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The Dimension of Cone and Ball

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1 The Dimension of Cone and Ball

2 Kerucut/ Cone Limas beraturan yang memiliki alas berbentuk lingkaran. Memiliki satu alas dengan satu titik puncak. Pyramid which has circle base. Has one base with one peak spot.

3 Surface Area Of Cone Coat Area Cone : πrs Cone Area : πr(r+s) Note :
Π =3.14 r = the radius of base s = painter line

4 Cone Volume Volume :1/3 πr2 t Note : Π = 3.14 r = the radius t = hight

5 The example of cone

6 Example Find total area, volume, and coat area of : r(6 cm), height( 8 cm).

7 The answer We use theorema pythagoras to find the length of s. s2=r2+t2 and we get s = 10 cm A) The coat area = πrs = 3.14 X 6 X = cm2

8 B)Total Area : πr(r+s) :3.14 X 6(6+10) : cm2 C) Volume :1/3 πr2t :1/3X3.14X36X8 : cm3

9 Bola/Ball Rangkaian titik-titik pada suatu ruang yang mempunyai jarak yang sama dari titik tetap (pusat). Jarak tersebut disebut jari-jari bola. Network of spots in a room which have same distance from a still spot (center). That distance called radius.

10 Surface Area(Luas permukaan)
Surface Area(SA)= 4 πr2

11 Volume of ball ( Volume)
Volume(V)=4/3 πr3

12 Example Find the area and the volume from ball that have r=6 cm

13 Answer A) The area : 4 πr2 : 4X3.14X36 : 452.16 cm2
B) The Volume : 4/3 πr3 : 4/3X3.14X216 : cm3

14 The Example of ball


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