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Trig/Precalc Chapter 5.7 Inverse trig functions
Objectives Evaluate and graph the inverse sine function Evaluate and graph the remaining five inverse trig functions Evaluate and graph the composition of trig functions
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The basic sine function fails the horizontal line test
The basic sine function fails the horizontal line test. It is not one-to-one so we can’t find an inverse function unless we restrict the domain. Highlight the curve –π/2 < x < π/2 π 2π π/2 -π/2 y = sin(x) We switch x and y to get inverse functions So for f(x) = sin-1 x the domain is [-1, 1] and range is [-π/2, π/2] On the interval [-π/2, π/2] for sin x: the domain is [-π/2, π/2] and the range is [-1, 1] Therefore
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Graphing the Inverse Next we rotate it across the y=x line producing this curve First we draw the sin curve When we get rid of all the duplicate numbers we get this curve This gives us: Domain : [-1 , 1] Range:
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Inverse sine function y = sin-1 x or y = arcsin x
The sine function gives us ratios representing opposite over hypotenuse in all 4 quadrants. The inverse sine gives us the angle or arc length on the unit circle that has the given ratio. π/2 1 -π/2 Remember the phrase “arcsine of x is the angle or arc whose sine is x”.
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Evaluating Inverse Sine
If possible, find the exact value. arcsin(-1/2) = ____ We need to find the angle in the range [-π/2, π/2] such that sin y = -1/2 What angle has a sin of ½? _______ What quadrant would it be negative and within the range of arcsin? ____ Therefore the angle would be ______
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Evaluating Inverse Sine cont.
b. sin-1( ) = ____ We need to find the angle in the range [-π/2, π/2] such that sin y = What angle has a sin of ? _______ What quadrant would it be positive and within the range of arcsin? ____ Therefore the angle would be ______ c. sin-1(2) = _________ √ 1
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Graphs of Inverse Trigonometric Functions
The basic idea of the arc function is the same whether it is arcsin, arccos, or arctan
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Inverse Functions Domains and Ranges
y = arcsin x Domain: [-1, 1] Range: y = arccos x Domain: [ -1, 1] y = arctan x Domain: (-∞, ∞) y = Arcsin (x) y = Arccos (x) y = Arctan (x)
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Evaluating Inverse Cosine
If possible, find the exact value. arccos(√(2)/2) = ____ We need to find the angle in the range [0, π] such that cos y = √(2)/2 What angle has a cos of √(2)/2 ? _______ What quadrant would it be positive and within the range of arccos? ____ Therefore the angle would be ______ b. cos-1(-1) = __ What angle has a cos of -1 ? _______
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Warnings and Cautions! Inverse trig functions are equal to the arc trig function. Ex: sin-1 θ = arcsin θ Inverse trig functions are NOT equal to the reciprocal of the trig function. Ex: sin-1 θ ≠ 1/sin θ There are NO calculator keys for: sec-1 x, csc-1 x, or cot- 1 x And csc-1 x ≠ 1/csc x sec-1 x ≠ 1/sec x cot-1 x ≠ 1/cot x
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Evaluating Inverse functions with calculators ([E] 25 & 34)
If possible, approximate to 2 decimal places. 19. arccos(0.28) = ____ 22. arctan(15) = _____ 26. cos-1(0.26) = ____ 34. tan-1(-95/7) = ____ Use radian mode unless degrees are asked for.
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You Try! Evaluate: csc[arccos(-2/3)] (Hint: Draw a triangle)
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