1. شناخت فرآیندهای صنعتی استاد راهنما : آقای دکتر لواسانی گروه ارائه دهنده : مجتبی محمدی سید حمید رضا شبیری اکبرظاهری 1 Blow out, given a kick while drilling string is running through the BOP FAULT TREE ANALISIS

4. فورانگیرها (BOPs)

5. انباره (ACCUMULATOR) 5 بستن فورانگیرها با روغنهای هیدرولیکی تحت فشار توسط نیتروژن ( ۱۰۰۰ الی۱۱ 00 ‍پام )

7. 7

10. Blow out, given a kick while drilling string is running through the BOP Oil Flow Controls Fails Main Control fails Chassis Fails General Shear Ram Failure General Don’t reach position Fails to maintain closure Not enough pressurePipe is not cut Not Activated General Annular Preventer Failure General Ram Preventer Failure General chock and kill valve Failure General chock and kill Lines all Failure General connect -ion Failure General Flexible joint Failure Seal Failure Blade is Dull Hydraulic leak Pipe collar in the way Pipe is too thick No Manual activation No automatic activation Wedges fail Loss hydraulic pressu re or and General main Control system Failure and

11. λ=1/334 λ=1/364 λ=1/67 λ=1/501 λ=1/308 λ=1/400 λ=1/4009 λ=1/401

12. T.E= X 1 +X 2 +X 3 X 3 = F+G X 2 = F+D+E X 1 = A.B. X 4 X 1 =A.B. (I+L+ (P.Q) +M+N+O+ (J.K) X 4 = I+X 5 X 6 = J.K X 5 = X 7 +X 8 X 8 = M+N+O X 7 = L+X 9 X 9 = P.Q X 7 =L+ (P.Q) X 5 = L+ (P.Q) +M+N+O X 4 =I+L+ (P.Q) +M+N+O+ (J.K) ………………………… X 1 =A.B. (I+L+ (P.Q) +M+N+O+ (J.K) CALCULATIONS

13. 0.0027= 1 – 1/4009))( 1 – (1 – 1.901 <= شاخه سوم 0.02= 1 – 1/308)) 1 – 1/501))( 1 – (1 – 1.67 <= شاخه دوم 0.02= 1 – 1/308)) 1 – 1/501))( 1 – (1 – 1.67 <= شاخه دوم (1/334) (1/364) (1/400) = 0.2 x 10 - 8 <= شاخه اول (1/334) (1/364) (1/400) = 0.2 x 10 - 8 <= شاخه اول T E= X 1 +X 2 +X 3 -X 1 X 2 -X 1 X 3 -X 2 X 3 +X 1 X 2 X 3 T E= 1-[(1-X 1 ) (1-X 2 ) (1-X 3 )] T E= 1-[(1-0.0027) (1-0.02) (1-0.2x10-8)] = 0.022