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(Constant acceleration)
Motion in a Plane (Constant acceleration)
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(Constant acceleration)
Motion in a Plane (Constant acceleration)
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(Constant acceleration)
Motion in a Plane (Constant acceleration) Example 1: A helicopter is in level flight with a constant horizontal speed of 11 m/s. At t = 0.0 s it begins to accelerate vertically at 0.96 m/s2. Assuming the helicopter’s acceleration remains constant for the time interval of interest, find… The horizontal and vertical distances through which it moves in 5.3 s, and Its x and y velocity components at t = 5.3 s.
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The equations of motion for an object undergoing constant acceleration are:
and What are the x- and y-components of the object’s initial position? A) x0 = 0 m, y0 = 0 m B) x0 = 1 m, y0 = 2 m C) x0 = 0 m, y0 = 2 m D) x0 = 1 m, y0 = 0 m E) x0 = 0 m, y0 = – 3 m
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The equations of motion for an object undergoing constant acceleration are:
and What are the x- and y-components of the object’s initial velocity? A) v0x = 0 m/s, v0y = 3 m/s B) v0x = 1 m/s, v0y = 2 m/s C) v0x = 0 m/s, v0y = 0 m/s D) v0x = 1 m/s, v0y = – 3m/s E) v0x = 0 m/s, v0y = – 3 m/s
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The equations of motion for an object undergoing constant acceleration are:
and What are the x- and y-components of the object’s acceleration? A) ax = 2 m/s2, ay = 0 m/s2 B) ax = 1 m/s2, ay = – 3 m/s2 C) ax = 0 m/s2, ay = – 6 m/s2 D) ax = 2 m/s2, ay = – 6m/s2 E) ax = 0 m/s2, ay = – 3 m/s2
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Motion subject only to the force of gravity
Projectile Motion Motion subject only to the force of gravity
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Motion subject only to the force of gravity
Projectile Motion Motion subject only to the force of gravity
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Projectile Motion Properties
Motion subject only to the force of gravity Properties Horizontal motion is independent of the vertical motion.
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The red ball drops straight down
The yellow ball has an initial horizontal motion Vertical motion is the same in each case
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Horizontal motion is uniform for the yellow ball
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Projectile Motion Properties
Motion subject only to the force of gravity Properties Horizontal motion is independent of the vertical motion. x vs. t is linear, y vs. t is quadratic (parabolic) y vs. x is always parabolic
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Projectile motion is always some part of a parabola
Projectile motion displays symmetry between left and right sides
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The angle between the initial velocity vector and the positive x-axis
“Launch angle” The angle between the initial velocity vector and the positive x-axis General launch angle Zero launch angle
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General Equations of Motion
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General Equations of Motion
Zero Launch Angle Equations of Motion (origin at the launch point)
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Zero Launch Angle Example 2: A person skateboarding with constant speed 1.30 m/s releases a ball from a height of 1.25 m above the ground. Find… x and y for t = s.
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Zero Launch Angle Example 2: A person skateboarding with constant speed 1.30 m/s releases a ball from a height of 1.25 m above the ground. Find… x and y for t = s. x and y for t = s.
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Zero Launch Angle Example 2: A person skateboarding with constant speed 1.30 m/s releases a ball from a height of 1.25 m above the ground. Find… x and y for t = s. x and y for t = s. the velocity, speed, and direction of motion of the ball at t = s.
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