – 5, find x. A. x = 1 B. x = 3 C. x = 5 D. x = 10 Example 2
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Concept 2
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Proving Rectangle Relationships
ART Some artists stretch their own canvas over wooden frames. This allows them to customize the size of a canvas. In order to ensure that the frame is rectangular before stretching the canvas, an artist measures the sides and the diagonals of the frame. If AB = 12 inches, BC = 35 inches, CD = 12 inches, DA = 35 inches, BD = 37 inches, and AC = 37 inches, explain how an artist can be sure that the frame is rectangular. Example 3
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Since AB = CD, DA = BC, and AC = BD, AB CD, DA BC, and AC BD.
Proving Rectangle Relationships Since AB = CD, DA = BC, and AC = BD, AB CD, DA BC, and AC BD. Answer: Because AB CD and DA BC, ABCD is a parallelogram. Since AC and BD are congruent diagonals in parallelogram ABCD, it is a rectangle. Example 3
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A. Since opp. sides are ||, STUR must be a rectangle.
Max is building a swimming pool in his backyard. He measures the length and width of the pool so that opposite sides are parallel. He also measures the diagonals of the pool to make sure that they are congruent. How does he know that the measure of each corner is 90? A. Since opp. sides are ||, STUR must be a rectangle. B. Since opp. sides are , STUR must be a rectangle. C. Since diagonals of the are , STUR must be a rectangle. D. STUR is not a rectangle. Example 3
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Rectangles and Coordinate Geometry
Quadrilateral JKLM has vertices J(–2, 3), K(1, 4), L(3, –2), and M(0, –3). Determine whether JKLM is a rectangle using the Distance Formula. Step 1 Use the Distance Formula to determine whether JKLM is a parallelogram by determining if opposite sides are congruent. Example 4
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Rectangles and Coordinate Geometry
Since opposite sides of a quadrilateral have the same measure, they are congruent. So, quadrilateral JKLM is a parallelogram. Example 4
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Step 2 Determine whether the diagonals of JKLM are congruent.
Rectangles and Coordinate Geometry Step 2 Determine whether the diagonals of JKLM are congruent. Answer: Since the diagonals have the same measure, they are congruent. So JKLM is a rectangle. Example 4
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Quadrilateral WXYZ has vertices W(–2, 1), X(–1, 3), Y(3, 1), and Z(2, –1). Determine whether WXYZ is a rectangle by using the Distance Formula. A. yes B. no C. cannot be determined Example 4
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Quadrilateral WXYZ has vertices W(–2, 1), X(–1, 3), Y(3, 1), and Z(2, –1). What are the lengths of diagonals WY and XZ? A. B. 4 C. 5 D. 25 Example 4
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End of the Lesson
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