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Advanced Engineering Mathematics 6th Edition, Concise Edition
by Peter V. O’Neil
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Ordinary Differential Equations
Part 1: Ordinary Differential Equations Ch1: First-Order Differential Equations Ch2: Second-Order Differential Equations Ch3: The Laplace Transform Ch4: Series Solutions
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Differential equation --- contains derivatives
e.g., or or y : function of x, x : independent variable (b) Ordinary differential equation – involves only total derivatives Partial differential equation – involves partial derivatives What is
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(c) The order of a differential equation e. g
(c) The order of a differential equation e.g., ○ The solution of a differential equation is a function y(x) of independent variable x that may be defined on e.g., i) , solution: y = sin2x for ii) , solution: y = xlnx – x for x > 0
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Ch. 1: First-Order Differential Equations
1.1. Preliminary Concepts ○ First-order differential equation: -- involves a first but no higher derivatives e.g., y:function of x x:independent variable : solution
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1.1.1. General and Particular Solutions
○ General solution: arbitrary constant Substitute into (A) Particular solutions: k = 1, ; k = 2 , k = ,
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1.1.2. Implicitly Defined Solutions
○ Explicit function: Implicit function: e.g., , ○ (Explicit solution) (Implicit solution)
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1.1.3. Integral Curves ○ Example 1.1: General solution:
-- Help to comprehend the behavior of solution ○ Example 1.1: General solution:
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1.1.4. Initial Value Problems
○ initial condition Graphically, the particular integral curve passes through point ( ) The objective is to obtain a unique solution ○ Example 1.4: , initial condition General solution: ,
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-- A set of line segments tangent to a curve
Direction Field -- A set of line segments tangent to a curve -- Give a rough outline of the shape of the curve ○ Giving , instead of solving for y, solving for
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-- A set of line segments tangent to a curve
Direction Field -- A set of line segments tangent to a curve -- Give a rough outline of the shape of the curve ○ Giving , instead of solving for y, solving for 11
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Slope: , General Solution:
○ Example 1.5: Slope: , General Solution: Figure 1.5. Direction field for y'= y² and integral curves through (0,1), (0,2), (0,3), - 1, (0, - 2), and (0, - 3).
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1.2. Separable Equations
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○ Example 1.7: , (the general solution) y = 0 is a solution, called a singular solution, it cannot be obtained from the general solution
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1.3. Linear Differential Equations -------- (A)
(1) Find integrating factor: (2) Multiply (A) by (3)
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○ Example 1.14: i) Integrating factor ii) Multiply the equation by , iii) iv) Integrate
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1.4. Exact Differential Equations
can be written as (A) If , s.t. and (implicitly define the solution) : potential function
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○ Example 1.17: Let From
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* We can start with , then as well
From Solution: * We can start with , then as well 19
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c(y) is not independent of x No potential function
* Not every is exact e.g. From c(y) is not independent of x No potential function
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Theorem 1.1: Exactness is exact iff (a) If is exact, then s.t.
(b) If , show s.t.
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Let : any point
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○ Example : 1.5. Integrating Factors If : not exact But : exact
is not exact 1.5. Integrating Factors If : not exact But : exact integrating factor
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. ○ How to find : exact, Try as , or ○ Example 1.21:
The equation is not exact
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Consider Let Try (B) Integrate
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(A) Let be the potential function The implicit solution: The explicit solution:
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○ Example 1.22: Let Find integrating factor by
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Try This cannot be solved for as a function of x (ii) Likewise, let
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(iii) Try (B) Divide by
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: independent Multiply (A) by Let Form
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From Obtain the potential function The implicit solution: or
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1.6. Homogeneous, Bernoulli, and Riccati Eqs.
