1. Quiz 6/1/05 Identify the quantities from the units:
15kPa
170 K
22.3 torr
2.0 atm
If 5.0 ml of a gas at a constant temperature at 100 kPa, expands to fill 15 ml, what is the new pressure? Identify V1, V2, and P1 and P2 ( 4 pts)
Solve the previous problem using the appropriate form of the equation P1 V1 = P2 V2
pressure
temperature
Pressure
V1 = 5.0 mL
6. V2 = 15 mL
7. P1 = 100 kPa
8. P2 = ?
-1 = 89 %
-2 = 78%
-3 = 67%
-4 = 56%
-5 = 45 %
-6 = 34 %
-7 = 23%
-8 = 12 %
-9 = 0%
6. P2 = (5mL)(100kPa)
15 mL
P2 = 33 kPa

2. Charles’ Law Volume and Temperature are directly proportional. V2 T2=
A 2.0 L volume of a gas is heated from 00C to 100 oC
What is the new volume?
2.0 L = V1
0oC =T1 add 273 = 273 K
100oC = T2 add 273 = 373 K
New Volume = unknown
Solve for V2
V1T2 = V2 T1
(2.0 L)(373K)
(273K)
= 2.73 L

3. HW 21: Notes page 463 #15 page 464 and # 43,44,45,46 on page 473
Combined Gas Law:
PV is equal to some number,
T a constant.
P1V1 T1
= P2V2 T2
= P3V3
T etcetera

4. How to solve wordy problems
#14. Freon-12, dichlorodifluoromethane
(CCl2F2) was a widely used refrigerant.
Consider a
sample of gaseous
CCl2F2 at a
2.23 dm3
pressure of 4.85 kPa and a
temperature of C. Calculate the
volume of the gas at a pressure of
1.38 kPa and a temperature of 5.5oC.
Step 1: ignore the extra words!
Remember dm3 = L
V1 = 2.23 L
P1 = 485 kPa
T1 = – 1.36 = K
V2 = ?
P2 = 1.38 kPa
T2 = = K

5. V2 = ?
P2 = 1.38 kPa
T2 = = K
V1 = 2.23 L
P1 = 485 kPa
T1 = – 1.36 = K
(485 kPa)
(2.23L)
(279 K)
(1.38 kPa)
(272 K)
= 8.04 L

6. # 15. Correct the volumes of the following gases as indicated:
P2 = kPa
T2 = 273 K
V1 = 7.51 m3
P1 = 59.9 kPa
T1 = = 278 K
(59.9 kPa)
(7.51 dm3)
(273 K)
(101.3 kPa)
(278 K)
= 4.36 m3

7. # 15. Correct the volumes of the following gases as indicated:b.
V2 = ?
P2 = 94.5 kPa
T2 = = 309 K
V1 = 3.51 cm3
P1 = 82.5 kPa
T1 = = 282 K
(82.5 kPa)
(3.51 cm3)
(309 K)
(94.5 kPa)
(282 K)
= 324 cm3

8. # 43. For the following gases, correct the volumes to the conditions indicated.b.
V2 = ?
P2 = 94.5 kPa
T2 = = 309 K
V1 = 654 cm3
P1 =65.3 kPa
T1 = = 279 K
(82.5 kPa)
(654 cm3)
(309 K)
(94.5 kPa)
(279 K)
= 324 cm3

9. Updated Problem solving vocabulary
Correct the volume: figure out the new volume.
Cylinder: A container the shape of a can of soup.
Compressed: Smooshed, particles are packed tightly and at high pressure.
are held constant: The beginning and end are the same.
piston: A device used to push a gas or fluid (like in a car engine, or a syringe.
vapor pressure: pressure caused by water molecules which have evaporated.
Standard Temperature = 273 K or 0oC
occupies: fills, has a volume of…
remains: stays (the same)
indicated: listed here