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ES2501: Statics/Unit 14-1: Equilibrium of Rigid Bodies: 2D Problems

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Presentation on theme: "ES2501: Statics/Unit 14-1: Equilibrium of Rigid Bodies: 2D Problems"— Presentation transcript:

1 ES2501: Statics/Unit 14-1: Equilibrium of Rigid Bodies: 2D Problems
Equilibrium Equations (2D): Force eqns can be replaced by one or two moment eqn(s). Say, Maximum three independent scalar eqns A Ai y x Statically indeterminate Problems: Number of unknowns is more than the number of equilibrium equations

2 ES2501: Statics/Unit 14-2: Equilibrium of Rigid Bodies: 2D Problems
Basic Procedures of Static Analysis Step 1: Draw free-body diagram(s); Step 2: List equilibrium equations; Step 3: Any supplementary equations? (for statically inderminate problems); Step 4: Solution; Step 5: Interpretation.

3 ES2501: Statics/Unit 14-3: Equilibrium of Rigid Bodies: 2D Problems
Free-Body Diagrams: Draw a FBD is still the first step for static analysis. Need to know nature reaction forces of supports Constrains of Supports (Reactions): Pin-connected (Hinged, Simply-support) Roller-support Only motion in the y- direction is restricted Motion in both x- and y- directions are restricted Fixed-support (built-in, clamped) Roller-support Motion in both x- and y- directions And also rotation about z-axis are restricted Only motion in the x- direction is restricted

4 ES2501: Statics/Unit 14-4: Equilibrium of Rigid Bodies: 2D Problems
Example 1: A ladder stands on a rough ground against a smooth wall. A man of weigh W climbs up. Assume that weight of the latter is ignored. The static friction coefficient between the ladder and the ground is Find the man can climb up such that the ladder will not slide down. Step 1: FBD (See the figure) B Note: There are three unknowns: Step 2: List Equilibrium equations. A Step 3: Solution What if weight of the ladder is considered? Law of friction: -Rougher ground and large angle help. - Infependent of W What if the wall is also rough, i.e. friction needs to be considered? --- Statically underminate

5 ES2501: Statics/Unit 14-5: Equilibrium of Rigid Bodies: 2D Problems
Example 2: Find reaction forces of supports in the following sytems. Statically equivalent Force: Step 1: FBD (See the above) Note: Different supports provide different reactions Step 2: List Equilibrium equations “-” indicates a force direction opposite to the assumed Step 3:Solution

6 ES2501: Statics/Unit 14-6: Equilibrium of Rigid Bodies: 2D Problems
Example 2: Comments 1. Alternative (moment) equations can be used The same results 2. Superposition Principle helps: + = The results for distributed load The results for single P The total results

7 ES2501: Statics/Unit 14-7: Equilibrium of Rigid Bodies: 2D Problems
Example 2: Comments 3. Sign consideration: Starts forces with an assumed direction. If a result is negative, the actual force direction should be opposite to the assumed. 4. Other supports? 5. Statically indeterminate problems: Different supports provide different reaction forces 5. More complex problems?


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