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Heap Sort Adam M.B..

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Presentation on theme: "Heap Sort Adam M.B.."— Presentation transcript:

1 Heap Sort Adam M.B.

2  DEFINITION

3 Heap Heap Tree Min Heap Complete Binary Tree (CBT)
Value of node <= value of its child Max Heap Value of node >= value of its child

4 Example of Heap Max Heap Min Heap k 24 4 2k 2k+1 19 15 5 8 2k 2k+1 2k
11 5 8 13 11 19 15 13 2k 4 24

5  BASIC PROCESSES

6 Processes in Heap Making of heap Heap sort

7 Making of Heap 7 3 2 14 11 5 1 2 3 4 5 6 1 14 7 2 3 Shift down from middle node (Sum of node/2) until first node 11 14 7 3 2 5 N = 6, Middle = N/2 = 6/2 = 3 4 5 6 Reorganize on third node 14 3 11 7 5 2 Reorganize on second node Reorganize on first node 14 11 5 3 7 2 1 2 3 4 5 6

8 Heap Sort 1 14 14 2 11 5 3 7 14 2 Binary tree in Max heap state.
“Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 11 5 4 5 6 3 7 2 14 14 2 11 5 3 7 14 2 1 2 3 4 5 6

9 Heap Sort 1 Binary tree in Max heap state.
“Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 14 2 2 3 11 5 4 5 6 3 7 2 14 14 2 11 5 3 7 14 2 1 2 3 4 5 6

10 Heap Sort 2 11 14 11 2 2 11 7 2 5 3 11 2 7 14 2 Reorganize heap
Middle = N/2 = 5/2 = 2 “Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 2 3 Reorganize heap on second node. 11 7 2 5 Reorganize heap on first node. 4 5 3 7 2 11 14 11 2 2 11 7 2 5 3 11 2 7 14 2 1 2 3 4 5 6

11 Heap Sort 3 7 11 14 7 2 2 3 2 7 5 3 2 7 11 2 7 14 2 Reorganize heap
Middle = N/2 = 4/2 = 2 “Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 2 3 Reorganize heap on second node. 2 3 7 5 Reorganize heap on first node. 4 3 2 7 11 14 7 2 2 3 2 7 5 3 2 7 11 2 7 14 2 1 2 3 4 5 6

12 Heap Sort 4 5 7 11 14 2 2 5 3 5 5 2 3 2 7 11 2 7 14 2 Reorganize heap
Middle = N/2 = 3/2 = 1 “Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 2 3 3 2 5 Reorganize heap on first node. 5 7 11 14 2 2 5 3 5 5 2 3 2 7 11 2 7 14 2 1 2 3 4 5 6

13 Heap Sort 5 1 2 2 3 Reorganize heap Middle = N/2 = 2/2 = 1 “Fired” root and swap with last node. Subtract number of nodes with 1. If N > 1 then reorganize heap again. Repeat step b to d until node is empty (N=0) 2 2 3 Reorganize heap on first node. 3 5 7 11 14 3 2 2 3 3 2 5 5 2 3 2 7 11 2 7 14 2 1 2 3 4 5 6

14 Heap Sort 6 1 2 Because N = 1 then reorganize isn’t happen. “Fired” root Subtract number of nodes with 1. Because N = 0 then sorting processes is finish. 2 3 5 7 11 14 2 3 3 2 5 2 5 3 2 7 11 2 7 14 2 1 2 3 4 5 6

15 m  CASE

16 Case Example Sort these name using heap sort method in descending way.
Node have 2 Case Example Sort these name using heap sort method in descending way. Num. Name 1 Rahmat 2 Didin 3 Ahmad 4 Joned 5 Syahrul 6 Riki 7 Arif 8 Susi 9 Donni 10 Asih

17 Making of CBT Complete Binary Tree Not Heap Rahmat Didin Ahmad Joned
Node have 2 Making of CBT Complete Binary Tree Rahmat Didin Ahmad Joned Syahrul Riki Arif Susi Donni Asih Not Heap Rahmat Didin Ahmad Joned Syahrul Riki Arif Susi Donni Asih 1 2 3 4 5 6 7 8 9 10

18 Heap Sort 1 Heap Ahmad Rahmat Didin Asih Arif Rahmat Ahmad Donni Joned
Node have 2 Heap Sort 1 Ahmad Rahmat Didin Asih Arif Rahmat Ahmad Donni Joned Asih Syahrul Didin Riki Rahmat Arif Susi Joned Donni Asih Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Ahmad Asih Arif Donni Didin Riki Rahmat Susi Joned Syahrul

