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States of Matter.

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Presentation on theme: "States of Matter."— Presentation transcript:

1 States of Matter

2 Heat vs. Hot Heat is a form of energy and is measured in joules or calories Hotness is measured as temperature Temperature is directly proportional to kinetic energy

3 Temperature and Kinetic Energy
Temperature is directly proportional to Kinetic Energy of the particles Kinetic Energy (energy of particle motion) = ½ mv2 where m is mass of particle and v is velocity of particle ALL PARTICLES ARE MOVING AT ALL TEMPERATURES ABOVE ABSOLUTE ZERO

4 Distribution of Energies
Individual particles’ energies vary. Temperature depends on the average kinetic energy of all the particles.

5 Phase Changes Phase changes involve a change in Potential Energy, not Kinetic Energy THERE IS NO CHANGE IN TEMPERATURE UNTIL THE ENTIRE SAMPLE HAS COMPLETED PHASE CHANGE

6 Endothermic Phase Changes
Heat must be absorbed by sample (Surroundings get cold as heat is transferred INTO system) Melting: solid to liquid Sublimation: solid to gas Vaporization: liquid to gas

7 Exothermic Phase Changes
Material releases heat to the surroundings. (Surroundings get hot as heat is transferred from the system.) Condensation: gas to liquid Deposition: gas to solid Freezing: liquid to solid

8 Forces of Attraction Strongest to Weakest
InTERmolecular 4. Hydrogen bonds Polar Compounds with H 5. Dipole-Dipole Polar with no H 6. (London) Dispersion Forces Nonpolar InTRAmolecular 1. Ionic 2. Metallic 3. Covalent The stronger the force, the more energy it takes to break it.

9 Heat and Phase Change Calculations
Freezing and Melting The energy required to melt 1 mole of a substance is called the molar heat of fusion. The energy released by freezing 1 mole of a substance is the molar heat of fusion.

10 Heat and Phase Change Calculations
Vaporizing and Condensing The energy required to convert 1 mole of a liquid substance to gas is the molar heat of vaporization. The energy released by when 1 mole of gas condenses to liquid is the molar heat of vaporization.

11 Example Problem 1 Calculate the energy required to melt 8.5 g of ice at 0° C. The molar heat of fusion for ice is 6.02 kj/mol. 8.5 g H2O x 1 mol H2O x kj = 2.8 kj g H2O mol H2O

12 Example Problem 2 Calculate the energy released when 25 g of steam at 100.°C condenses and cools to 55° C. The molar heat of vaporization is 40.6 kj/mol. Process 1: Condensation 25 g H2O x 1 mol x 40.6 kj = 57 kj released g mol Process 2: Cooling Q = mCΔt (25 g) ( 4.18 j/g°C) ( 55°-100.°C) = 4700 j released Total Energy Released = 57 kj kj = 62 kj


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