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ACID BASE DISORDER DR UZMA MALIK
ASSISTANT PROFESSOR MEDICINE(EAST MEDICAL WARD) FCPS(Medicine)FCPS (Endocrinology)
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Example EXAMPLE pO2= 76 pH= 7.2 pCO2= 84 HCO3= 28.3
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SOLUTION Type 2 respiratory failure
EXAMPLE Po2= 76 pH= 7.2 pCO2= 84 HCO3= 28.3 Type 2 resp. failure Acidosis Respiratory acidosis Metabolic compensation Calculation forexpected compensation ∆HCO3=0.1 X ( 84-40) ∆HCO3=0.1 X 44 ∆HCO3=4.4 Expected HCO3=24+4.4=28.4 Type 2 respiratory failure Partially compensated acute respiratory acidosis
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Interpretation of ABGs
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Interpretation of ABGs
Respiratory failure Type 1 Type 2 Acid base disorder Acidosis Alkalosis
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NORMAL VALUES pH = 7.35 - 7.45 ( 7.4 ) pCO2 = 33 - 45 ( 40 ) mEq/L
HCO3 = ( 24 ) mEq/L pO2 = mmHg
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Interpretation of ABGs
Respiratory failure Type 1; pO2 low Type 2; pO2 low, pCO2 high
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Respiratory Alkalosis
Acid Base disorder Respiratory Acidosis Respiratory Alkalosis Metabolic Acidosis Metabolic Alkalosis
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BASIC CONCEPTS pH~ CO2 ↔ H2CO3 ↔ H+ HCO3
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Respiratory Acidosis pH~ PATHOGENESIS Retention of CO2
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Respiratory Acidosis Causes Anatomical Site Disorder
CNS depression of resp.centre trauma, barbiturate Upper airway obstruction; Acute epiglotitis croup Resp. muscles paralysis ALS, phrenic nerve injury, GBS, poliomyelitis, hypokalemia, hypophsphatemia( ATP) Lungs obstructive diseases; chronic bronchitis, cystic fibrosis other; pulmonary edema, ARDS, RDS, severe bronchial asthma
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Respiratory Acidosis COMPENSATION Metabolic alkalosis
HCO3 < 30 mEq/L in acute respiratory acidosis HCO3 > 30 mEq/L in chronic respiratory acidosis CALCULATION OF EXPECTED COMPENSATION Acute resp. acidosis ∆HCO3=0.1 X ∆pCO2 Chronic resp. acidosis ∆HCO3=0.4 X ∆pCO2
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Respiratory Acidosis EXAMPLE pH= 7.2 pCO2= 74 HCO3= 27
∆HCO3=0.1 X ( 74-40) ∆HCO3=0.1 X 34 ∆HCO3=3.4 Expected HCO3=24+3.4=27.4
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Respiratory Acidosis EXAMPLE pH= 7.34 pCO2= 60 HCO3= 32
∆HCO3=0.4 X ( 60-40) ∆HCO3=0.4 X 20 ∆HCO3=8 Expected HCO3=24+8=32
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Respiratory Alkalosis
pH~ PATHOGENESIS Elimination of CO2
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Respiratory Alkalosis
Causes Anatomical Site Disorder CNS over stimulation of resp.centre anxiety, high altitude, pregnancy, salicylate poisoning, endotoxic shock, cirrhosis Resp. muscles rib fracture; hyper ventilate from pain Lungs restrictive diseases; sarcoidosis, asbestosis, others; pulmonary embolus, mild bronchial asthma
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Respiratory Alkalosis
COMPENSATION Metabolic acidosis HCO3 > 18 mEq/L in acute respiratory alkalosis HCO3 < 18 but >12 mEq/L in chronic respiratory alkalosis CALCULATION OF EXPECTED COMPENSATION Acute resp. alkalosis ∆HCO3=0.2 X ∆pCO2 Chronic resp. alkalosis ∆HCO3=0.5 X ∆pCO2
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Respiratory Alkalosis
EXAMPLE pH= pCO2= 24 HCO3= 21 ∆HCO3=0.2 X ( 40-24) ∆HCO3=0.2 X 16 ∆HCO3=3.2 Expected HCO3=24-3.2=20.8
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Respiratory Alkalosis
EXAMPLE pH= pCO2= 18 HCO3= 13 ∆HCO3=0.5X ( 40-18) ∆HCO3=0.5 X 22 ∆HCO3=11 Expected HCO3=24-11=13
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Metabolic Acidosis pH~ PATHOGENESIS
Addition of an acid ( increased anion gap ) Loss of HCO3 or inability to synthesize HCO3( normal anion gap )
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Metabolic Acidosis COMPENSATION Resp. alkalosis
