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Math 160 Notes Packet #23 Vectors. Math 160 Notes Packet #23 Vectors.

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Presentation on theme: "Math 160 Notes Packet #23 Vectors. Math 160 Notes Packet #23 Vectors."β€” Presentation transcript:

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2 Math 160 Notes Packet #23 Vectors

3 Suppose a car is heading NE (northeast) at 60 mph
Suppose a car is heading NE (northeast) at 60 mph. We can use a vector to help draw a picture (see right).

4 Suppose a car is heading NE (northeast) at 60 mph
Suppose a car is heading NE (northeast) at 60 mph. We can use a vector to help draw a picture (see right). 𝒗

5 A vector consists of two parts:
1. a magnitude (ex: 60 mph) a direction (ex: NE) By contrast, a scalar only has a magnitude (ex: 60 mph).

6 A vector consists of two parts:
1. a magnitude (ex: 60 mph) a direction (ex: NE) By contrast, a scalar only has a magnitude (ex: 60 mph).

7 Examples of vectors include: displacement, velocity, acceleration, and force. Examples of scalars include: distance, speed, time, and volume.

8 Examples of vectors include: displacement, velocity, acceleration, and force. Examples of scalars include: distance, speed, time, and volume.

9 A vector has an initial point and a terminal point
A vector has an initial point and a terminal point. The magnitude is the length of the vector. 𝑨𝑩

10 A vector has an initial point and a terminal point
A vector has an initial point and a terminal point. The magnitude is the length of the vector. 𝑨𝑩

11 Two vectors are equal if they have the same magnitude and direction
Two vectors are equal if they have the same magnitude and direction. So, all of the vectors to the right are equal.

12 To add two vectors visually, put them tip to tail and make a triangle.

13 Or put them tail to tail and make a parallelogram.

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15 You can stretch and shrink vectors by multiplying by a scalar
You can stretch and shrink vectors by multiplying by a scalar. Negative values make the vector go in the opposite direction.

16 In a two-dimensional coordinate system, we can represent vectors using two components: an π‘₯-component (horizontal component) and a 𝑦-component (vertical component). Here’s the notation: 𝑣 = π‘Ž,𝑏

17 If vector 𝑣 has initial point 3, βˆ’1 and terminal point 1, 2 , then 𝑣 = 1βˆ’3, 2βˆ’ βˆ’1 =βŒ©βˆ’2, 3βŒͺ.

18 If vector 𝑣 has initial point 3, βˆ’1 and terminal point 1, 2 , then 𝑣 = 1βˆ’3, 2βˆ’ βˆ’1 =βŒ©βˆ’2, 3βŒͺ.

19 If vector 𝑣 has initial point 3, βˆ’1 and terminal point 1, 2 , then 𝑣 = 1βˆ’3, 2βˆ’ βˆ’1 =βŒ©βˆ’2, 3βŒͺ.

20 The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐
The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐 . ex: The magnitude of 𝑒 = 2,βˆ’3 is 𝑒 = 2,βˆ’3 = βˆ’3 2 = 13 .

21 The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐
The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐 . ex: The magnitude of 𝑒 = 2,βˆ’3 is 𝑒 = 2,βˆ’3 = βˆ’3 2 = 13 .

22 The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐
The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐 . ex: The magnitude of 𝑒 = 2,βˆ’3 is 𝑒 = 2,βˆ’3 = βˆ’3 2 = 13 .

23 The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐
The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐 . ex: The magnitude of 𝑒 = 2,βˆ’3 is 𝑒 = 2,βˆ’3 = βˆ’3 2 = 13 .

24 The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐
The magnitude (or length) of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is 𝒗 = 𝒂 𝟐 + 𝒃 𝟐 . ex: The magnitude of 𝑒 = 2,βˆ’3 is 𝑒 = 2,βˆ’3 = βˆ’3 2 = 13 .

25 The direction of a vector 𝑣 =βŒ©π‘Ž,𝑏βŒͺ is πœƒ (in the quadrant that 𝑣 points) where 𝐭𝐚𝐧 𝜽 = 𝒃 𝒂 . Ex 1. Find the direction (in degrees) of 𝑒 =βŒ©βˆ’ 3 , 1βŒͺ.

26 To add/subtract vectors, you just add/subtract their components.
ex: 3,βˆ’1 + βˆ’4,7 = 3+ βˆ’4 ,βˆ’1+7 =βŒ©βˆ’1, 6βŒͺ

27 To multiply a vector by a scalar, you just β€œdistribute” the scalar to each component. ex: βˆ’3 2, 5 =βŒ©βˆ’6,βˆ’15βŒͺ

28 Ex 2. If 𝑒 = 2,βˆ’3 and 𝑣 = βˆ’1,2 , find 2 𝑒 βˆ’3 𝑣 .

29 0 =〈0,0βŒͺ is called the zero vector.

