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Chapter 6 Differentiation
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Section 6.3 L’Hospital’s Rule
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Consider the limit where f (x) L and g(x) M.
If g(x) 0 for x close to c and M 0, then Theorem says that If both L and M are zero, we can sometimes evaluate the limit by canceling a common factor in the quotient. In this section we derive another technique that is often easier to use than factoring and has wider application. In general, when L = M = 0, the limit of the quotient f /g is called an indeterminate form, because different values may be obtained for the limit. For example, for any real number k, let f (x) = kx and g(x) = x. Then So the indeterminate form (sometimes labeled 0/0) can lead to any real number as the limit.
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(Cauchy Mean Value Theorem) Theorem 6.3.1
Let f and g be functions that are continuous on [a, b] and differentiable on (a, b). Then there exists at least one point c (a, b) such that [ f (b) – f (a)] g (c) = [g (b) – g (a)] f (c). Theorem 6.3.1 Proof: Let h (x) = [ f (b) – f (a)]g (x) – [g (b) – g (a)] f (x) for each x [a, b]. Then h is continuous on [a, b] and differentiable on (a, b). Furthermore, h (a) = [ f (b) – f (a)]g (a) – [g (b) – g (a)] f (a) = f (b) g (a) – g (b) f (a) h (b) = [ f (b) – f (a)]g (b) – [g (b) – g (a)] f (b) = f (b) g (a) – g (b) f (a) So, h(a) = h(b). Thus, by the mean value theorem (or Rolle’s Theorem), there exists c (a, b) such that h(c) = 0. That is, [ f (b) – f (a)] g (c) – [g (b) – g (a)] f (c) = 0.
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Theorem 6.3.2 (L’Hospital’s Rule)
In the expression [ f (b) – f (a)] g (c) = [g (b) – g (a)] f (c), or, if g(x) = x for all x, then we have This formula is the original mean value theorem. Theorem 6.3.2 (L’Hospital’s Rule) Let f and g be continuous on [a, b] and differentiable on (a, b). Suppose that c [a, b] and that f (c) = g (c) = 0. Suppose also that g (x) 0 for x U, where U is the intersection of (a, b) and some deleted neighborhood of c. If with L , then
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L L We have c [a, b], f (c) = g (c) = 0, g (x) 0 for x U, and
Proof: Let (xn) be a sequence in U that converges to c. Apply the Cauchy mean value theorem to f and g on the intervals [xn, c] or [c, xn] to obtain a sequence (cn) with cn between xn and c for each n, such that [ f (xn) – f (c)] g (cn) = [g (xn) – g (c)] f (cn). Since g (x) 0 for all x U, and g (c) = 0, we must have g (xn) 0 for all n. (See Rolle’s Theorem.) Thus, since f (c) = g(c) = 0, we have L L for all n. Furthermore, since xn c and cn is between xn and c, it follows that cn c. Thus by Theorem 5.1.8, But then, so , also.
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Example 6.3.3 Example 6.3.4 Let f (x) = 2x2 – 3x + 1 and g(x) = x – 1.
Then f (1) = g(1) = 0. And we have f (x) = 4x – 3 and g (x) = 1, so that We did this same problem by factoring in Example Example 6.3.4 Let f (x) = 1 – cos x and g(x) = x2. Then f (0) = g(0) = 0. And we have f (x) = sin x and g (x) = 2x, so that Since sin x 0 and 2x 0 as x 0, we again have the indeterminate form 0/0. provided that the second limit exists. So we use l’Hospital’s rule again. Note that g (x) must be nonzero in a deleted neighborhood of 0, but it is permitted that g (0) = 0.
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Definition 6.3.6 Definition 6.3.7
In some situations we wish to evaluate the limit of a function for larger and larger values of the variable. Definition 6.3.6 Let f : (a, ) We say that the real number L is the limit of f as x , and we write provided that for each > 0 there exists a real number N > a such that x > N implies that | f (x) – L | < . Very often as x the values of a given function also get large. This leads to the following definition. Definition 6.3.7 Let f : (a, ) We say that f tends to as x , and we write provided that given any there exists an N > a such that x > N implies that f (x) > . Using these definitions, we can state l’Hospital’s rule for indeterminates of the form /.
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Theorem 6.3.8 (L’Hospital’s Rule) with L , then
Let f and g be differentiable on (a, ). Suppose that limx f (x) = limx g (x) = , and that g (x) 0 for x (a, ). If with L , then The proof is lengthy, but basically consists of the Cauchy mean value theorem and algebra. There is also an extension of l’Hospital’s rule that applies to f /g when lim x c f (x) = lim x c g(x) = and c (See Exercise 13.) There are other limiting situations involving two functions that can give rise to ambiguous values. These indeterminate forms are indicated by the symbols 0 , 00, 1, 0, and – , and are evaluated by using algebraic manipulations, logarithms, or exponentials to change them into one of the forms 0/0 or /.
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Example For x > 0, let f (x) = x and g(x) = – ln x. Then lim x 0+ f (x)g(x) is an indeterminate of the form 0 . To evaluate the limit, we write = 0. From this we also conclude that lim x 0+ x ln x = 0.
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