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Part two of acid/base pH calculations

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1 Part two of acid/base pH calculations
Student will : if given pH calculate the hydronium ion concentration hydroxide ion concentration molarity of a solution Ws. 19.2

2 “If given pH…find antilog” negative # = [hydronium conc.]
If pH is what is the [hydronium] or the molarity? “If given pH…find antilog” negative # = [hydronium conc.] enter [ E -8 ] “secret….hydronium concentration is the molarity for an acid” BUT::::: if they also ask for hydroxide concentration one must use the equilibrium constant for water::::::::: Equilibrium Constant for water is Kw = 1 x 10-14 Kw = [H+] [OH-] Yellow 2nd log

3 The pH of an orange is 4.0pH. What are the [H30] and [OH] in this fruit? What is its Molarity?

4 2. Lemons have a pH What are the hydronium and the hydroxide concentrations? What is its molarity?

5 What is the molarity if the pH is 12
What is the molarity if the pH is 12.9 for a Calcium hydroxide solution?

6 4. Given pH 5.5 for an acid solution. What is the molarity?

7 5. Given pH 8.8 for a base solution what is the molarity?

8 6. Given pH 6. 7, what is the molarity
6. Given pH 6.7, what is the molarity? What are the [hydronium] and the [hydroxide] ?

9 If the [H3O] for butter is 6.0 x 10-7
is it acidic, basic, or neutral?

10 8. If given the [OH] as 3.16 x 10-11, what is the hydronium concentration? What is the pH?

11 9. If given the [H3O] as 1.6 x 10-6, what is the hydroxide concentration? What is the pH?

12 Remember: 3 formulas: pH=-log[H3O]
pOH=-log[OH] pH + pOH = 14 Remember: [H3O] is hydronium concentration or…..molarity for an Acid or…..H+ proton concentration Remember: [OH] is hydroxide concentration or molarity for a base Remember: if given pH use antilog to calculate [H3O] [OH] put pH in as negative number Remember: Kw = 1x10-14 Kw = [H3O] [OH]

13 If the pH=5.2 what is the [OH]?
6.31 x 10-6 1.58x 10-9 8.8 x 10 -7

14 Part two of acid/base pH calculations
Student will : if given pH calculate the hydronium ion concentration hydroxide ion concentration molarity of a solution Ws. 19.2


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