1. 3-9 Finding Square Roots Warm Up Problem of the Day
Lesson Presentation
Pre-Algebra

2. 3-9 Finding Square Roots Warm Up
Pre-Algebra
3-9
Finding Square Roots
Warm Up
Find the two square roots of each number.
Evaluate each expression.
±12
±16 20
119

3. Problem of the Day
A pyramid of blocks is built in layers. The bottom layer has 62, or 36, blocks. The next layer has 52 blocks, and so on until the top layer has 1 block. How many blocks are there in all?
91 blocks

4. Finding Square Roots
Learn to estimate square roots to a given number of decimal places and solve problems using square roots.

5. A museum director wants to install a skylight to illuminate an unusual piece of art. It must be square and have an area of 300 square inches, with wood trim around it. Can you calculate the trim that you need? You can do this by using your knowledge of squares and square roots.

6. Additional Example 1A: Estimating Square Roots of Numbers
Each square root is between two integers. Name the integers.
Think: What are perfect squares close to 55? A. 55
72 = 49
49 < 55
82 = 64
64 > 55
55 is between 7 and 8.
7 < < 8

7. Additional Example 1B: Estimating Square Roots of Numbers Continued
Each square root is between two integers. Name the integers.
Think: What are perfect squares close to 90? B. – 90
–92 = 81
81 < 90
–102 = 100
100 > 90 90 –
is between –9 and –10.
–9 < – < –10

8. Try This: Example 1A
Each square root is between two integers. Name the integers.
Think: What are perfect squares close to 80? A. 80
82 = 64
64 < 80
92 = 81
81 > 80
is between 8 and 9. 80
8 < < 9

9. Try This: Example 1B
Each square root is between two integers. Name the integers.
Think: What are perfect squares close to 45? B. – 45
–62 = 36
36 < 45
–72 = 49
49 > 45 45 –
is between –6 and –7.
–6 < – 45 < –7

10. Additional Example 2: Problem Solving Application
You want to sew a fringe on a square tablecloth with an area of 500 square inches. Calculate the length of each side of the tablecloth and the length of fringe you will need to the nearest tenth of an inch.
Understand the Problem
First find the length of a side. Then you can use the length of a side to find the perimeter, the length of fringe around the tablecloth.

11. Additional Example 2 Continued
Make a Plan
The length of a side, in feet, is the number that you multiply by itself to get 500. To be accurate, find this number to the nearest tenth. If you do not know a step-by-step method for finding 500, use guess and check.

12. Additional Example 2 Continued Solve
Because 500 is between 222 and 232, the square root of 500 is between 22 and 23.
Square root is between 22 and 22.5
Too high
22.52 =
Guess 22.5 1
Square root is between 22.2 and 22.5
Too low
22.22 =
Guess 22.2 2
Square root is between 22.3 and 22.4
Too low
22.32 =
Guess 22.3 4
Square root is between 22.2 and 22.4
Too high
22.42 =
Guess 22.4 3
22.0
22.2
22.4
22.6
The square root is between 22.3 and 22.4.

13. Additional Example 2 Continued
Solve
The square root is between 22.3 and To round to the nearest tenth, look at the next decimal place.
Consider =
Too low
The square root must be greater than 22.35, so round up.
To the nearest tenth, is about 22.4.
The length of each side of the table is about 22.4 in.

14. Additional Example 2 Continued
Solve
The length of a side of the tablecloth is 22.4 inches, to the nearest tenth of an inch. Now estimate the length around the tablecloth.
4 • 22.4 = 89.6
Perimeter 4 • side
You will need about 89.6 inches of fringe.

15. Additional Example 2 Continued
Look Back
The length 90 inches divided by 4 is 22.5 inches. A 22.5-inch square has an area of square inches, which is close to 500, so the answers are reasonable.

16. Try This: Example 2
You want to build a fence around a square garden that is 250 square feet. Calculate the length of one side of the garden and the total length of the fence, to the nearest tenth.
Understand the Problem
First find the length of a side. Then you can use the length of a side to find the perimeter, the length of the fence.

17. Try This: Example 2 Continued
Make a Plan
The length of a side, in feet, is the number that you multiply by itself to get 250. To be accurate, find this number to the nearest tenth. If you do not know a step-by-step method for finding 250, use guess and check.

18. Try This: Example 2 Continued Solve
Because 250 is between 152 and 162, the square root of 250 is between 15 and 16.
Guess 15.5
15.52 =
Too Low
Square root is between 15.5 and 16
Guess 15.9
15.92 =
Too high
Square root is between 15.5 and 15.9
Guess 15.7
15.72 =
Too Low
Square root is between 15.7 and 15.9
Guess 15.8
15.82 =
Too Low
Square root is between 15.8 and 15.9 1 3 4 2
15.5
15.7
15.9
16.1
The square root is between 15.8 and 15.9.

19. Try This: Example 2 Continued
Solve
To round to the nearest tenth, look at the next decimal place.
Consider =
The square root is lower than 15.85, so round down.
To the nearest tenth, is about 15.8.
The length of each side of the garden is about 15.8 ft.

20. Try This: Example 2 Continued
Solve
The length of a side of the garden is 15.8 feet, to the nearest tenth of a foot. Now estimate the length around the garden.
4 • 15.8 = 63.2
Perimeter 4 • side
You will need about 63.2 feet of fence.

21. Try This: Example 2 Continued
Look Back
The length 63.2 feet divided by 4 is 15.8 feet. A 15.8 foot square has an area of square feet, which is close to 250, so the answers are reasonable.

22. Use a calculator to find 500. Round to the nearest tenth.
Additional Examples 3: Using a Calculator to Estimate the Value of a Square Root
Use a calculator to find Round to the nearest tenth.
Using a calculator, ≈ ….
Rounded, is 22.4.

23. Use a calculator to find 200. Round to the nearest tenth.
Try This: Example 3
Use a calculator to find Round to the nearest tenth.
Using a calculator, ≈ ….
Rounded, is 14.1.

24. Lesson Quiz
Each square root is between two integers. Name the two integers.
– 456
5 and 6
–22 and –21
Use a calculator to find each value. Round to the nearest tenth.
9.4
35.0
5. A square field has an area of 2000 square feet. To the nearest foot, how much fencing would be needed to enclose the field?
179 ft