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Solving Rational Inequalities
Part 1
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In order to solve a rational inequality,
it MUST be set equal to ZERO and be simplified to a SINGLE RATIONAL EXPRESSION. Example: π π βπ π π βπ <π
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π π βπ π π βπ <π Now follow these stepsβ¦ Step 1: Factor the top and bottom of the rational expression and find all the values of x that make the top = 0 and the bottom = 0. (top) (x + 3) (x β 3) soβ¦ x = 3 and -3 (bottom) (x + 1) (x β 1) soβ¦ x = 1 and -1
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Step 2: Draw a picture of the x-axis and mark these
points. These are often called βcritical pointsβ. Discuss marking the critical points with open or closed circles depending on the inequality symbol.
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Step 3: Our critical points partition the x-axis into
five intervals. Pick a point (your choice!) within each interval. Letβs use x = 0, x = Β±2, and x = Β±4. Compute f(x) for these points. π β4 = π β2 = π 0 = π 2 = π 4 = β5 3 <0 7 15 >0 β9 β1 >0 β5 3 <0 7 15 >0
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These five points represent what happens in the intervals in which they are contained.
You can indicate this on the x-axis by inserting plus or minus signs on the x-axis. + -- + -- +
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Step 4: We want the expression to be
LESS THAN 0, so we are looking for the intervals that are negative. The solution is β¦. (-3, -1) and (1, 3). If the inequality had β₯ or β€ then you would use brackets [ ] around the intervals.
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x β 1 x + 2 β€ 0 (-2, 1] (-β, -3] , [-2,-1) , (5, β) x 2 + 5x + 6 x 2 β 4x β 5 β₯ 0 x 2 β 16 x 2 β 3x + 2 < 0 (-4,1) , (2,4)
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Solving Rational Inequalities
Part 2 What do I do when the problem isnβt a SINGLE RATIONAL EXPRESSION set equal to ZERO?
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Solving Rational Inequalities 2
Remember from previous notes that you must COMBINE all fractions together on ONE SIDE so it is set to 0. 2 π₯β4 + 1 π₯+1 >0 How would we combine this into a single fraction on the left?
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Try this one: 1 π₯ π₯β4 <0
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What if there are terms on BOTH sides?
2π₯ 4 β 5π₯+1 3 >3
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Extra Credit Level:
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Practice: 1) 2) 3) 4) 5) 4 π₯β6 + 2 π₯+1 >0 π₯+6 4π₯ β3 β₯1 π₯ 2 βπ₯β11 π₯β2 β€3 1 π₯ > 1 π₯+5 π₯ π₯+1 β π₯β1 π₯ < 1 20
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