1.6.1 Homogeneous Equation: (A) * A homogeneous equation is always transformed into a separable one by letting ↑=1 (A)
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○ Example 1.25: Let (A)
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1.6.2. Bernoulli Equation linear separable
can be transformed into linear by
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○ Example 1.27: Let (A) Multiply by (linear) Integrating factor:
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Riccati Equation Let S(x) be a solution and let The Riccati equation is transformed into linear ○ Example 1.28: By inspection, is a solution of (A) Let
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(linear) Integrating factor: Integrate and Solution:
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Initial Value Problems:
1.8. Existence and Uniqueness for Solutions of Initial Value Problems Initial Value Problems: The problem may have no solution and may have multiple solutions ○ Example 1.30: The equation is separable and has solution The equation has no real solution. is not a solution because it does not satisfy the initial condition.
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○ Example 1.31: The equation has solution This problem has multiple solutions i, Trivial solution: ii, Define Consider All satisfy the initial condition
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○ Theorem 1.2: If f, : continuous in , then s.t.
The initial value problem has a unique solution defined on The size of h depends on f and
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the entire plane and hence on
○ Example 1.31: not continuous on (x, 0) ○ Example:The problem : both continuous on the entire plane and hence on s.t. the problem has a unique solution in Solve the problem , which is valid for , we can take 41
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○ Theorem 1.3: : continuous on I The problem , has a unique solution defined Proof: From the general solution of the linear equation and the initial condition , the solution of the initial value problem is : continuous on I, the solution is defined
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Homework 1 Chapter 1 Sec.1.1: 1, 2, 7, 12 Sec.1.2: 1, 2, 11 Sec.1.3: 1 Sec.1.4: 1 Sec.1.5: 1
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1.5(1): Determine a test involving M and N to tell
when has an integrating factor that is a function of y only. Ans: Let be an integrating factor such that is exact. Then,
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must be independent of x.
The test is then that must be independent of x. 45
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Homework 2 Chapter 1 Sec.1.6: 15, 16, 20, 21 Sec.1.8: 1, 3, 5
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Chapter 2: Second-Order Differential Equations
2.1. Preliminary Concepts ○ Second-order differential equation e.g., Solution: A function satisfies , (I : an interval)
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○ Linear second-order differential equation
Nonlinear: e.g., 2.2. Theory of Solution ○ Consider y contains two parameters c and d
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The graph of Given the initial condition
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Given another initial condition
The graph of ◎ The initial value problem: ○ Theorem 2.1: : continuous on I, has a unique solution
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○ Theorem 2.2: : solutions of Eq. (2.2)
2.2.1.Homogeous Equation ○ Theorem 2.2: : solutions of Eq. (2.2) solution of Eq. (2.2) : real numbers Proof:
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※ Two solutions are linearly independent.
Their linear combination provides an infinity of new solutions ○ Definition 2.1: f , g : linearly dependent If s.t or ; otherwise f , g : linearly independent In other words, f and g are linearly dependent only if for
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○ Wronskian test -- Test whether two solutions of a homogeneous differential equation are linearly independent Define: Wronskian of solutions to be the 2 by 2 determinant
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○ Let If : linear dep., then or Assume
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○ Theorem 2.3: 1) Either or 2) : linearly independent iff Proof (2): (i) (if : linear indep. (P), then (Q) if ( Q) , then : linear dep. ( P) ) : linear dep.
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(ii) (if (P), then : linear indep. (Q)
if : linear dep. ( Q), then ( P)) : linear dep., ※ Test at just one point of I to determine linear dependency of the solutions
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。 Example 2.2: are solutions of : linearly independent
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。 Example 2.3: Solve by a power series method The Wronskian of at nonzero x would be difficult to evaluate, but at x = 0 are linearly independent
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○ Definition 2.2: ◎ Find all solutions 1. : linearly independent
: fundamental set of solutions : general solution : constant ○ Theorem 2.4: : linearly independent solutions on I Any solution is a linear combination of
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Proof: Let be a solution.
