Download presentation
Presentation is loading. Please wait.
Published byDerek Taylor Modified over 6 years ago
2
Math 160 Notes Packet #23 Vectors
3
Suppose a car is heading NE (northeast) at 60 mph
Suppose a car is heading NE (northeast) at 60 mph. We can use a vector to help draw a picture (see right).
4
Suppose a car is heading NE (northeast) at 60 mph
Suppose a car is heading NE (northeast) at 60 mph. We can use a vector to help draw a picture (see right). π
5
A vector consists of two parts:
1. a magnitude (ex: 60 mph) a direction (ex: NE) By contrast, a scalar only has a magnitude (ex: 60 mph).
6
A vector consists of two parts:
1. a magnitude (ex: 60 mph) a direction (ex: NE) By contrast, a scalar only has a magnitude (ex: 60 mph).
7
Examples of vectors include: displacement, velocity, acceleration, and force. Examples of scalars include: distance, speed, time, and volume.
8
Examples of vectors include: displacement, velocity, acceleration, and force. Examples of scalars include: distance, speed, time, and volume.
9
A vector has an initial point and a terminal point
A vector has an initial point and a terminal point. The magnitude is the length of the vector. π¨π©
10
A vector has an initial point and a terminal point
A vector has an initial point and a terminal point. The magnitude is the length of the vector. π¨π©
11
Two vectors are equal if they have the same magnitude and direction
Two vectors are equal if they have the same magnitude and direction. So, all of the vectors to the right are equal.
12
To add two vectors visually, put them tip to tail and make a triangle.
13
Or put them tail to tail and make a parallelogram.
15
You can stretch and shrink vectors by multiplying by a scalar
You can stretch and shrink vectors by multiplying by a scalar. Negative values make the vector go in the opposite direction.
16
In a two-dimensional coordinate system, we can represent vectors using two components: an π₯-component (horizontal component) and a π¦-component (vertical component). Hereβs the notation: π£ = π,π
17
If vector π£ has initial point 3, β1 and terminal point 1, 2 , then π£ = 1β3, 2β β1 =β©β2, 3βͺ.
18
If vector π£ has initial point 3, β1 and terminal point 1, 2 , then π£ = 1β3, 2β β1 =β©β2, 3βͺ.
19
If vector π£ has initial point 3, β1 and terminal point 1, 2 , then π£ = 1β3, 2β β1 =β©β2, 3βͺ.
20
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π . ex: The magnitude of π’ = 2,β3 is π’ = 2,β3 = β3 2 = 13 .
21
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π . ex: The magnitude of π’ = 2,β3 is π’ = 2,β3 = β3 2 = 13 .
22
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π . ex: The magnitude of π’ = 2,β3 is π’ = 2,β3 = β3 2 = 13 .
23
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π . ex: The magnitude of π’ = 2,β3 is π’ = 2,β3 = β3 2 = 13 .
24
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π
The magnitude (or length) of a vector π£ =β©π,πβͺ is π = π π + π π . ex: The magnitude of π’ = 2,β3 is π’ = 2,β3 = β3 2 = 13 .
25
The direction of a vector π£ =β©π,πβͺ is π (in the quadrant that π£ points) where πππ§ π½ = π π . Ex 1. Find the direction (in degrees) of π’ =β©β 3 , 1βͺ.
26
To add/subtract vectors, you just add/subtract their components.
ex: 3,β1 + β4,7 = 3+ β4 ,β1+7 =β©β1, 6βͺ
27
To multiply a vector by a scalar, you just βdistributeβ the scalar to each component. ex: β3 2, 5 =β©β6,β15βͺ
28
Ex 2. If π’ = 2,β3 and π£ = β1,2 , find 2 π’ β3 π£ .
29
0 =β©0,0βͺ is called the zero vector.
30
Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: π€ = 3 5 , 4 5 is a unit vector since π€ = =1
31
Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: π€ = 3 5 , 4 5 is a unit vector since π€ = =1 unit vectors
32
Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: π€ = 3 5 , 4 5 is a unit vector since π€ = =1 unit vectors
33
Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: π€ = 3 5 , 4 5 is a unit vector since π€ = =1 unit vectors
34
Vectors with length 1 are called ____________
Vectors with length 1 are called ____________. ex: π€ = 3 5 , 4 5 is a unit vector since π€ = =1 unit vectors
35
You can get a unit vector in the direction of any vector π£ by dividing by π£ . ex: A unit vector in the direction of β2, 5 would be β2, 5 β2, 5 = β2, 5 β = β2, 5 29 = β 2 29 , 5 29
36
You can get a unit vector in the direction of any vector π£ by dividing by π£ . ex: A unit vector in the direction of β2, 5 would be β2, 5 β2, 5 = β2, 5 β = β2, 5 29 = β 2 29 , 5 29
37
You can get a unit vector in the direction of any vector π£ by dividing by π£ . ex: A unit vector in the direction of β2, 5 would be β2, 5 β2, 5 = β2, 5 β = β2, 5 29 = β 2 29 , 5 29
38
You can get a unit vector in the direction of any vector π£ by dividing by π£ . ex: A unit vector in the direction of β2, 5 would be β2, 5 β2, 5 = β2, 5 β = β2, 5 29 = β 2 29 , 5 29
39
You can get a unit vector in the direction of any vector π£ by dividing by π£ . ex: A unit vector in the direction of β2, 5 would be β2, 5 β2, 5 = β2, 5 β = β2, 5 29 = β 2 29 , 5 29
40
Two special unit vectors are given their own letters: π =β©π,πβͺ and π =β©π,πβͺ We can represent any vector in terms of π and π : π£ = π,π =π π +π π ex: 5,β8 =5 π β8 π
41
Two special unit vectors are given their own letters: π =β©π,πβͺ and π =β©π,πβͺ We can represent any vector in terms of π and π : π£ = π,π =π π +π π ex: 5,β8 =5 π β8 π
42
Two special unit vectors are given their own letters: π =β©π,πβͺ and π =β©π,πβͺ We can represent any vector in terms of π and π : π£ = π,π =π π +π π ex: 5,β8 =5 π β8 π
43
Ex 3. If π’ =3 π +2 π and π£ =β π +6 π , write 2 π’ +5 π£ in terms of π and π .
44
It is often useful to break a vector into its horizontal and vertical components.
45
Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction π 30 β πΈ. Express the velocity π£ of the airplane relative to the air, and the velocity π’ of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplaneβs movement relative to the ground.
46
Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction π 30 β πΈ. Express the velocity π£ of the airplane relative to the air, and the velocity π’ of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplaneβs movement relative to the ground.
47
Ex 4. An airplane heads due north with an airspeed of 300 mi/h (this is speed relative to the air). It experiences a 40 mi/h crosswind blowing in the direction π 30 β πΈ. Express the velocity π£ of the airplane relative to the air, and the velocity π’ of the wind, in component form. Find the velocity of the airplane relative to the ground. Find the speed and direction of the airplaneβs movement relative to the ground.
48
Ex 5. A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the speed of the boat (relative to the water) is 10 mi/h and the river is flowing east at the rate of 5 mi/h, in what direction should she head the boat in order to arrive at the desired landing point?
49
Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)
50
Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)
51
Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)
52
Ex 6. A 600-pound calculus book is suspended from two ropes
Ex 6. A 600-pound calculus book is suspended from two ropes. Find the tension in each rope. (Note: Since the book is not moving, it said to be in static equilibrium, so the sum of all forces acting on it is zero.)
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.