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TANGENT LINE/ NORMAL LINE
Aimen Abbasi and Jael Navarro
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Tangent Line (x, y)
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5 steps 1. Plug in x to your original equation 2. Derive
3. Plug in x to your derived equation 4. Plug in to point intercept form 5. Chang it to y – intercept form
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STEP 1 y = x^3 - 2x + 5 at x=2 y = (2)^3 - 2(2) + 5 y = 9
- You are given: y = x^3 - 2x at x=2 - To find y, you need plug in x to your original equation y = (2)^3 - 2(2) + 5 y = 9
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STEP 2 - Derive y = 3x^2 - 2
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STEP 3 - Plug in your x to your derived equation y = 3(2)^ = 10 SLOPE!
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STEP 4 y –y1 = m(x + x1) y –9 = 10(x + 2)
- Plug it in to Point Intercept Form y –y1 = m(x + x1) y –9 = 10(x + 2)
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STEP 5 Change it into y intercept form y= 10x - 11
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Lets try another - You are given X^2 + 2x – 3 at (1, 0 )
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Next Step 2 is - Differentiate 2X + 2 - Plug it in 2(1) + 2 = 4 SLOPE!
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Point – Slope Form y – 0 = 4 (x - 1) y = 4 x - 4 - Plug it in
- Change to standard y = mx +b y = 4 x - 4
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Graph your line y = 4 x - 4
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Lets Practice ! - Find the tangent lines of the following
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