19 Heap Sort 2 Not Heap Ahmad Syahrul Asih Arif Donni Didin Riki Rahmat
Node have 2 Heap Sort 2 Ahmad Syahrul Asih Arif Donni Didin Riki Rahmat Susi Joned Syahrul Not Heap 1 2 3 4 5 6 7 8 9 10 Ahmad Syahrul Ahmad Asih Arif Donni Didin Riki Rahmat Susi Joned Ahmad Syahrul

20 Heap Sort 3 Heap Arif Syahrul Asih Arif Syahrul Rahmat Donni Didin
Node have 2 Heap Sort 3 Arif Syahrul Asih Arif Syahrul Rahmat Donni Didin Riki Rahmat Syahrul Susi Joned Heap 1 2 3 4 5 6 7 8 9 10 Ahmad Arif Syahrul Asih Syahrul Rahmat Arif Donni Didin Riki Rahmat Syahrul Susi Joned Ahmad Syahrul

21 Heap Sort 4 Not Heap Arif Joned Asih Rahmat Donni Didin Riki Syahrul
Node have 2 Heap Sort 4 Arif Joned Asih Rahmat Donni Didin Riki Syahrul Susi Joned Not Heap 1 2 3 4 5 6 7 8 9 10 Arif Ahmad Arif Joned Asih Rahmat Donni Didin Riki Syahrul Susi Joned Arif Ahmad Syahrul

22 Heap Sort 5 Heap Asih Joned Didin Joned Asih Rahmat Donni Didin Joned
Node have 2 Heap Sort 5 Asih Joned Didin Joned Asih Rahmat Donni Didin Joned Riki Syahrul Susi Heap 1 2 3 4 5 6 7 8 9 10 Arif Ahmad Asih Joned Joned Didin Asih Rahmat Donni Didin Joned Riki Syahrul Susi Arif Joned Ahmad Syahrul

23 Heap Sort 6 Not Heap Susi Asih Didin Rahmat Donni Joned Riki Syahrul
Node have 2 Heap Sort 6 Susi Asih Didin Rahmat Donni Joned Riki Syahrul Not Heap Susi 1 2 3 4 5 6 7 8 9 10 Asih Arif Ahmad Asih Susi Didin Rahmat Donni Joned Riki Syahrul Asih Susi Joned Arif Ahmad Syahrul

24 Heap Sort 7 Heap Susi Didin Didin Susi Donni Rahmat Susi Donni Joned
Node have 2 Heap Sort 7 Susi Didin Didin Susi Donni Rahmat Susi Donni Joned Riki Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Asih Arif Ahmad Susi Didin Didin Susi Donni Rahmat Donni Susi Joned Riki Syahrul Susi Asih Arif Joned Ahmad Syahrul

25 Heap Sort 8 Not Heap Didin Syahrul Donni Rahmat Susi Joned Riki
Node have 2 Heap Sort 8 Didin Syahrul Donni Rahmat Susi Joned Riki Syahrul Not Heap 1 2 3 4 5 6 7 8 9 10 Didin Asih Arif Ahmad Syahrul Didin Donni Rahmat Susi Joned Riki Didin Syahrul Susi Asih Joned Arif Ahmad Syahrul

26 Heap Sort 9 Heap Donni Syahrul Donni Joned Syahrul Rahmat Susi Syahrul
Node have 2 Heap Sort 9 Donni Syahrul Donni Joned Syahrul Rahmat Susi Syahrul Joned Riki Heap 1 2 3 4 5 6 7 8 9 10 Didin Asih Arif Ahmad Donni Syahrul Syahrul Joned Donni Rahmat Susi Syahrul Joned Riki Didin Syahrul Asih Susi Arif Joned Ahmad Syahrul

27 Heap Sort 10 Not Heap Riki Donni Joned Rahmat Susi Syahrul Riki 1 2 3
Node have 2 Heap Sort 10 Riki Donni Joned Rahmat Susi Syahrul Riki Not Heap 1 2 3 4 5 6 7 8 9 10 Donni Didin Asih Arif Ahmad Donni Riki Joned Rahmat Susi Syahrul Donni Riki Didin Syahrul Susi Asih Joned Arif Ahmad Syahrul

28 Heap Sort 11 Heap Riki Joned Joned Riki Rahmat Susi Syahrul 1 2 3 4 5
Node have 2 Heap Sort 11 Riki Joned Joned Riki Rahmat Susi Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Donni Didin Asih Arif Ahmad Riki Joned Riki Joned Rahmat Susi Syahrul Donni Riki Didin Syahrul Susi Asih Arif Joned Ahmad Syahrul

