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LINEAR ALGEBRA
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Example : Find x1 and x2 from these equation : Solution :
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General form : Where : a1, a2, a3 .. an and b are constantas
x1, x2, x3 .. xn are variables
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Linear Equation in matrix form
If we have some equations : Then, we can write :
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General form : Where : Or, we can write :
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Example : Find x1 and x2 from these equation : Solution :
Find A
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A-1 : Formula :
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Cramer’s rules Assume : Determinants :
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x1 : x2 : x3 :
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Example : Find x1 and x2 from these equation : Solution :
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x1 and x2 : Proof :
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Find x1, x2 and x3 from these equations :
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Find Determinants :
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Find x1, x2 and x3 :
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Adjoint Matrix Adjoint matrix of a square matrix is the transpose of the matrix formed by cofactors of elements of determinant |A| How to calculate adjoint : Calculate minor matrix for each element of matrix Make cofactor matrix cofactor is a sign minor, denoted by : Cij = (-1)ij . Mij Change to Transpose matrix.
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Example Find inverse for A : Calculate |A| :
=( ) – ( ) = 15 – 30 = - 15
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Make a new matrix with minor and cofactor
→ Transpose that matrix :
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Find x1, x2 and x3 from these equations :
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Matrix form : Formula :
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Determinants : Use minor cofactor :
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New matrix K : A-1 :
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Formula :
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Questions x + y + z – 6 = 0 2x – z + 1 = 0 x – y + 2z – 5 = 0
Find x1 and x2 from these equations : 2x1 + x2 – 4 = 0 x1 – 3x2 + 5 = 0 Find x, y and z from these equations : x + y + z – 6 = 0 2x – z + 1 = 0 x – y + 2z – 5 = 0
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