Download presentation
Presentation is loading. Please wait.
1
MASS - MASS STOICHIOMETRY
Given the mass of a reactant in a reaction, the masses of the products can be determined.
2
MASS - MASS STOICHIOMETRY
PROBLEM: When 34 grams of ammonia reacts with enough oxygen, nitrogen and water vapor are yielded as products. How much water vapor is produced?
3
MASS - MASS STOICHIOMETRY
STEP 2 - BALANCE EQUATION 4 NH O > 2 N H2O
4
MASS - MASS STOICHIOMETRY
STEP 3 - Given the mass of “A”, calculate the moles of “A” by dividing by the MOLAR MASS of “A.” GIVEN: 34 grams of ammonia
5
MASS - MASS STOICHIOMETRY
STEP 3 - 4 NH O > 2 N H2O 34 grams 34 grams x 1mole = grams Molar mass of ammonia 2 moles of ammonia
6
MASS - MASS STOICHIOMETRY
STEP 4 - Convert moles of “A” into moles of “B” using a molar ratio from the coefficients
7
MASS - MASS STOICHIOMETRY
STEP 4 - 4 NH O > 2 N H2O 2 moles 4 moles of NH3 = 2 moles of NH moles of water X X = 3 moles of water
8
MASS - MASS STOICHIOMETRY
STEP 5 - Convert moles of “B” into mass of “B” by multiplying by the MOLAR MASS of “B” 4 NH O > 2 N H2O 3 moles 3 moles x 18 grams = mole Molar mass of water 54 grams of water
9
MASS - MASS STOICHIOMETRY
NOW LETS SEE THE WHOLE THING AT ONCE… 4 NH O > 2 N H2O 34 grams 2 moles 3 moles 54 grams
10
The Question...
11
The Answer
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.