1. Square Root Method Trinomial Method when a = 1 GCF
1A.4 Factoring
Square Root Method
Trinomial Method when a = 1
GCF

2. Solving with Square Roots
Get x2 or the binomial squared by itself
Take the square root of BOTH sides of the equal sign
Don’t forget the  sign
Simplify

3. Solve by Taking Square Roots
X = ± 2i

4. Solve by Taking Square Roots
X = ± 3 2

5. Solve by Taking Square Roots
X = ± 3

6. Solve by Taking Square Roots
X = -4 ± 3 2

7. Solve by Taking Square Roots
5. 5(x – 4)2 = 125
X = -1 and 9

8. Solve by Taking Square Roots
x2 – 2 = -5
X = ± 5

9. Solve by Taking Square Roots
x2 = 243
X = ± 3i 3

10. Solve by Factoring (a=1)
Standard Form of a Quadratic Equation:
ax2 + bx + c = 0
Put the equation in descending order from highest power to lowest power.
List all the factors of c.
Determine which factors of c when added together equal b.
Create two binomials with the variable as the first term and set it equal to zero… (x )(x )= 0
Write in the factors that you determined from step 3.
Set each binomial equal to zero and solve each one for your variable.

11. Solve by Factoring (a=1)
1. 8x + x2 + 7 = 0
x = -7 x = -1

12. Solve by Factoring (a=1)
4. x2 – x – 56 = 0
x = -7 x = 8

13. Solve by Factoring (a=1)
2. n2 – 11n + 10 = 0
n = 10 n = 1

14. Solve by Factoring (a=1)
3. m2 + m – 90 = 0
m = 9 m = -10

15. Solve by Factoring (a=1)
5. x2 – 5x – 104 = 0
x = -8 x = 13

16. Solve by Factoring When There is a Greatest Common Factor(GCF)
Standard Form of a Quadratic Equation:
ax2 + bx + c = 0
When a > 1, examine the factors of a, b and c to determine if there is a GCF (the largest number that a, b & c can all be divided by).
Divide each term of the quadratic equation by the GCF.
Put the GCF in front and the new trinomial from step 2 in parentheses, and set it equal to zero.
Factor the trinomial like normal.

17. Solve by Factoring (GCF)
1. 2x2 + 6x – 108 = 0
x = -9 x = 6

18. Solve by Factoring (GCF)
2. 3x2 + 9x – 54 = 0
x = -6 x = 3