29 Heap Sort 12 Not Heap Syahrul Joned Riki Rahmat Susi Syahrul 1 2 3 4 5
Node have 2 Heap Sort 12 Syahrul Joned Riki Rahmat Susi Syahrul Not Heap 1 2 3 4 5 6 7 8 9 10 Joned Donni Didin Asih Arif Ahmad Joned Syahrul Riki Rahmat Susi Joned Syahrul Donni Riki Didin Syahrul Asih Susi Arif Joned Ahmad Syahrul

30 Heap Sort 13 Heap Rahmat Syahrul Riki Syahrul Rahmat Susi 1 2 3 4 5 6
Node have 2 Heap Sort 13 Rahmat Syahrul Riki Syahrul Rahmat Susi Heap 1 2 3 4 5 6 7 8 9 10 Donni Donni Didin Asih Arif Ahmad Syahrul Rahmat Riki Syahrul Rahmat Susi Syahrul Joned Donni Riki Didin Syahrul Susi Asih Joned Arif Ahmad Syahrul

31 Heap Sort 14 Not Heap Rahmat Susi Riki Syahrul Susi 1 2 3 4 5 6 7 8 9
Node have 2 Heap Sort 14 Susi Rahmat Riki Syahrul Susi Not Heap 1 2 3 4 5 6 7 8 9 10 Rahmat Donni Donni Didin Asih Arif Ahmad Susi Rahmat Riki Syahrul Rahmat Susi Syahrul Joned Donni Riki Didin Syahrul Asih Susi Arif Joned Ahmad Syahrul

32 Heap Sort 15 Heap Riki Susi Riki Susi Syahrul 1 2 3 4 5 6 7 8 9 10
Node have 2 Heap Sort 15 Riki Susi Riki Susi Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Rahmat Donni Donni Didin Asih Arif Ahmad Susi Riki Susi Riki Syahrul Rahmat Susi Joned Syahrul Donni Riki Didin Syahrul Asih Susi Joned Arif Ahmad Syahrul

33 Heap Sort 17 Heap Syahrul Susi Syahrul Susi 1 2 3 4 5 6 7 8 9 10 Riki
Node have 2 Heap Sort 17 Syahrul Susi Susi Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Riki Rahmat Donni Donni Didin Asih Arif Ahmad Susi Syahrul Susi Syahrul Syahrul Rahmat Susi Joned Syahrul Donni Riki Didin Syahrul Susi Asih Joned Arif Ahmad Syahrul

34 Heap Sort 16 Not Heap Syahrul Riki Susi Syahrul 1 2 3 4 5 6 7 8 9 10
Node have 2 Heap Sort 16 Syahrul Riki Susi Syahrul Not Heap 1 2 3 4 5 6 7 8 9 10 Riki Rahmat Donni Donni Didin Asih Arif Ahmad Riki Syahrul Susi Syahrul Riki Rahmat Susi Joned Syahrul Donni Riki Didin Syahrul Susi Asih Arif Joned Ahmad Syahrul

35 Heap Sort 18 Heap Syahrul Susi Syahrul 1 2 3 4 5 6 7 8 9 10 Susi Riki
Node have 2 Heap Sort 18 Syahrul Susi Syahrul Heap 1 2 3 4 5 6 7 8 9 10 Susi Riki Rahmat Donni Donni Didin Asih Arif Ahmad Syahrul Susi Susi Syahrul Syahrul Rahmat Susi Syahrul Joned Donni Riki Didin Syahrul Asih Susi Arif Joned Ahmad Syahrul

36 Heap Sort 19 Syahrul Syahrul 1 2 3 4 5 6 7 8 9 10 Susi Riki Rahmat
Node have 2 Heap Sort 19 Syahrul Syahrul 1 2 3 4 5 6 7 8 9 10 Susi Riki Rahmat Donni Donni Didin Asih Arif Ahmad Syahrul Syahrul Susi Syahrul Rahmat Susi Syahrul Joned Donni Riki Didin Syahrul Susi Asih Joned Arif Ahmad Syahrul

37 GRACIAS THANK YOU Copyright © Adam Mukharil Bachtiar 2012
Contact Person: Adam Mukharil Bachtiar Informatics Engineering UNIKOM Jalan Dipati Ukur Nomor Bandung 40132 Blog: Copyright © Adam Mukharil Bachtiar 2012

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