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Liquids and Solids
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Phase Changes Solid to Liquid Melting Fusing
Ice melts at 0 degrees Celsius
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Phase Changes Liquid to gas vaporization Evaporation Boiling
A vapor is the gas phase of a substance that is liquid at room temperature water boils at 100 degrees Celsius
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Phase Changes Gas to Liquid Condensation
Water vapor condenses to water liquid at 100 degrees Celsius
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Phase Changes Liquid to Solid solidification freezing Crystallization
water freezes at 0 degrees Celsius
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Solid to Gas (skip liquid)
Phase Changes Solid to Gas (skip liquid) sublimation Dry ice (Solid carbon dioxide) sublimes into carbon dioxide gas at room temperature
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Gas to Solid (skip liquid)
Phase Changes Gas to Solid (skip liquid) deposition Water vapor deposits into ice crystals on cold surfaces
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Heating Curve
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Heating Curve of Water
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Cooling Curve
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Cooling Curve gas condensing liquid freezing solid
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During a phase change: The temperature does not change (flat line)
Average kinetic energy does not change Potential Energy changes!
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KE increases PE increases
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Energy equations Q = mcΔt
Can only be used when there is no phase change occurring
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Energy equations Q = mhf
Can only be used when there is melting or freezing occurring Hf is the heat of fusion (Notice there is no temperature term, since temp does not change)
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Hv is the heat of vaporization
Energy equations Q = mhv Can only be used when there is boiling or condensing occurring Hv is the heat of vaporization (Notice there is no temperature term, since temp does not change)
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Example # 1 Which equation would you use for this problem?
How many joules of heat are absorbed when 50 g of water is heated from 30.2 degrees C to 58.6 degrees C? Q = mcΔt
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Answer Q = 50g x 4.18 J/goc x (58.6 – 30.2 oC) Q = 5936J
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Example # 2 Which equation would you use for this problem?
How many joules of heat are required to melt 225 g of ice at 0 degrees C? Q = mHf
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Answer Q = 225g x 334 J/g Q = 75,150 J Q = kJ
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Example # 3 Which equation would you use for this problem?
How many joules of heat are required to vaporize 423 g of water at 100 degrees C? Q = mHv
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Answer Q = 423g x 2260 J/g Q = 955,980 J Q = kJ
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Why does boiling 1 g of water require so much more energy than melting 1 g of water?
Boiling = 2260 J/g Melting = 334 J/g
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Lots of energy needed to separate the particles from liquid to gas
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