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When Vd4 = Vg4 > Vdd-|Vtp|, want Ms on, VB < Vdd - 2|Vtp|
Start-up When Vd4 = Vg4 > Vdd-|Vtp|, want Ms on, VB < Vdd - 2|Vtp| When Vd4 = Vg4 < Vdd -|Vtp|-Veff, want Ms off VB < Vdd - 2|Vtp| - Veff make VB ~ Vdd-2|Vtp| to Vdd-2|Vtp|-Veff Also make IQ in right branch to be very small. VDD VDD VDD M3 M4 VB Ms M1 M2
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When Vd4 = Vg4 > Vdd-|Vtp|, PMOS are off, VB ~ 0 want Ms on,
Start-up When Vd4 = Vg4 > Vdd-|Vtp|, PMOS are off, VB ~ 0 want Ms on, When Vd4 = Vg4 < Vdd -|Vtp|-Veff, PMOS are on, want VB goes high, Ms off make M6’s saturation current << M5’s saturation current. VDD VDD VDD M3 M4 VB Ms VDD M1 M2
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When Vd4 = Vg4 > Vdd-|Vtp|, PMOS are off, VB ~ 0 want Ms on,
Start-up When Vd4 = Vg4 > Vdd-|Vtp|, PMOS are off, VB ~ 0 want Ms on, When Vd4 = Vg4 < Vdd -|Vtp|-Veff, PMOS are on, want VB goes high, Ms off make M6’s saturation current << M5’s saturation current. VDD VDD VDD M3 M4 VDD VB Ms VDD M1 M2
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Start-up VDD VDD VDD M3 M4 VB M1 M2
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Temperature independent reference
Generate a negatively PTAT (Proportional To Absolute Temperature) and a positively PTAT quantities and sum them appropriately. X can be voltage or current
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Bandgap voltage reference
Chapter 7 Figure 09 Works in bipolar or BiCMOS
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A Common way of bandgap reference
This is easily available in digital CMOS DVBE kT/q
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VBE has negative temp coeff at roughly -2
VBE has negative temp coeff at roughly -2.2 mV/°C at room temperature, called CTAT or NTAT Vt = kT/q is PTAT that has a temperature coefficient of mV/°C at room temperature. Multiply Vt by a constant K and sum it with the VBE to get VREF = VBE + KVt If K is right (2.2/0.08526), temperature coefficient can be zero.
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In general, use VBE + VPTAT
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Bandgap reference still varies a little with temp
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How to get Bipolar in CMOS?
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Layout P-active is E N-well is B P-substrate is C Tie both n-well and p-substrate to Vss Issues: this will not pass LVS Cadence does not know how to simulate
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DVbe = ln(n)kT/q 1:1 1:1 Vref = xDVbe + Vbe = xln(n)kT/q + Vbe + +
VDD VDD VDD 1:1 1:1 Dvbe/R - + Dvbe/R Vref = xDVbe + Vbe = xln(n)kT/q + Vbe = xln(n) Vbe1 + - + - R DVbe xR xDVbe Vbe2 Q nQ nQ IseVbe1/vth nIseVbe2/vth =
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VDD VDD VDD 1:1 1:1 - + Vref R xR Q 8Q 8Q
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Design Steps Convenient ratio: n=8
Select desired current I (e.g. 10 uA) Select R by making I = ln(n)kT/q/R R = ln(8)*26mV/10uA Select xR to make Vref = 1.26 V x = 0.65V/26mV/ln(8) Trim xR to make Vref correct
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Adding more degrees of freedom
VDD VDD VDD m:1 1:r - + Vref R xR Q nQ nQ
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R1 and R3 equal and equal to xR2
Q2 = nQ1 Design steps are identical to before. Chapter 7 Figure 13
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These are popular structures, but not doable in CMOS
Chapter 7 Figure 11 These are popular structures, but not doable in CMOS Chapter 7 Figure 10
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Cascoded CM Cascoded CG amplifier
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Chapter 7 Figure 15
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Banba, Hironori, Hitoshi Shiga, Akira Umezawa, Takeshi Miyaba, Toru Tanzawa, Shigeru Atsumi, and Koji Sakui. "A CMOS bandgap reference circuit with sub-1-V operation." Solid-State Circuits, IEEE Journal of 34, no. 5 (1999):
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