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Practice. Practice Practice Practice Practice r = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 (4) 72.

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Presentation on theme: "Practice. Practice Practice Practice Practice r = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 (4) 72."— Presentation transcript:

1

2 Practice

3 Practice

4 Practice

5 Practice r = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 (4) 72

6 Practice r = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 -92 20
(4) 120 (4) 123 20 19 X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4

7 Practice r = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 -92 20
80 131 X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4

8 Practice -.90 = X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4 -92
102.37 80 131 X = 20 X2 = 120 Y = 19 Y2 = 123 XY = 72 N = 4

9 Remember this: Statistics Needed
Need to find the best place to draw the regression line on a scatter plot Need to quantify the cluster of scores around this regression line (i.e., the correlation coefficient)

10 Regression allows us to predict!
. . . . .

11 Straight Line Y = mX + b Where:
Y and X are variables representing scores m = slope of the line (constant) b = intercept of the line with the Y axis (constant)

12 Excel Example

13 That’s nice but How do you figure out the best values to use for m and b ? First lets move into the language of regression

14 Straight Line Y = mX + b Where:
Y and X are variables representing scores m = slope of the line (constant) b = intercept of the line with the Y axis (constant)

15 Regression Equation Y = a + bX Where:
Y = value predicted from a particular X value a = point at which the regression line intersects the Y axis b = slope of the regression line X = X value for which you wish to predict a Y value

16 Practice Y = -7 + 2X What is the slope and the Y-intercept?
Determine the value of Y for each X: X = 1, X = 3, X = 5, X = 10

17 Practice Y = -7 + 2X What is the slope and the Y-intercept?
Determine the value of Y for each X: X = 1, X = 3, X = 5, X = 10 Y = -5, Y = -1, Y = 3, Y = 13

18 Finding a and b Uses the least squares method Minimizes Error
Error = Y - Y  (Y - Y)2 is minimized

19 . . . . .

20 . . . . . Error = Y - Y  (Y - Y)2 is minimized Error = 1 Error = .5

21 Finding a and b Ingredients r value between the two variables
Sy and Sx Mean of Y and X

22 b = b r = correlation between X and Y SY = standard deviation of Y
SX = standard deviation of X

23 a a = Y - bX Y = mean of the Y scores b = regression coefficient computed previously X = mean of the X scores

24 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41

25 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41

26 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41
b =

27 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41
b = .88 1.50 1.41

28 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41 b = 1.5
a = Y - bX

29 Mean Y = 4.6; SY = 2.41 r = .88 Mean X = 3.0; SX = 1.41 b = 1.5
0.1 = (1.50)3.0

30 Regression Equation Y = a + bX Y = (1.5)X

31 Y = (1.5)X . . . . .

32 Y = (1.5)X X = 1; Y = 1.6 . . . . . .

33 Y = (1.5)X X = 5; Y = 7.60 . . . . . . .

34 Y = (1.5)X . . . . . . .

35

36

37 Practice

38 Mean Y = 14.50; Sy = 4.43 Mean X = 6.00; Sx= 2.16 r = -.57

39 Mean Y = 14.50; Sy = 4.43 Mean X = 6.00; Sx= 2.16 r = -.57
b =

40 Mean Y = 14.50; Sy = 4.43 Mean X = 6.00; Sx= 2.16 r = -.57
b = -.57 -1.17 2.16

41 Mean Y = 14.50; Sy = 4.43 Mean X = 6.00; Sx= 2.16 b = -1.17
a = Y - bX

42 Mean Y = 14.50; Sy = 4.43 Mean X = 6.00; Sx= 2.16 b = -1.17
21.52= (-1.17)6.0

43 Regression Equation Y = a + bX Y = (-1.17)X

44 Y = (-1.17)X . 22 20 . 18 16 . 14 . 12 10

45 Y = (-1.17)X . . 22 20 . 18 16 . 14 . 12 10

46 Y = (-1.17)X . . 22 20 . 18 16 . 14 . . 12 10

47 Y = (-1.17)X . . 22 20 . 18 16 . 14 . . 12 10


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