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Published bySherman Hensley Modified over 6 years ago
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The Ideal Gas Law PV=nRT P = Pressure V = Volume n = Number of Moles
R = ideal gas constant T = temperature in Kelvin
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R -The ideal gas constant
Depends on unit of pressure L . Atm / K . mol 62.4 L . mmHg / K . mol (torr is mm Hg) 8.31 L . kPa / K . mol
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Ideal Gas Law example problem
Calculate the pressure of 1.65 g of helium gas at 16.0oC and occupying a volume of 3.25 L? You will need g to moles and Celsius to Kelvin: 1.65 g He 1 mole He 4.0 g He = mol He K = oC ; = 289 K For this problem you will need to pick an R value. For this problem I will choose to use the R value containing kPa. I picked it. You can’t do anything about it. So; just try and stop me. Plug and Chug baby, get ‘R done. Do it. Come on I dare ya. Get it - ‘R as in ideal gas constant
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Ideal Gas Law example problem
P x 3.25 L = mol x 8.31 kPa . L x 289 K mol . K Do the algebra and solve; if you do it right, guess what? You get the answer right. Neat concept, huh? Maybe your mommy will give you a cookie. = 305 kPa Your turn How many moles of gas are present in a sample of Argon at 58oC with a volume of 275 mL and a pressure of atm.
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Ideal Gas Law example problem
Answer 0.987 atm x L = n x L . Atm x 331K mol . K Do the dew; oops, I mean the algebra and presto; the answer with the correct number of sig figs is.. Do you know how to keep a so called chem student in suspense? Do ya? = mol Ar Congrats - you can plug and chug. Bye Bye now.
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