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5.1 – Isotopes and average atomic mass
Ms. Munir
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Weighted Average Mass of (A + B + C) / Number of items
Given three items of mass 1.0 kg, 2.0 kg, 3.0 kg, the weighted average is: = = kg Given that you have 2 items of A, 3 items of B, and item of C. 2(1.0) + 3(2.0) + 1(3.0) = = 1.8 kg
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Calculating Average Atomic Mass
Example: 1 Lithium exists as 2 isotopes: Li – 6 & Li – 7 Li – 6 = 7.4% Li – 7 = 92.6% Mass of Li – 7 is 7.015u and Li – 6 is 6.015u Avg. atomic mass = = 6.941u
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Example Isotope Atomic Mass Unit (u) Relative Abundance
Silver has 2 isotopes. Isotope Atomic Mass Unit (u) Relative Abundance Ag – % Ag – % What is the average atomic mass of Ag?
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Calculating Isotopic Abundance
Boron exists as 2 isotopes. B – 10 (10.01u) and B – 11 (11.01u). Calculate the isotope abundance. Solution: From periodic table the avg. atomic mass of B is u. Let % abundance of B – 10 be x and B – 11 would be 1 – x. = x(10.01) + (1 – x)(11.01) = 10.01x – 11.01x 11.01 – = 11.01x – 10.01x x = x = 0.20 Therefore, B -10 is 20% B – 11 is 80%
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Homework P 167 #1-4 McGraw Hill P 170 # 5 – 8 McGraw Hill
Worksheet for Nelson (see Ms. Munir)
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