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TRIGONOMETRIC LEVELLING

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Presentation on theme: "TRIGONOMETRIC LEVELLING"— Presentation transcript:

1 TRIGONOMETRIC LEVELLING
Base of the object is not accessible. (Expression for R. L. of top of the object)

2 Roll No. Group Members. Enroll. No. 42 Jubin Tamakuwala

3 SURVEYING ( )

4 Trigonometric leveling.
Definition: “ Trigonometric levelling is the process of determining the differences of elevations of stations from observed vertical angles and known distances. ” The vertical angles are measured by means of theodolite. The horizontal distances by instrument Relative heights are calculated using trigonometric functions. Note : If the distance between instrument station and object is small. correction for earth's curvature and refraction is not required.

5 Method of Observation. Direct Method:
Where is not possible to set the instrument over the station whose elevation is to be determined. Combined correction is required. 2) Reciprocal method: In this method the instrument is set on each of the two station, alternatively and observations are taken.

6 METHODS OF DETERMINING THE ELEVATION OF A POINT BY THEODOLITE:
Case 1. Base of the object accessible A = Instrument station B = Point to be observed h = Elevation of B from the instrument axis D = Horizontal distance between A and the base of object h1 = Height of instrument (H. I.) Bs = Reading of staff kept on B.M. = Angle of elevation = L BAC => h = D tan 

7 Case 2. Base of the object inaccessible, Instrument stations in the vertical plane as the elevated object.

8 Case 3. Base of the object inaccessible.
Instrument stations not in the same vertical plane as the elevated object.

9 Procedure. Set up the instrument at P and measure the horizontal angle QPR’(1). Measure the vertical angle 1. Take the staff reading h1 at the BM. Shift the instrument to Q. Set it up and measure the horizontal angle PQR’(1). Measure the vertical angle 2. Take the staff reading h2 on the BM. Measure the Horizontal distance d between the instrument stations(P and Q).

10 In triangle PQR’ L PR’Q = 180 – ( 1 + 2 ) = 3 By the sine rule,

11 Knowing horizontal distances D1 and D2, the vertical components H1 an H2 are calculated as under: Now, H1 = ST = P’T tan 2 = PR’ tan2 [since P’T=PR’] And H2 = SR” = tan2 = QR’ tan2 [since Q’R’’=QR’] R.L. of S = R.L. of B.M. + h1 + H2 Also R.L. of S = R.L. of B.M. + h2 + H2

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