Download presentation
Presentation is loading. Please wait.
1
Reaction Acidity Synthesis
Alkynes Reaction Acidity Synthesis
2
s-Complex of Acetylene
p-Bonds
3
Hydrocarbon Comparison
4
Alkyne Nomenclature
5
Enes with Ynes
6
Endiyne Antitumor Agents
12
Catalytic Hydrogenation
13
Lindlar’s Catalyst
14
H2 on a Poisoned Catalyst Prevents Over-Reduction cis Alkenes
15
Dissolved Lithium in NH3 trans Alkenes
16
Addition of HX
17
Br2 Addition
18
Oxymercuration Hydration Markovnikov
19
Enol – Keto Tautomerization Intermolecular
20
Oxymercuration Mechanism
21
Hydroboration Hydration Anti-Markovnikov
22
Hydroboration Mechanism
23
Draw the Products
25
Ozonolysis
26
Acidity of Terminal Alkynes
27
Acetylide Formation
28
Alkylation of Acetylide Ions Homologations using SN2 rxn
29
Multi-step Syntheses
30
Retrosynthetic Analysis Begin with the Product
31
Fill in the Reagents
32
How Many Steps?
33
5 Steps
34
An unknown compound (A) has a formula of C11H14
An unknown compound (A) has a formula of C11H14. Treatment of A with H2/Pd-carbon gives B (C11H20). Treatment of A with H2 on a Lindlar catalyst gives C (C11H16). Ozonolysis of C followed by workup with Zn, HOAc affords formaldehyde and the tricarbonyl compound shown below.
35
Schematic of the Problem
36
An initial approach to this problem is to determine the number of degrees of unsaturation in each of the molecules A, B, and C. When A (C11H14, 5o unsat.) is hydrogrenated, B (C11H20, 2o unsat.) is formed. That means that 3 p bonds reacted (3 mol. equivalents) to form B. When A is treated with H2 over a Lindlar (poisoned) catalyst, 1 mol equiv. of H2 reacts. Since this reaction is specific for the reduction of alkynes to alkenes, 2 of the 3 p bonds in A are in the form of a triple bond. The remaining p bond must be an alkene. We have accounted for three of the five degrees of unsaturation in A, therefore the other two must be rings since they do not react with H2.
37
Propose Structures for A, B, and C
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.