CALCULATION OF EXPECTED COMPENSATION ∆pCO2 =1.2 X ∆HCO3 +/- 2
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Metabolic Acidosis EXAMPLE pH= 7.27 pCO2= 27 HCO3= 12
∆pCO2 =1.2 X ∆ HCO3 +/- 2 ∆pCO2 =1.2 X ( 24-12) +/- 2 ∆pCO2 =1.2 X 12 +/- 2 ∆pCO2 = /- 2 Expected pCO2= 40 – 14.4= /- 2= 23.6 to 27.6
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Metabolic Acidosis INCREASED ANION GAP TYPE Formula
AG= serum Na – (serum Cl + serum HCO3 )= 12 +/- 2 Example Na = 130 ( ) Cl = 88 ( 95 – 105 ) HCO3 = ( 22 – 28 ) AG= 130 – ( 88+10) = 130 – 98= 32
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Metabolic Acidosis INCREASED ANION GAP TYPE Causes Lactic acidosis
Ketoacidosis Renal failure ( retention of organic acids) Salicylate poisoning Ethylene glycol poisoning Methyl alcohalpoisoning
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Metabolic Acidosis NORMAL ANION GAP TYPE Formula
AG= serum Na – (serum Cl + serum HCO3 )= 12 +/- 2 Example Na = 136 ( ) Cl = ( 95 – 105 ) HCO3 = 14 ( 22 – 28 ) AG= 136 – ( ) = 136 –124= 12
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Metabolic Acidosis NORMAL ANION GAP TYPE CAUSES Diarrhoea
Cholestyramine Drainage of bile or pancreatic secretions Type 1 distal renal tubular acidosis Type 11 proximal renal tubular acidosis Type IV renal tubular acidosis
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Metabolic Alkalosis pH~ PATHOGENESIS Loss of hydrogen ion Gain of HCO3
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Metabolic Alkalosis COMPENSATION Resp. acidosis
CALCULATION OF EXPECTED COMPENSATION ∆pCO2 =0.7 X ∆ HCO3 +/- 2
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Metabolic Alkalosis EXAMPLE pH= 7.58 pCO2= 49 HCO3= 39
∆pCO2 =0.7 X ∆ HCO3 +/- 2 ∆pCO2 =0.7 X ( 39-24) +/- 2 ∆pCO2 =0.7 X 15 +/- 2 ∆pCO2 =10.5 +/- 2 Expected pCO2= = /- 2= 48.5 to 52.5
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Metabolic Alkalosis CAUSES Vomiting Mineralocorticoid excess
Thiazide and loop diuretics
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Calculate expected compensation
5 easy steps Look at pO2 Look at pH Look at pCO2 Look at HCO3 Calculate expected compensation
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Type 1; pO2 low Type 2; pO2 low, pCO2 high Respiratory failure
5 easy steps Respiratory failure Type 1; pO2 low Type 2; pO2 low, pCO2 high Look for pO2
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5 easy steps 2. Look for pH pH acidosis pH alkalosis
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5 easy steps 3. Look for pCO2 pCO2 acidosis pCO2 alkalosis
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5 easy steps 4. Look for HCO3 HCO3 acidosis HCO3 alkalosis
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5 easy steps 5. Calculate for expected compensation
If compensation within expected range one primary disorder If compensation outside normal range more than one primary disorder
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uncompensated disorder
5 easy steps 5. Compensation uncompensated disorder expected compensation in normal range partially compensated disorder Expected compensation moves outside the normal range, But does not bring pH in normal range full compensation and brings pH in normal range
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Primary disorder pH pCO2 HCO3 Respiratory acidosis Respiratory alkalosis Metabolic acidosis Metabolic alkalosis
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Example EXAMPLE pO2= 76 pH= 7.2 pCO2= 84 HCO3= 28.3
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SOLUTION Type 2 respiratory failure
EXAMPLE Po2= 76 pH= 7.2 pCO2= 84 HCO3= 28.3 Type 2 resp. failure Acidosis Respiratory acidosis Metabolic compensation Calculation forexpected compensation ∆HCO3=0.1 X ( 84-40) ∆HCO3=0.1 X 44 ∆HCO3=4.4 Expected HCO3=24+4.4=28.4 Type 2 respiratory failure Partially compensated acute respiratory acidosis
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p02 THANK YOU pH~
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