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HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of.

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Presentation on theme: "HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of."— Presentation transcript:

1 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? g left? g made? g made? H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Start with a balanced chemical equation & associate the information from the problem. Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. p.3

2 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? g left? g made? g made? H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Race! Convert each reactant to product. That which makes less is limiting. Lesser amount is theoretical yield. Start with strategy. g moles moles moles Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. p.3

3 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? g left? g made? g made? H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Set up conversions that change each reactant to one product. I’ve chosen Pb(SO4), but you could use either one. And I’ve converted grams of reactant to grams of that product. g moles moles moles 5.00 g H2(SO4) 1 mol 1 mol Pb(SO4) g = g Pb(SO4) 98 g 1 mol H2(SO4) 1 mol 5.00 g Pb(C2H3O2)2 1 mol mol Pb(SO4) g = 4.66 g Pb(SO4) g mol Pb(C2H3O2)2 1 mol Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. p.3

4 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? 0 g g g made? H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Pb(C2H3O2) is the limiting reactant because it makes less product. No Pb(C2H3O2) is left when the reaction is over because it has all been converted to product. The conversion has also predicted the theoretical yield of Pb(SO4). g moles moles moles 5.00 g H2(SO4) 1 mol 1 mol Pb(SO4) g = g Pb(SO4) 98 g 1 mol H2(SO4) 1 mol 5.00 g Pb(C2H3O2)2 1 mol mol Pb(SO4) g = 4.66 g Pb(SO4) g mol Pb(C2H3O2)2 1 mol limiting theoretical yield Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. p.3

5 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? 0 g g g H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Now start with moles of limiting reactant and calculate moles of acetic acid made. 5.00 g H2(SO4) 1 mol 1 mol Pb(SO4) g = g Pb(SO4) 98 g 1 mol H2(SO4) 1 mol 5.00 g Pb(C2H3O2)2 1 mol mol Pb(SO4) g = 4.66 g Pb(SO4) g mol Pb(C2H3O2) 1 mol limiting theoretical yield 1.54E-2 moles Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. 1.54E-2 moles Pb(C2H3O2)2 2 moles H(C2H3O2) g = g H(C2H3O2) 1 mole Pb(C2H3O2)2 1 mole H(C2H3O2) p.3

6 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   g left? 0 g g g H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Next start with moles of limiting reactant and calculate moles of the other reactant, H2(SO4) used. 5.00 g H2(SO4) 1 mol 1 mol Pb(SO4) g = g Pb(SO4) 98 g 1 mol H2(SO4) 1 mol 5.00 g Pb(C2H3O2)2 1 mol mol Pb(SO4) g = 4.66 g Pb(SO4) g mol Pb(C2H3O2) 1 mol limiting theoretical yield 1.54E-2 moles Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. 1.54E-2 moles Pb(C2H3O2)2 2 moles H(C2H3O2) g = g H(C2H3O2) 1 mole Pb(C2H3O2)2 1 mole H(C2H3O2) 1.54E-2 moles Pb(C2H3O2)2 1 moles H2(SO4) g = g H2(SO4) 1 mole Pb(C2H3O2)2 1 mole H2(SO4) used p.3

7 HW 3, problem 24 24. Solutions of sulfuric acid and lead (II) acetate react to form solid lead (II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead (II) acetate are mixed, calculate the number of grams of each reactant and product that exist when the reaction is complete.   3.49 g 0 g g g H2(SO4) + Pb(C2H3O2)2  Pb(SO4) + 2H(C2H3O2) 5.00 g g Finally, calculate the amount of H2(SO4), the reactant present in excess, that are left when the reaction is complete. 5.00 g H2(SO4) 1 mol 1 mol Pb(SO4) g = g Pb(SO4) 98 g 1 mol H2(SO4) 1 mol 5.00 g Pb(C2H3O2)2 1 mol mol Pb(SO4) g = 4.66 g Pb(SO4) g mol Pb(C2H3O2) 1 mol limiting theoretical yield 1.54E-2 moles Well, chemistry has led to many advances that most feel have improved life, including medicine, conservation of natural resources, more materials to work with. Unfortunately, it’s not “all good”. Chemistry has caused environmental pollution, contributed to global warming, and has negative impacts on human health. Like all sciences, chemistry is only as “good” as the wisdom, care and foresight of those practicing it. 1.54E-2 moles Pb(C2H3O2)2 2 moles H(C2H3O2) g = g H(C2H3O2) 1 mole Pb(C2H3O2)2 1 mole H(C2H3O2) 1.54E-2 moles Pb(C2H3O2)2 1 moles H2(SO4) g = g H2(SO4) 1 mole Pb(C2H3O2)2 1 mole H2(SO4) used 5.00 g H2(SO4) given – 1.51 g H2(SO4) used = 3.49 g H2(SO4) leftover or remaining p.3


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