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Warm-Up Find the Molarity of the following.
If 22.4 g of NaOH is contained in 700. mL of solution If 600. mL of 6.0 M HCl is diluted to 1.5 L
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Follow along in your text Chapters 14 & 15
What are Acids & Bases? Follow along in your text Chapters 14 & 15
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Properties ACIDS BASES electrolytes electrolytes sour taste
bitter taste turn litmus red turn litmus blue react with metals to form H2 gas slippery feel vinegar, milk, soda, apples, citrus fruits ammonia, lye, antacid, baking soda ChemASAP
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HCl + H2O H3O+ + Cl– Definitions – +
Arrhenius - In aqueous solution… Acids form hydronium ions (H3O+) HCl + H2O H3O+ + Cl– H Cl O – + acid
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NH3 + H2O NH4+ + OH- Definitions – +
Arrhenius - In aqueous solution… Bases form hydroxide ions (OH-) NH3 + H2O NH4+ + OH- H N O – + base
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HCl + H2O Cl– + H3O+ Definitions acid conjugate base base
Brønsted-Lowry Acids are proton (H+) donors. Bases are proton (H+) acceptors. HCl + H2O Cl– + H3O+ acid conjugate base base conjugate acid
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Definitions H2O + HNO3 H3O+ + NO3– B A CA CB
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Amphoteric - can be an acid or a base.
Definitions NH3 + H2O NH4+ + OH- B A CA CB Amphoteric - can be an acid or a base.
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Polyprotic - an acid with more than one H+
Definitions Give the conjugate base for each of the following: HF H3PO4 H3O+ F - H2PO4- H2O Polyprotic - an acid with more than one H+
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Br - HSO4- CO32- HBr H2SO4 HCO3- Definitions
Give the conjugate acid for each of the following: Br - HSO4- CO32- HBr H2SO4 HCO3-
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Definitions Lewis Acids are electron pair acceptors.
Bases are electron pair donors. Lewis base Lewis acid
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Strength Strong Acid/Base 100% ionized in water strong electrolyte HCl
- + HCl HNO3 H2SO4 HBr HI HClO4 NaOH KOH Ca(OH)2 Ba(OH)2
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Strength Weak Acid/Base does not ionize completely weak electrolyte HF
- + HF CH3COOH H3PO4 H2CO3 HCN NH3
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Follow along in your text Chapter 15 Section2 Pages 539 -547
The pH Scale Follow along in your text Chapter 15 Section2 Pages
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H2O + H2O H3O+ + OH- Kw = [H3O+][OH-] = 1.0 10-14
Ionization of Water Hydronium Ion H2O + H2O H3O+ + OH- Kw = [H3O+][OH-] = 1.0 10-14
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Ionization of Water Find the hydroxide ion concentration of 3.0 10-2 M HCl. [H3O+][OH-] = 1.0 10-14 [3.0 10-2][OH-] = 1.0 10-14 [OH-] = 3.3 M Acidic or basic? Acidic Hint: [H3O+] > [OH-]
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pouvoir hydrogène (Fr.)
pH Scale 14 7 INCREASING ACIDITY INCREASING BASICITY NEUTRAL pH = -log[H3O+] pouvoir hydrogène (Fr.) “hydrogen power”
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pH of Common Substances
pH Scale pH of Common Substances
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pH = -log[H3O+] pOH = -log[OH-] pH + pOH = 14 [H3O+] = 10-pH
pH Scale pH = -log[H3O+] pOH = -log[OH-] pH + pOH = 14 [H3O+] = 10-pH [OH-] = 10-pOH
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pH Scale What is the pH of 0.050 M HNO3? pH = -log[H3O+]
Acidic or basic? Acidic
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pH Scale What is the molarity of HBr in a solution that has a pOH of 9.6? pH + pOH = 14 pH = 14 pH = 4.4 pH = -log[H3O+] So [H3O+] = 10-pH [H3O+] = [H3O+] = 4.0 10-5 M HBr Acidic
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ACID + BASE SALT + WATER
Neutralization Chemical reaction between an acid and a base. Products are a salt (ionic compound) and water. ACID + BASE SALT + WATER Neutralization does not mean pH = 7.
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Neutralization HC2H3O2 + NaOH NaC2H3O2 + H2O
Salts can be neutral, acidic, or basic. HCl + NaOH NaCl + H2O strong strong neutral HC2H3O2 + NaOH NaC2H3O2 + H2O weak strong basic
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Titration standard solution unknown solution Titration Analytical method in which a standard solution is used to determine the concentration of an unknown solution.
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Titration Equivalence point (endpoint)
Point at which equal amounts of H3O+ and OH- have been added. Determined by… indicator color change dramatic change in pH
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pH Indicators Indicator Type pH Range Color Changes Methyl Violet
-2 – 3 Yellow to Violet Thymol Blue 0 – 4.5 6 – 11 Red to Yellow Yellow to Blue Methyl Orange 2 – 6 Methyl Red 4 – 8 Litmus 3.5 – 9.5 Red to Blue Bromothymol Blue 4 – 8.5 Phenolphthalein Colorless to Pink Alizarin Yellow R 8 – 13 Yellow to Red
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Titration
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moles H3O+ = moles OH- MV n = MV n Titration M: Molarity V: volume
n: # of H+ ions in the acid or # of OH- ions in the base
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Titration 42.5 mL of 1.3M KOH are required to neutralize 50.0 mL of H2SO4. Find the molarity of H2SO4. H3O+ M = ? V = 50.0 mL n = 2 OH- M = 1.3M V = 42.5 mL n = 1 MV# = MV# M(50.0mL)(2) =(1.3M)(42.5mL)(1) M = 0.55M H2SO4
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