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Opener – do on a sheet of paper (or GOOS Paper

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Presentation on theme: "Opener – do on a sheet of paper (or GOOS Paper"— Presentation transcript:

1 Opener – do on a sheet of paper (or GOOS Paper
Opener – do on a sheet of paper (or GOOS Paper!) and we will be correcting in 5 minutes Calculate the percent composition of phosphoric acid, H3PO4 (used to give carbonated beverages a tart taste)

2 Empirical Formulas

3 Methanal, CH2O Ethanoic acid, C2H4O2 Same % composition! 40.0% C, 6.7% H, 53.3% O

4 Very different properties
Methanal – formaldehyde and preservation of specimens

5 Ethanoic acid - vinegar

6 Therefore, the best way to identify an unknown is to identify its chemical formula.
Let’s use the previous percent composition as our next example

7 40.0% C, 6.7% H, 53.3% O We want to work with a convenient sample size, so we will use 100 g We can do this because the percentages will be the same, no matter what our sample size is.

8 So now we are looking at 40.0 g of carbon, 6.7 g hydrogen, 53.3 g oxygen

9 Next we determine the amount

10 Next we determine the amount

11 CH2O What do we notice? The ratio of carbon : oxygen is just about 1:1
The amount of hydrogen is almost double this C:H:O = 1:2:1 CH2O

12 One way to determine ratios
Divide each amount by the smallest amount. In this way the smallest amount becomes “1” and other amounts have higher values, relative to 1.

13 Empirical formula: Simplest whole number ratio of atoms or ions in a compound.

14 Molecular formula: Exact number of each type of atom in a compound.

15 Determining empirical formulas

16 example Determine the empirical formula of a compound with 35.4% Na, and the remainder is N.

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19 What about more complex compounds?

20 69.9% iron, 30.1% oxygen

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23 Ratios from fractions Whole number Multiply all subscripts by 0.25 = ¼
4 (0.25) = 1 4 0.33 = 1/3 3(0.33) = 1 3 0.50 = ½ 2(0.5) = 1 2 0.67 = 2/3 3 (0.67) = 2 0.75 = ¾ 4 (0.75) = 3

24 Last One! 3 elements: 52.2% C, 6.15% H, 41.7% O

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