Show s.t. Let and Then, is the unique solution on I of the initial value problem
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2. 2. 2. Nonhomogeneous Equation ○ Theorem 2
Nonhomogeneous Equation ○ Theorem 2.5: : linearly independent homogeneous solutions of : a nonhomogeneous solution of any solution has the form
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Proof: Given , solutions
: a homogenous solution of : linearly independent homogenous solutions (Theorem 2.4)
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1. Find the general homogeneous solutions
○ Steps: 1. Find the general homogeneous solutions of 2. Find any nonhomogeneous solution of 3. The general solution of is 2.3. Reduction of Order -- A method for finding the second independent homogeneous solution when given the first one
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○ Let Substituting into ( : a homogeneous solution ) Let (separable)
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For symlicity, let c = 1, 。 Example 2.4: : a solution Let
: independent solutions 。 Example 2.4: : a solution Let
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Substituting into (A), For simplicity, take c = 1, d = 0 : independent The general solution:
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2. 4. Constant Coefficient Homogeneous A, B : numbers ----- (2
2.4. Constant Coefficient Homogeneous A, B : numbers (2.4) The derivative of is a constant (i.e., ) multiple of Constant multiples of derivatives of y , which has form , must sum to 0 for (2,4) ○ Let Substituting into (2,4), (characteristic equation)
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i) Solutions : : linearly independent The general solution:
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。 Example 2.6: Let , Then Substituting into (A), The characteristic equation: The general solution:
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ii) By the reduction of order method, Let Substituting into (2.4)
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Choose : linearly independent The general sol. : 。 Example 2
Choose : linearly independent The general sol.: 。 Example 2.7: Characteristic eq. : The repeated root: The general solution:
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iii) Let The general sol.:
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。 Example 2.8: Characteristic equation: Roots: The general solution: ○ Find the real-valued general solution 。 Euler’s formula:
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Maclaurin expansions:
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。 Eq. (2.5),
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Find any two independent solutions Take
The general sol.:
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2.5. Euler’s Equation , A , B : constants -----(2.7)
Transform (2.7) to a constant coefficient equation by letting
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Substituting into Eq. (2. 7), i. e. , --------(2
Substituting into Eq. (2.7), i.e., (2.8) Steps: (1) Solve (2) Substitute (3) Obtain
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Characteristic equation: Roots: General solution:
。 Example 2.11: (A) (B) (i) Let Substituting into (A) Characteristic equation: Roots: General solution:
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○ Solutions of constant coefficient linear equation have the forms:
Solutions of Euler’s equation have the forms:
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2.6. Nonhomogeneous Linear Equation ------(2.9)
The general solution: ◎ Two methods for finding (1) Variation of parameters -- Replace with in the general homogeneous solution Let Assume (2.10) Compute
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Substituting into (2.9), -----------(2.11) Solve (2.10) and (2.11) for
Likewise,
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。 Example 2. 15: ------(A) i) General homogeneous solution : Let
。 Example 2.15: (A) i) General homogeneous solution : Let . Substitute into (A) The characteristic equation: Complex solutions: Real solutions: :independent
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ii) Nonhomogeneous solution Let
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iii) The general solution:
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(2) Undetermined coefficients Apply to A, B: constants Guess the form of from that of R e.g. : a polynomial Try a polynomial for : an exponential for Try an exponential for
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。 Example 2.19: ---(A) It’s derivatives can be multiples of or Try Compute Substituting into (A),
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: linearly independent
and The homogeneous solutions: The general solution:
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。 Example 2. 20: ------(A) , try Substituting into (A),
。 Example 2.20: (A) , try Substituting into (A), * This is because the guessed contains a homogeneous solution Strategy: If a homogeneous solution appears in any term of , multiply this term by x. If the modified term still occurs in a homogeneous solution, multiply by x again
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Try Substituting into (A),
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○ Steps of undetermined coefficients: (1) Find homogeneous solutions (2) From R(x), guess the form of If a homogeneous solution appears in any term of , multiply this term by x. If the modified term still occurs in a homogeneous solution, multiply by x again (3) Substitute the resultant into and solve for its coefficients
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○ Guess from Let : a given polynomial , : polynomials with unknown coefficients
Guessed
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2.6.3. Superposition Let be a solution of is a solution of (A)
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。 Example 2.25: The general solution: where homogeneous solutions
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Chapter 3: The Laplace Transform
3.1. Definition and Basic Properties 。 Objective of Laplace transform -- Convert differential into algebraic equations ○ Definition 3.1: Laplace transform s.t. converges s, t : independent variables * Representation:
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。Example 3.2: Consider
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Not every function has a Laplace transform
* Not every function has a Laplace transform. In general, can not converge 。Example 3.1:
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○ Definition 3.2.: Piecewise continuity (PC) f is PC on if there are finite points s.t. and are finite i.e., f is continuous on [a, b] except at finite points, at each of which f has finite one-sided limits
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If f is PC on [0, k], then so is and
exists
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◎ Theorem 3.2: Existence of f is PC on If Proof:
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* Theorem 3.2 is a sufficient but not a necessary
condition.