30 Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: 𝑀 = 3 5 , 4 5 is a unit vector since 𝑀 = =1

31 Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: 𝑀 = 3 5 , 4 5 is a unit vector since 𝑀 = =1 unit vectors

32 Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: 𝑀 = 3 5 , 4 5 is a unit vector since 𝑀 = =1 unit vectors

33 Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: 𝑀 = 3 5 , 4 5 is a unit vector since 𝑀 = =1 unit vectors

34 Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: 𝑀 = 3 5 , 4 5 is a unit vector since 𝑀 = =1 unit vectors

35 You can get a unit vector in the direction of any vector 𝑣 by dividing by 𝑣 . ex: A unit vector in the direction of βˆ’2, 5 would be βˆ’2, 5 βˆ’2, 5 = βˆ’2, 5 βˆ’ = βˆ’2, 5 29 = βˆ’ 2 29 , 5 29

36 You can get a unit vector in the direction of any vector 𝑣 by dividing by 𝑣 . ex: A unit vector in the direction of βˆ’2, 5 would be βˆ’2, 5 βˆ’2, 5 = βˆ’2, 5 βˆ’ = βˆ’2, 5 29 = βˆ’ 2 29 , 5 29

37 You can get a unit vector in the direction of any vector 𝑣 by dividing by 𝑣 . ex: A unit vector in the direction of βˆ’2, 5 would be βˆ’2, 5 βˆ’2, 5 = βˆ’2, 5 βˆ’ = βˆ’2, 5 29 = βˆ’ 2 29 , 5 29

38 You can get a unit vector in the direction of any vector 𝑣 by dividing by 𝑣 . ex: A unit vector in the direction of βˆ’2, 5 would be βˆ’2, 5 βˆ’2, 5 = βˆ’2, 5 βˆ’ = βˆ’2, 5 29 = βˆ’ 2 29 , 5 29

39 You can get a unit vector in the direction of any vector 𝑣 by dividing by 𝑣 . ex: A unit vector in the direction of βˆ’2, 5 would be βˆ’2, 5 βˆ’2, 5 = βˆ’2, 5 βˆ’ = βˆ’2, 5 29 = βˆ’ 2 29 , 5 29

40 Two special unit vectors are given their own letters: π’Š =〈𝟏,𝟎βŒͺ and 𝒋 =〈𝟎,𝟏βŒͺ We can represent any vector in terms of 𝑖 and 𝑗 : 𝑣 = π‘Ž,𝑏 =π‘Ž 𝑖 +𝑏 𝑗 ex: 5,βˆ’8 =5 𝑖 βˆ’8 𝑗

41 Two special unit vectors are given their own letters: π’Š =〈𝟏,𝟎βŒͺ and 𝒋 =〈𝟎,𝟏βŒͺ We can represent any vector in terms of 𝑖 and 𝑗 : 𝑣 = π‘Ž,𝑏 =π‘Ž 𝑖 +𝑏 𝑗 ex: 5,βˆ’8 =5 𝑖 βˆ’8 𝑗

42 Two special unit vectors are given their own letters: π’Š =〈𝟏,𝟎βŒͺ and 𝒋 =〈𝟎,𝟏βŒͺ We can represent any vector in terms of 𝑖 and 𝑗 : 𝑣 = π‘Ž,𝑏 =π‘Ž 𝑖 +𝑏 𝑗 ex: 5,βˆ’8 =5 𝑖 βˆ’8 𝑗

43 Ex 3. If 𝑒 =3 𝑖 +2 𝑗 and 𝑣 =βˆ’ 𝑖 +6 𝑗 , write 2 𝑒 +5 𝑣 in terms of 𝑖 and 𝑗 .

44 It is often useful to break a vector into its horizontal and vertical components.

45 Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction 𝑁 30 ∘ 𝐸. Express the velocity 𝑣 of the airplane relative to the air, and the velocity 𝑒 of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplane’s movement relative to the ground.

46 Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction 𝑁 30 ∘ 𝐸. Express the velocity 𝑣 of the airplane relative to the air, and the velocity 𝑒 of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplane’s movement relative to the ground.

47 Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction 𝑁 30 ∘ 𝐸. Express the velocity 𝑣 of the airplane relative to the air, and the velocity 𝑒 of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplane’s movement relative to the ground.

48 Ex 5. A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the speed of the boat (relative to the water) is 10 mi/h and the river is flowing east at the rate of 5 mi/h, in what direction should she head the boat in order to arrive at the desired landing point?

49 Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)

50 Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)

51 Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)

52 Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)


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