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Week 3 2. Review of inner product spaces

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1 Week 3 2. Review of inner product spaces
۞ An inner product on a vector space V is an operation that assigns to each pair of vectors x and y in V a real number <x, y>, and satisfies the following conditions (axioms): ۞ A vector space with an inner product is called an inner product space.

2 Example 1: The standard inner product (IP) for ℝn is the scalar (dot) product: We can also define a different IP, e.g. where w1, w2, and w3 are positive real numbers (weights). Q: Why do weights have to be positive? Which axiom would be violated if, say, one of the weights is negative or zero?

3 Example 2: The usual inner product for the space C[a, b] of real continuous functions defined on a closed interval [a, b] is (1) ۞ Vectors x and y of an inner product space are called orthogonal if <x, y> = 0. Example 3: Show that the vectors f = [sin x] and g = [cos x] are orthogonal in C[–π, π] with respect to inner product (1).

4 ۞ The norm of a vector x in an inner product space is a real positive number denoted by || x || and equal to Theorem 1: The Cauchy–Schwartz Lemma (CSL) In an inner space, any vectors x and y satisfy where the equality occurs if and only if x and y are parallel, i.e. if either y = const × x or x = const × y.

5 Proof: If y = 0, the CSL holds. Next, consider the case y ≠ 0 and introduce Consider the (obviously correct) inequality (2) hence, Expand the above expression using Axiom (iv) to obtain

6 ...hence, recalling the definition of λ,
(3) which is equivalent to the Cauchy–Schwartz inequality. It remains to prove that...

7 (*) If x and y are parallel, the CSL holds with “=” instead of “≥”.
(**) If the CSL holds with “=”, then x and y are parallel. To prove (*), let x = αy in the CSL and see what happens. To prove (**) observe that replacing “≥” with “=” in CLS implies the same change in (3) – and, hence, in all the previous inequalities including (2) – thus, hence, hence, x is parallel to y, QED (quod erat demonstrandum).

8 ۞ The angle θ between vectors x and y is defined by
The existence of a real θ is guaranteed by CSL (how?). Thus, using inner product, one can define the angle between any objects which can be interpreted as vectors, e.g. functions.

9 3. Metric spaces “Metric” is a fancy word for “distance”. A metric space is a set where, for each pair of elements x and y, we have defined the distance d(x, y) between them. ۞ A metric on a set M is a function d: M×M → ℝ such that, for any x, y, and z in M,

10 Comment: Axiom (A) is superfluous, as it follows from the other three axioms. Indeed, consider (D) with z = x, then take into account (B): then take into account (C), then cancel 2 and thus obtain (A).

11 Comment: Metric spaces are not directly related to vector spaces. A vector space is a metric space only if we define d(x, y) for it. A metric space is a vector space only if we define a vector addition and a vector-by-scalar multiplication for it. Still, we’ll consider many examples which are both vector and metric spaces. Example 4: ℝ2 with make a metric space.

12 Comment: Metric spaces and inner product spaces are related (unlike the former and vector spaces). Theorem 2: An inner product space is always a metric space with Proof: see Q4.3. Comment: A metric space is not necessarily an inner product space (for one thing, the former doesn’t have to be a vector space, whereas the latter does).

13 Example 5: The set C[a, b] of all continuous functions defined on a closed interval [a, b] and make a metric space. Comments: Q1: How can we be sure that the integral in d(f, g) exists? Q2: Would it exist if we considered C(a, b) instead of C[a, b]? A2: In C(a, b), functions are allowed to tend to infinity as x → a or x → b, and for such functions the metric can be infinite.

14 Proof (of the statement in Example 5):
Axioms (A), (C), and the “ part” of Axiom (B) obviously hold. To prove the “ part” of Axiom (B), let and observe that f(x) and g(x) can differ only at isolated points of x – which they however can’t, as they are both continuous.

15 To prove that Axioms (D) holds, consider the (obviously correct) inequality:
(4) which holds when p and q are either real numbers or real functions. Assuming the latter, let where f(x), g(x), and h(x) are certain functions. Then, (4) becomes (5)

16 Integrating (5) with respect to x over [a, b] and recalling this example’s definition of metric, we obtain which is Axiom (D) (with x, y, and z replaced with f, g, and h).

17 (a) {xn = (n + 1)/n}, (b) {xn = 1/n2}.
Quick review of limits of sequences in ℝ ۞ A sequence or real numbers {xn} (n = 1, 2, 3...) is said to converge to a limit L if Comment: Here, N depends on (is a function of) ε. Example 6: Prove that the sequence {xn = 1/n} converges to x = 0. Example 7: Find the limits of the following sequences: (a) {xn = (n + 1)/n}, (b) {xn = 1/n2}.

18 ۞ A sequence {xn} in a metric space with a metric d(x, y) is said to converge to a limit L if


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