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Chapter 2-2 Acceleration.

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Presentation on theme: "Chapter 2-2 Acceleration."— Presentation transcript:

1 Chapter 2-2 Acceleration

2 Acceleration is the measure of how fast something speeds up or slows down.
a = (vf-vi)/t Si Units for acceleration is m/s2

3 Practice 2B #1. As the shuttle comes to a sudden stop, it accelerates at -4.1m/s2 as it slows from 9 m/s to 0 m/s in what time? Knowns? a = -4.1m/s2, vi = 0m/s, vf = 9m/s Unknown? Time = ? Equation? a = (vf-vi)/t Answer? -4.1 = (9 -0)/t; 9/-4.1 = 2.2 s

4 Vector versus Scalar A vector has a size and a direction
Example – 20 m/s due North A scalar has only a size - no direction Example – 20 m/s

5 Acceleration is a vector because it has size and direction.
If the final velocity is greater than the initial velocity the ∆v will be positive If the final velocity is less than the initial velocity the ∆v will be negative .

6 Graphs The slope and shape of a graph describes the object’s motion.

7

8 Accelerating Versus Decelerating
A negative acceleration doesn’t always mean the object is slowing down. It could be moving in the negative direction.

9 Constant Acceleration
Velocity increases by the exactly the same amount during each time interval. The displacement for each time interval increases by the same amount.

10 4 Kinematic Equations All the kinematic equations are related.
There is always more than one way to solve each problem. In general though, one equation is generally easier to use then others.

11 Equations - Kinematic Vf = vi +at ∆x=vi(t) + ½ a(t)2 ∆x = ½ (Vi +Vf)∆t Vf2 = Vi2 +2ax

12 Practice 2C #1. A car accelerates from rest to a speed of 23.7 km/h in 6.5 s. Find the distance the car travels. Knowns? vi = 0m/s, vf = 23.7km/h (6.58 m/s), t = 6.5 s Unknowns? Distance = ?, x= ? Equation? ∆x = ½ (Vi +Vf)∆t Answer = ? x = .5 (6.58)(6.5) =21.38 m

13 Homework Assignment Worksheet 2.2


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