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2 DIMENSIONAL KINEMATICS
MIT C.P. PHYSICS 2 DIMENSIONAL KINEMATICS
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Zero Angle Projectile Motion
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Zero Angle Projectile Motion
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Zero Angle Projectile Motion
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Zero Angle Projectile Motion
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Zero Angle Projectile Motion
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Zero Angle Projectile Motion
Which Ball Will Hit The Ground First?
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Zero Angle Projectile Motion
Neither!!!!
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Lab: Zero Angle Trajectory
Interactive
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Lab: Zero Angle Trajectory
Data Chart 1 Trial # Height (m) Angle (°) Speed (m/s) Range (m) Time (s) 1 25 15 2 50 3 75 4 100
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Lab: Zero Angle Trajectory
Data Chart 2 Trial # Height (m) Angle (°) Speed (m/s) Range (m) Time (s) 1 100 30 2 40 3 50 4 60
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Formulas Time Range Height Velocity h = 1/2gt^2 v = d/t t = √2h/g
d = vt v = gt t = d/v
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Sample Problem 1 A student rolls a ball with a velocity of 35 m/s off a flat table 1.6 m above the floor. How long does it take to hit the ground? How far does the ball land away from the table? t = √2h/g Step 1 t = √2(1.6)/9.81 Step 2 t = 0.57 s Step 3
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Sample Problem 1 A student rolls a ball with a velocity of 35 m/s off a flat table 1.6 m above the floor. How long does it take to hit the ground? How far does the ball land away from the table? Step 1 d = vt Step 2 d = (35)(0.57) Step 3 d = 20. m
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How long does it take to hit the ground? How high is the building?
Sample Problem 2 A student rolls a ball with a velocity of 20.0 m/s off a roof. It lands 82.0 m away from the building. How long does it take to hit the ground? How high is the building? t = d/v Step 1 t = 82/20.0 Step 2 t = 4.10 s Step 3
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How long does it take to hit the ground? How high is the building?
Sample Problem 2 A student rolls a ball with a velocity of 20.0 m/s off a roof. It lands 82.0 m away from the building. How long does it take to hit the ground? How high is the building? Step 1 h = ½ gt^2 Step 2 h = ½(9.81)(4.10)^2 Step 3 h = 82.5 m
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Problem Two cannons, each at a different height, aim directly at each other. What will happen if both cannons fire at the same time at each other?
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Answer
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Launch Angle Trajectory
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Launch Angle Trajectory Demo
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Velocity & Launch Angle
Range & Time & Height Velocity & Launch Angle
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Lab: Validating Projectile Formulas
Interactive
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Lab: Validating Projectile Formulas
Data Chart 1 Trial # Velocity (m/s) Angle (°) Height (m) Range (m) 1 6 70 2 10 3 14 4 18 5 21
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Lab: Validating Projectile Formulas
Data Chart 2 Trial # Velocity (m/s) Angle (°) Height (m) Range (m) 1 15 10 2 20 3 30 4 40 5 50 6 60 7 70 8 80
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Formulas Range d = v^2 sin2Θ/g
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Which launch angle (30°,45°,60°)will give you the maximum range?
Sample Range Problem Which launch angle (30°,45°,60°)will give you the maximum range? Step 1: d = v^2 sin2Θ/g Step 2: d = 1^2 sin2(30°) (9.81) d = 1^2 sin2(45°) (9.81) d = 1^2 sin2(60°) (9.81)
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Which launch angle (30°,45°,60°)will give you the maximum range?
Sample Range Problem Which launch angle (30°,45°,60°)will give you the maximum range? 0.107 m 0.159 m 0.107 m Home Run
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Formulas Range Height d = v^2 sin2Θ/g h = v^2 sinΘ/2g
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Sample Height Problem A ball is kicked up into the air at 35.0°. Its initial velocity was 25.0m/s. How high will the ball travel? Step 1: h = v^2(sinΘ)/2g Step 2: h = (25.0)^2(sin35.0°) 2(9.81) Step 3: 18.2m
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Formulas Range Height Time d = v^2 sin2Θ/g h = v^2 sinΘ/2g
T = 2v sinΘ/g
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Lab: Determine the Velocity of a Marble Launcher
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Lab: Determine the Velocity of a Marble Launcher
Data Chart Trial # Angle (°) Distance (m) 1 2 3 4 5
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Formulas Velocity Velocity Velocity v = √dg/sin2Θ v = √h2(g)/sinΘ
v = Tg/sin2Θ
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Sample Velocity Problem
A ball is kicked up into the air at 35.0°. It lands 8.01 meters away. What was its initial velocity? Step 1: v = √dg/sin2Θ Step 2: v = √(8.01)(9.81) sin2(35°) Step 3: 9.14 m/s
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Lab: Delude Challenge
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Test Review Game Added Points Score(Single) Score(Double) 1 3000 1500
2 3500 1750 3 4000 2000 4 4500 2250 5 5000 2500 6 5500 2750 7 6000 8 6500 3250 9 7000 10 7500 3750
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Lab: Determine the Velocity of a Potato Launcher
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