1. Warm-Up Geometry 1st Hour – Unit 10 Test Scores 103 94 87 77 65
Mean = _______ Median = _______
Mode = _______ Range = ________

2. Warm-Up Geometry 2nd Hour – Unit 10 Test Scores 103 92 86 65 31
Mean = _______ Median = _______
Mode = _______ Range = ________

3. Warm-Up Geometry 7th Hour – Unit 10 Test Scores 104 101 93 80 37
Mean = _______ Median = _______
Mode = _______ Range = ________

4. Surface Area of Prisms and Cylinders
Section 12 – 2
Surface Area of Prisms and Cylinders

5. Vocabulary
Polyhedron: A solid that is bounded by polygons, called faces, that enclose a single region of space.
Prism: A polyhedron with two congruent faces, called bases, that lie in parallel planes.
Lateral Faces: The faces of a prism that are parallelograms formed by connecting the corresponding vertices of the bases of the prism.
Lateral Edges: The segments connecting the corresponding vertices of the bases of a prism.

6. Vocabulary
Lateral Area: The sum of the areas of the faces of a polyhedron or other solid.
Surface Area: The sum of the areas of the lateral faces of a polyhedron or other solid with one or two bases.

7. Surface Area of a Prism:
Theorem 12-2
Surface Area of a Prism:
The surface area SA of a right prism is
SA = LA + 2B
LA = Ph
SA = Ph + 2B
where B is the area of the base, P is the perimeter of a base and h is the height.

8. Surface Area of a Right Cylinder:
Theorem 12-3
Surface Area of a Right Cylinder:
The surface area SA of a right cylinder is
SA = 2Πr2 + 2Πrh
r is the radius of a base and h is the height.

9. Example 1 LA = Ph LA = 22(6) LA = 132 cm2 SA = LA + 2B
Find the surface area of a rectangular prism.
LA = Ph
LA = 22(6)
3 cm
LA = 132 cm2
8 cm
6 cm
SA = LA + 2B
SA = (8)(3)
SA =
SA = 180 cm2

10. Example 2 SA = 2Πr2 + 2Πrh SA = 2(3.14)(4)2 + 2(3.14)(4)(36)
Find the surface area of the cylinder.
4 in
SA = 2Πr2 + 2Πrh
SA = 2(3.14)(4)2 + 2(3.14)(4)(36)
36 in
SA =
SA = in2

11. Example 3 SA = 2Πr2 + 2Πrh 262.64 = 90.6832 + 23.864(h)
Find the height of the right cylinder, which has a surface area of cm2.
3.8
SA = 2Πr2 + 2Πrh
= 2(3.14)(3.8)2 + 2(3.14)(3.8)(h) h
= (h)
= h
h = 7.2 cm

12. Homework Section 12-2 Page 806 – 809 3, 6, 9 – 11, 13, 14, 17, 18,
20, 22, 28