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* There may be different functions whose Laplace transforms are the same e.g., and have the same Laplace transform ○ Theorem 3.3: Lerch’s Theorem * Table 3.1 lists Laplace transforms of functions
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○ Theorem 3. 1: Laplace transform is linear Proof: ○ Definition 3. 3:
○ Theorem 3.1: Laplace transform is linear Proof: ○ Definition 3.3:. Inverse Laplace transform e.g., * Inverse Laplace transform is linear
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3.2 Solution of Initial Value Problems Using Laplace Transform ○ Theorem 3.5: Laplace transform of f: continuous on : PC on [0, k] Then, (3.1)
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Proof: Let
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○ Theorem 3.6: Laplace transform of : PC on [0, k] for s > 0, j = 1,2 … , n-1
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。 Example 3.3: From Table 3.1, entries (5) and (8)
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○ Laplace Transform of Integral
From Eq. (3.1),
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3.3. Shifting Theorems and Heaviside Function
3.3.1.The First Shifting Theorem ◎ Theorem 3.7: ○ Example 3.6: Given
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○ Example 3.8:
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3.3.2. Heaviside Function and Pulses
○ f has a jump discontinuity at a, if exist and are finite but unequal ○ Definition 3.4: Heaviside function 。 Shifting
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。 Laplace transform of heaviside function
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3.3.3 The Second Shifting Theorem
Proof:
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○ Example 3.11: Rewrite
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◎ The inverse version of the second shifting theorem ○ Example 3.13:
where rewritten as
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3.4. Convolution
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◎ Theorem 3.9: Convolution theorem Proof:
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◎ Theorem 3.10: ○ Exmaple 3.18 ◎ Theorem 3.11: Proof :
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○ Example 3.19:
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3.5 Impulses and Dirac Delta Function
○ Definition 3.5: Pulse ○ Impulse: ○ Dirac delta function: A pulse of infinite magnitude over an infinitely short duration
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○ Laplace transform of the delta function ◎ Filtering (Sampling) ○ Theorem 3.12: f : integrable and continuous at a
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Proof:
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by Hospital’s rule ○ Example 3.20:
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3.6 Laplace Transform Solution of Systems
○ Example 3.22 Laplace transform Solve for
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Partial fractions decomposition Inverse Laplace transform
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3.7. Differential Equations with Polynomial Coefficient
◎ Theorem 3.13: Proof: ○ Corollary 3.1:
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○ Example 3.25: Laplace transform
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Find the integrating factor, Multiply (B) by the integrating factor
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Inverse Laplace transform
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○ Apply Laplace transform to algebraic expression for Y
Differential equation for Y
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◎ Theorem 3.14: PC on [0, k],
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○ Example 3.26: Laplace transform ------(A) ------(B)
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Finding an integrating factor, Multiply (B) by ,
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In order to have
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Formulas: ○ Laplace Transform: ○ Laplace Transform of Derivatives: ○ Laplace Transform of Integral:
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○Shifting Theorems: ○ Convolution: Convolution Theorem: ○
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○
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