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By: Drake Hudspeth 03/07/11 Math-03

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1 By: Drake Hudspeth 03/07/11 Math-03
x=algebra The substitute is in! By: Drake Hudspeth 03/07/11 Math-03

2 The Problem Equations- 3x+y=38 3x+2y=52
The school that Stefan goes to is selling tickets to a choral performance. On the first day of ticket sales the school sold three senior citizen tickets and one child ticket for a total of 38$. The school took in 52$ on the second day by selling three senior citizen tickets and two child tickets. Find the price of a senior citizen ticket and the price of a child ticket. Equations- 3x+y=38 3x+2y=52

3 Graphing Use Microsoft Excel.
Plot your point in cells B2 and C2-B8 and C8. Use cell A1 to put x. In A2-A8 put -5,-3,-1,0,1,3,and5. Put your equation in cells B1 and C1. Go to insert and choose graphs. Pick the x and y graph. The reason that I do not recommend this system is because there is no way to go back and see why you missed the answer and because you must first solve for y.

4 Substitution Start with one equation. 3x+y=38
Subtract the x on both sides. 3x-3x+y=38-3x You now use this y on the next equation. 3x+2(38-3x)=52 Distribute or multiply what is outside of the parenthesis with what is inside of it. 3x+76-6x=52 Combine like terms. -3x=-24 Divide the two terms that you have. X=8 Use x to solve for y. 3(8)+y=38 Distribute. 24+y=38 Subtract the integer on the left from the integer on the right. 38-24=14 You now have y. y=14 So x=8 and y=14. I enjoy this method because it is accurate and there are many steps to see where you have made a mistake.

5 Elimination You must use both equations in the beginning. First subtract one integer from the other. (3x+2y=52)-(3x+y=38). You now have y=14. Now plug y=14 into one equation. 3x+2(14)=52 Distribute. 3x+28=52 Subtract the integer on the left from the integer on the right =24 You should now have 3x=24. Now divide. 24/3=8 y=14 and x=8 This method is okay to use but it will not always be this simple.


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