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To be worked at the blackboard in lecture. R

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Presentation on theme: "To be worked at the blackboard in lecture. R"— Presentation transcript:

1 To be worked at the blackboard in lecture. R
Example: calculate the electric field at “center” of semicircular line of uniformly-distributed positive charge, oriented as shown. +Q To be worked at the blackboard in lecture. R y x You don’t have to follow the steps in the exact order I present here. Just let the problem tell you what to. You may do things in a different order; that’s probably OK. d ds R dE

2 Start with our usual OSE. dq ds
Example: calculate the electric field at “center” of semicircular line of uniformly-distributed positive charge, oriented as shown. +Q Start with our usual OSE. dq ds d R y Pick an infinitesimal dq of charge. x dq subtends an arc length ds, and an angle d. What is the charge dq?

3 Draw the dE due to the dq, and show its components. dq ds dq′ R
Example: calculate the electric field at “center” of semicircular line of uniformly-distributed positive charge, oriented as shown. +Q Draw the dE due to the dq, and show its components. dq ds dq′ d R y Do you see any helpful symmetry? dE′ dE x Pick a dq′ horizontally across the arc from dq. The x-components of dq and dq′ will cancel. Because of this symmetry, Ex = 0 Each dEy points downward so Ey will be negative.

4  is also one of the angles in the vector triangle.
Example: calculate the electric field at “center” of semicircular line of uniformly-distributed positive charge, oriented as shown. +Q Recall that dq and ds are infinitesimal. dq is located at an angle  along the semicircle from the negative y-axis. dq ds dq R y dE x  is also one of the angles in the vector triangle.

5 Example: calculate the electric field at “center” of semicircular line of uniformly-distributed positive charge, oriented as shown. +Q An arc of a circle has a length equal to the circle radius times the angle subtended (in radians): dq ds dq R y dE x Also,

6 Let’s summarize what we have done so far. dq ds dq R
y dE x Every dq is a distance R away from the arc center:

7 Awesome Youtube derivation: http://www.youtube.com/watch?v=L1n2EUvayfw
+Q dq ds dq R y dE x Awesome Youtube derivation:


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