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ACIDS, BASES and SALTS Definitions Acid Base
Arrhenius Dissociates in water to produce a hydrogen ion (H +) HCl(aq) + H2O(l) H+(aq) + Cl-(aq) H3O+(aq) + Cl-(aq) Dissociates in water to produce a hydroxide ion (OH -) NaOH(aq) + H2O(l) Na+(aq) + OH-(aq)
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Accepts pair of electrons Donates a pair of electrons
ACIDS, BASES and SALTS Definitions Acid Base Lewis Accepts pair of electrons Donates a pair of electrons
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ACIDS, BASES and SALTS Hydrogen ion donor (H +) Proton donor
Definitions Acid Base Bronsted-Lowry Hydrogen ion donor (H +) Proton donor Hydrogen ion acceptor (H +) Proton acceptor
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ACIDS, BASES and SALTS Hydrogen ion donor (H +) Proton donor
Definitions Acid Base Bronsted-Lowry Hydrogen ion donor (H +) Proton donor Hydrogen ion acceptor (H +) Proton acceptor 11H ● → 11H + Hydrogen atom loses e- to become hydrogen ion
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ACIDS, BASES and SALTS NH3 + H2O NH4+ + OH- NH4+ + OH- NH3 + H2O
Conjugate Acid – Base Pairs - (use Bronsted-Lowry definition) NH H2O NH OH- NH OH NH H2O
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Identify the conjugate acid base pairs.
CH3COO- + H2O ↔ CH3COOH + OH-
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Identify the conjugate acid base pairs.
HCN + H2O ↔ H3O CN-
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Identify the conjugate acid base pairs.
HNO3 + H2O ↔ NO H3O+ H2PO H2O ↔ H3O HPO42- H3PO OH- ↔ H2PO H2O HClO4 + CH3COOH ↔ CH3COOH ClO2-
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For the following list which two substances act like acids and which act like bases.
H2CO H2O ↔ H3O HCO3- HI H2O ↔ H3O I-
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HSO HF ↔ H2SO F- H2O H2O ↔ H3O OH-
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Amphoteric (Amphiprotic) substances
ACIDS, BASES and SALTS Amphoteric (Amphiprotic) substances – can act as either an acid _________________ or as a base _________________________ proton (H+) donor proton (H+) acceptor
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ACIDS, BASES and SALTS Identify the acid, base, conjugate acid and conjugate base. (see Table L - the stronger acid is the proton donor) Remember Bronstead-Lowery Definitions: An acid donates a proton (H+) A base accepts a proton (H+)
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ACIDS, BASES and SALTS H2O H2O + NH3 ↔ H2O + HCl ↔ NH3 NH3 + HCl ↔
NH3 NH3 + HCl ↔ NH3 + H- ↔ HCO3- HCO3- + H2O ↔ HCO3- + HSO4- ↔ HSO4- HSO4- + H2O ↔ HSO4- + HCl ↔ H2PO4- H2PO4- + H2O ↔ H2PO4- + HBr ↔
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