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Chapter 15 Principles of Stereochemistry

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1 Chapter 15 Principles of Stereochemistry
Chapter 15 Principles of Stereochemistry ***Bring Your Model Kits to Class!***

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3 Stereoisomers: compounds that have the same connectivity, but a different arrangement of atoms in space Enantiomers: molecules that are non-superimposable (non-congruent) mirror images

4 Enantiomers

5 Carvone

6 Problem Draw the missing enantiomer:

7 Enantiomers are said to be “chiral”
They possess the property of “chirality” Greek: “hand” or “handedness” No plane of symmetry

8 If a molecule is superimposable on its mirror image it is said to be “achiral”
Has a plane of symmetry

9 Chiral Carbons Many chiral molecules contain one or more asymmetric carbons Called “Chiral Carbons” Attached to four different groups Denoted by an asterisk Source of stereoisomerism Interchange of groups = other stereoisomer Stereocenters

10 Problems Identify, with an asterisk, the chiral carbons in the following molecules:

11 How do we differentiate between these two enantiomers
How do we differentiate between these two enantiomers? What do we call them?

12 Nomenclature of Enantiomers
Identify your chiral carbon Prioritize your substituents on the chiral carbon according to the Cahn-Ingold-Prelog priority rules Highest priority = 1, Lowest Priority = 4 Priority assignment rules: Higher atomic # = higher priority Higher isotopic mass = higher priority

13 If the first atoms connected to the chiral carbon are the same, continue moving outward until the first point of difference

14 Multiple-bonded atoms are equivalent to the same number of single bonded atoms

15 Point the lowest priority substituent away from you and look at the 3 remaining groups in a plane
Count  1, 2, 3 If you go CW = R (rectus, Latin “proper”) If you go CCW = S (sinister, Latin “left”)

16 Name your enantiomers by placing an “(R)-” or an “(S)-” in front of the molecule’s IUPAC name

17 Problems Identify whether the following molecules are R or S.
Identify and name the following molecules:

18 For pharmaceuticals, slight differences in 3D spatial arrangement can make the difference between targeted treatment and undesired side effects. WHY?

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21 Physical Properties of Enantiomers
Enantiomers share identical physical properties m.p., b.p., nD, density, heats of formation etc. Example: Lactic Acid m.p. = 53°C b.p. = 122°C Lactic Acid

22 Enantiomers rotate a plane of polarized light in equal, but opposite directions
Called “Optical Activity” Use Polarimeter

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24 Optical Activity If the sample rotates the plane of polarized light CW → dextrorotatory (+) Latin: Dexter = Right If the sample rotates the plane of polarized light CCW → levorotatory (-) Latin = Laevus = Left If one enantiomer is +, the other will be – (+)-lactic acid (–)-lactic acid

25 The sign of optical rotation is unrelated to R and S configuration of a compound
(S)-(+)-lactic acid (R)-(–)-lactic acid

26 Optical rotation (a) is a quantitative measure of optical activity
[a] = a/cl [a] = specific rotation a = Observed rotation (degrees) c = concentration (g/mL) l = path length (dm) Often, temp and wavelength indicated

27 (S)-(-)-glyceraldehyde [α]20 = -13.5° mL g-1 dm-1
(R)-(+)-glyceraldehyde [α]20 = +13.5° mL g-1 dm-1

28 Racemic Mixtures Racemic mixture/Racemate: a mixture containing equal amounts of two enantiomers typically have different physical properties from that of the pure enantiomers Example: Lactic Acid m.p. (R or S) = 53°C m.p. (R and S)= 17°C Indicating racemic mixture: Racemic Lactic Acid (±)-Lactic Acid Optical rotation = 0

29 Celexa vs. Lexapro Celexa = racemic mixture Lexapro = enantiopure S
R-(−)-citalopram S-(+)-citalopram Celexa = racemic mixture Lexapro = enantiopure S escitalopram

30 Fischer Projections Convenient 2D representation of 3D carbohydrate molecules Carbon chain written vertically All bonds depicted horizontally and vertically Chiral carbons are represented by crossing lines

31 Vertical bonds go back Horizontal bonds come forward

32 Fischer Projections – More Complex
Based on an eclipsed molecular conformation

33 An interchange of any two of the groups bound to an asymmetric carbon changes the configuration of that carbon

34 Problems Draw the enantiomer for the following molecule. Then, draw it as a molecular representation with dashes and wedges. Which is R? Which is S? How many chirality centers does the following molecule possess? Draw L-Glucose.

35 Isomer Identification Flowchart

36 Molecules with more than one chirality center have mirror image stereoisomers that are enantiomers
In addition they can have stereoisomeric forms that are not mirror images, called diastereomers

37 Diastereomers and Enantiomers

38 Fischer Projections can also be used to quickly assess stereoisomeric relationships

39 Problem Which of the following molecules are enantiomers? Which are diastereomers?


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