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Published byLawrence Dalton Modified over 6 years ago
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Gas Densities, Partial Pressures, and Kinetic-Molecular Theory
Sections
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Objectives Apply the ideal-gas equation to real gas situations.
Interpret the kinetic-molecular theory of gases
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Gas Densities and Molar Mass
Rearrange the ideal-gas equation : n = P V RT Multiply both sides by molar mass, M nM = PM V RT Product of n/V and M = density in g/L Moles x grams = grams Liter mole liter
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Gas Densities and Molar Mass
Density is expressed: D = PM RT Density depends on pressure, molar mass, and temperature
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Gas Mixtures and Partial Pressure
Dalton’s Law of Partial Pressures: Total pressure of a mixture equals sum of the pressures that each would exert if present alone. Pt = P1 + P2 + P3 + ….
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Gas Mixtures and Partial Pressures
Thus: P1 = n1 (RT); P2 = n2 (RT); P3 = n3 (RT);… V V V And Pt = (n1 + n2 + n3 + ….) RT = nt (RT) V V
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Mole Fraction, X P1 = n1 RT/ V = n1 Pt = nt RT/ V = nt Thus…
P1 = (n1/nt)Pt = X1Pt
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Example Mole fraction of N2 in air is 0.78 (78%). If the total pressure is 760 torr, what is the partial pressure of N2?
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Homework 59-67, odd only
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Kinetic-Molecular Theory
Explains why gases behave as they do Developed over 100 year period Published in 1857 by Rudolf Clausius
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Kinetic Molecular Theory
* Theory of moving molecules You Must Know the 5 Postulates of the Kinetic Molecular Theory of Gases (page 421).
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Root-mean-square speed, u
Speed of a molecule possessing average kinetic energy Є = ½ mu2 Є is average kinetic energy m is mass of molecule Both Є and u increase as temperature increases
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Application to Gas Laws
Effect of a V increase at constant T: - Average kinetic energy does not change when T is constant. Thus rms speed is unchanged. With V increase, there are fewer collisions with container walls, and pressure decreases (Boyle’s Law).
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Application to Gas Laws
2. Effect of a T increase at constant V: - Increase T means increase of both average kinetic energy and rms speed. No change in V means there will be more collisions with walls.
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Molecular Effusion & Diffusion
u = 3RT M *Derived equation from the k-m theory **Less massive gas molecules have higher rms speed
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Effusion Escape of gas molecules through a tiny hole into an evacuated space
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Diffusion Spread of one substance throughout a space or throughout a second substance
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Graham’s Law of Effusion
Effusion rate of a gas is inversely proportional to the square root of its molar mass. Rates of effusion of two gases: * At same T and P in containers with identical pinholes
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Graham’s Law of Effusion
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Diffusion and Mean Free Path
Similar to Effusion (faster for lower mass molecules) BUT diffusion is slower than molecular speeds because of molecular collisions Mean Free Path: average distance traveled by a molecule between collisions
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Homework 69, 71, 73, 75, 76, 77, and 79
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