Presentation is loading. Please wait.

Presentation is loading. Please wait.

Microwave Circuit Design

Similar presentations


Presentation on theme: "Microwave Circuit Design"— Presentation transcript:

1 Microwave Circuit Design

2 Syllabus Transmission lines Network parameters Matching techniques
Power dividers and combiners Diode circuits Microwave amplifiers Oscillators Filters design Applications Miscellaneous

3 References David M Pozar ,Microwave Engineering- 2nd Ed., John Wiley , 1998 E.H.Fooks & R.A.Zakarevicius, Microwave Engineering using microstrip circuits, Prentice Hall,1989. G. D. Vendelin, A.M.Pavio &U.L.Rohde, Microwave circuit design-using linear and Nonlinear Techniques, John Wiley, 1990. W.H.Hayward, Introduction to Radio Frequency Design, Prentice Hall, 1982.

4 Transmission Line

5 Equivalent Circuit R L R L C G Lossy line Lossless line

6 From Kirchoff Voltage Law
Analysis From Kirchoff Voltage Law Kirchoff current law (a) (b)

7 Analysis then Let’s V=Voejwt , I = Ioejwt Therefore b a
Differentiate with respect to z

8 Analysis The solution of V and I can be written in the form of c d
where and Let say at z=0 , V=VL , I=IL and Z=ZL Therefore f e and

9 Analysis Solve simultaneous equations ( e ) and (f )
Inserting in equations ( c) and (d) we have

10 Analysis and But Then, we have * ** and

11 For lossless transmission line , g= jb since a=0
Analysis or Or further reduce For lossless transmission line , g= jb since a=0

12 Standing Wave Ratio (SWR)
Analysis antinode Standing Wave Ratio (SWR) Reflection coefficient node Ae-gz Begz Voltage and current in term of reflection coefficient or

13 Analysis For loss-less transmission line g = jb
By substituting in * and ** ,voltage and current amplitude are g h Voltage at maximum and minimum points are and Therefore For purely resistive load

14 Analysis Other related equations
From equations (g) and (h), we can find the max and min points Maximum Minimum

15 Important Transmission line equations
Zin ZL Zo

16 Various forms of Transmission Lines

17 Parallel wire cable Where a = radius of conductor
d = separation between conductors

18 Coaxial cable b a Where a = radius of inner conductor
b = radius of outer conductor c = 3 x 108 m/s

19 Micro strip Conducted strip t Substrate he er w Ground
t=thickness of conductor

20 Characteristic impedance of Microstrip line
w=width of strip h=height and t=thickness Where

21 Microstrip width For A>1.52 For A<1.52

22 Simple Calculation Approximation only

23 Microstrip components
Capacitance Inductance Short/Open stub Open stub Transformer Resonator

24 Capacitance Zoc Zo Zo For For

25 Inductance ZoL Zo Zo For For

26 Short Stub Zo Zo Zo ZL Z

27 Open stub Zo Zo Zo ZL Z

28 Quarter-wave transformer
l/4 x ZT ZL Zo Zo Zmx/min At maximum point q in radian

29 Quarter-wave transformer
at minimum point q in radian

30 Resonator Circular microstrip disk Circular ring
Short-circuited l/2 lossy line Open-circuited l/2 lossy line Short-circuited l/4 lossy line

31 * These components usually use for resonators
Circular disk/ring feeding a a * These components usually use for resonators

32 Short-circuited l/2 lossy line
Zin = series RLC resonant cct Zo b a =nl/2 where

33 Open-circuited l/2 lossy line
Zin = parallel RLC resonant cct Zo b a =nl/2 where

34 Short-circuited l/4 lossy line
Zin = parallel RLC resonant cct Zo b a =l/4 where

35 Rectangular waveguide
b a Cut-off frequency of TE or TM mode Conductor attenuation for TE10

36 Using this equation to calculate cutoff frequency of each mode
Example Given that a= 2.286cm , b=1.016cm and s=5.8 x 107S/m. What are the mode and attenuation for 10GHz? Using this equation to calculate cutoff frequency of each mode

37 Calculation TE10 a=2.286mm, b=1.016mm, m=1 and n=0 ,thus we have
Similarly we can calculate for other modes

38 Example TE20 TE01 TE11 TE10 6.562GHz 13.123GHz 14.764GHz 16.156GHz Frequency 10Ghz is propagating in TE10.mode since this frequency is below the GHz (TE20) and above 6.561GHz (TE10)

39 continue or

40 Evanescent mode Mode that propagates below cutoff frequency of a wave guide is called evanescent mode Wave propagation constant is Where kc is referred to cutoff frequency, g is referred to propagation in waveguide and b is in space When f0< fc , But g = a +jb a=attenuation b=phase constant Since no propagation then The wave guide become attenuator

41 Cylindrical waveguide
TE mode Dominant mode is TE11

42 continue a TM mode TM01 is preferable for long haul transmission

43 Example Refer to tables TM modes TE modes
Find the cutoff wavelength of the first four modes of a circular waveguide of radius 1cm 2nd mode Refer to tables TM modes TE modes 3rd &4th modes 3rd &4th modes 1st mode

44 Calculation 1st mode Pnm= 1.841, TE11 2nd mode Pnm= 2.405, TM01
1st mode Pnm= 3.832, TE01 and TM11

45 Stripline b w

46 Continue On the other hand we can calculate the width of
stripline for a given characteristic impedance

47 t =thickness of the strip
Continue Where t =thickness of the strip


Download ppt "Microwave Circuit Design"

Similar presentations


Ads by Google