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November 2010 Paper 3
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1)a) Milk : Dark 2 : 1 24 : 12 There are 36 chocolates in total
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2) a) p x p x p x p = p4 b) 2c x 3d = 6cd
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3)a) b) (2, 9) (4, 7) (6, 5) (8, 3) c) P(less than 6) = 3/20 + 2 4 6 8 1 3 5 7 9 11 13 15 17
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4)a) 4n – 2 b) 10 – n2 i) 3rd term = 10 – 32 = 1 ii) 5th term = 10 – 52 = -15
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5) Area of circle = π x radius2
Area = π x 102 = 314cm2
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6) 236 x 4.85 (1 mark for any x 5 one of these) 4000 1000 4 (1 mark for any answer between and 4)
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175 x 37 = 6475 £64.75
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Line drawn through (−2, 6) (−1, 5) (0, 4) (1, 3) (2, 2) (3, 1) (4, 0), (5, − 1)
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Equilateral triangle so all angles are 60°
x = 120° Angles on a straight line add up to 180 °
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10)a) Key 9|1 = 91 b) Mode = 77 6 9 7 2 4 8 1 3
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11) 17.5% of 6000 = 1050 (1 mark) (1 mark) = (1 mark) 7050 – (1 mark) 4050 ÷ (1 mark) = (1 mark)
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12) Rotation (1 mark) 180° (1 mark) Centre (0,0) (1 mark)
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12)b)
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13) t = v + 2 5 t – 2 = v (t – 2) x 5 = v 5(t – 2) = v
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14) Midpoint of PQ is (7, 5)
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15) B and E
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16) a) 3(x + 5) + 2(5x – 6) = 3x x – 12 = 13x + 3 b) 2x + 4 = x + 2 2 c) 5x + 10 = 5(x + 2) d) x2y + xy2 = xy(x + y)
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17) A B
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18)a) 2 17/20 – 1 2/5 17 _ 2 or 17 _ 8 9 20 Answer = 19/20 or 29/20 57 _ 7 57 _ 28 29 20
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18)b) 2 2/3 x 1 3/4 8 x 7 3 4 56 12 (or equivalent...e.g. 14/3 or 42/3
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19)a) DC = 12cm A 10cm 10cm x 1.5 or ÷ 2 then x 3 E B 8cm 8cm 5cm D C
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19)b) Area of trapezium = ½ (a + b) x height Area of trapezium
10cm Parallel sides E B 8cm 5cm D C Area of trapezium = ½ (8 + 12) x 5 = 50cm2 8cm 5cm 12cm
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20) a) 13.2 13.8 – 12.6 = 1.2 IQR ignores extreme values/outliers
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21) 6x + 2y = − 3 (1) 4x − 3y = (2) Make the ys the same x 3 18x + 6y = -9 x 2 8x – 6y = 22 (1 mark) Signs Same Subtract 26x = 13 (1 mark) x = ½ (1 mark) Now find y 6x + 2y = -3 3 + 2y = -3 2y = -6 y = -3 (1 mark)
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22) a) A tangent is at right angles to a radius
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22) b) OB2 = OA2 + AB2 OB2 = OB2 = 100 OB = 10 BC = OB – 6 = 4cm
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23) (x − 3)(x + 5) x2 – 3x + 5x – 15 x2 + 2x – 15 x2 + 8x − 9 = 0 (x + 9)(x – 1) = 0 either x + 9 = 0 or x – 1 = 0 x = x = 1
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24)a)
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24)b) = 25
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25) x 50 = 9 1000
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26) P is inversely proportional to V.
When V = 8, P = 5 P = k V 5 = k 8 k = 40 P = 40
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26)b) P = 40 V P = 40 2 P = 20
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27)a) OP = a + b OM = ½a + ½b
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27)b) TM = -a + ½a + ½b TM = -½a + ½b
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28) (-1.6,2.6) (2.6,-1.6)
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Grade Boundaries A* (85) A (68) B (51) C (34) D (21) E (14)
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