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Clicker Question 1 What is cos3(x) dx ? A. ¼ cos4(x) + C

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Presentation on theme: "Clicker Question 1 What is cos3(x) dx ? A. ¼ cos4(x) + C"— Presentation transcript:

1 Clicker Question 1 What is cos3(x) dx ? A. ¼ cos4(x) + C
B. -3cos2(x) sin(x) + C C. x – (1/3) sin3(x) + C D. sin(x) – (1/3) sin3(x) + C E. sin2(x) cos(x) + C

2 Clicker Question 2 What is tan4(x)sec4(x)dx ?
A. (1/25)tan5(x)sec5(x) + C B. tan7(x) + tan5(x) + C C. tan6(x) + tan4(x) + C D. (1/6) tan6(x) +(1/4) tan4(x) + C E. (1/7)tan7(x) + (1/5)tan5(x) + C

3 Trig Substitutions (9/18/13)
Motivation: What is the area of a circle of radius r ? Put such a circle of the coordinate system centered at the origin and write down an integral which would get the answer. Can you see how to evaluate this integral?

4 Replacing Algebraic With Trigonometric
An expression like (1 – x2) may be difficult to work with in an integral since the inside is a binomial. Perhaps the Pythagorean Identities from trig might help since they equate a binomial (1 – sin2()) with a monomial (cos2()). So try letting x = sin() and go from there. You must also replace dx !

5 An example What is 1 /(1 – x2)3/2 dx ? Regular substitution?
Well, try a “trig sub”. Let x = sin() , so that dx = cos() d. Now rebuild the integrand in terms of trig functions of . Can we integrate what we now have?? (Yes, think back!) Finally, we must return to x for the final answer.

6 Clicker Question 3 What is x / (1 – x2)5 dx?
A. –1 / (8( 1 – x2)4) + C B. 1 / (6( 1 – x2)6) + C C. 1 / (12( 1 – x2)6) + C D. 1 / (8( 1 – x2)4) + C E. –1 / (10( 1 – x2)5) + C

7 Back to the circle Try a trig substitution.
Since this is a definite integral, we can eliminate x once and for all and stick with  (so we must replace the endpoints also!). We’ve now proved the most famous formula in geometry.

8 Other trig substitutions
Recall that d/dx(arctan(x)) = 1/ (1 + x2) Hence 1 / (1 + x2) dx = arctan(x) + C This leads to the idea that integrands which contain expressions of the form (a2 + x2) (where a is just a constant) may be related to the tan function. Thus in the expression above we make the substitution x = a tan() (so dx = a sec2()d). What about expressions of the form (x2 – a2)?

9 Assignment for Friday Make sure you understand and appreciate the derivation of the area of a circle. Assignment: Read Section 7.3 and do Exercises 1, 3 (see Exercise 23 in Section 7.2), 4 (The answer is 2/15. Since it’s a definite integral, eliminate x completely, including endpoints), and 9. Hand-in #1 is due on Monday.


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