1. The Millikan Experiment: Determining the Elementary Charge
Textbook: 7.5
Homework: pg 364 # 1 – 5

2. Parallel plates capacitor

3. Millikan’s Oil Drop Experiment

4. Millikan’s Oil Drop Experiment

5. Ex. 2
An oil drop of mass 4.95 x kg is balanced between two large, horizontal parallel plates 1.0 cm apart, maintained at a potential difference of 510 V. The upper plate is positive. Calculate the charge on the drop, both in coulombs and as a multiple of the elementary charge, and state whether there is an excess or deficit of electrons.
9.6 x 10^ -19 C; 6e; excess

6. Ex. 1
Two large, horizontal metal plates are separated by m. A small plastic sphere is suspended halfway between them. The sphere experiences an upward electric force of 4.5 x N, just sufficient to balance its weight.
(a) If the charge on the sphere is 6.4 x C, what is the potential difference between the plates?
(b) Calculate the mass of the sphere.
(a) 3.5 x 10^2 V
(b) 4.6 x 10^ -16 kg

7. Motion of charged particles in an electric field
Textbook: 7.6
Homework: pg 368 # 1, 3, 5
pg 371 # 1, 2, 5

8. Motion of charged particles in an electric field
Derive using conservation of energy

9. Ex. 3
The cathode in a typical cathode-ray tube (Figure 4), found in a computer terminal or an oscilloscope, is heated, which makes electrons leave the cathode. They are then attracted toward the positively charged anode. The first anode has only a small potential rise while the second is at a large potential with respect to the cathode. If the potential difference between the cathode and the second anode is 2.0 x 104 V, find the final speed of the electron.
Mass of an electron = 9.1*10^-31kg
Charge of an electron = 1.6*10^-19 C
The final speed of the electron is 8.4 x 10^7 m/s.

11. Ex. 4.
An electron is fired horizontally at 2.5 x 106 m/s between two horizontal parallel plates 7.5 cm long, as shown in Figure 7. The magnitude of the electric field is 130 N/C. The plate separation is great enough to allow the electron to escape. Edge effects and gravitation are negligible. Find the velocity of the electron as it escapes from between the plates.
The final velocity is 2.6 x 10^6 m/s [right 15° up from the horizontal]

12. Textbook: 8.1 – 8.2 Homework: pg. 391 #1, 2, 7
Magnetism
Textbook: 8.1 – 8.2
Homework: pg. 391 #1, 2, 7

13. What do we know about magnetism?
LEDs
Incandescent lights
What do we know about magnetism?
- They have poles
- Opposite poles attract, similar poles repel
- It is an action-at-a-distance force (therefore can be described in terms of fields)
- One of the oldest known forces (magnetite was a naturally occurring magnet)
- Is used for navigation (Earth’s iron core creates a magnetic field aligned in the NS direction)
What are some properties of magnets?
- Things can be magnetized and demagnetized
- When a magnet is broken in half it makes two smaller magnets
- Some objects when magnetized maintain the field, others do not
- Heating, dropping and striking a magnet can demagnetize it
- A strong magnetic field can reverse the direction of a bar magnet

14. Domain Theory
Ferromagnetic materials can be magnetized (ex. Iron, nickel, cobalt)
Ferromagnetic materials are made up of tiny magnetic domains which act like miniature magnets
If, on average, the magnetic domains align they create an induced magnet

15. Electromagnetism
Oersted’s Principal: A moving electric current induces a magnetic field
The direction of the induced electromagnetic field can be determined using the Right Hand Rules.

16. RHR for straight conductor
RHR for solenoid

17. Relative permeability: is the ratio of the magnetic field strength for a particular core material to the magnetic field strength in the absent of the material.

18. Magnetic Force on Moving Charges

19. Draw the magnetic fields of the permanent magnet and the conductor.
Determine the direction of the force on the conductor.

20. Show the labels of the magnetic poles, the magnetic field, and the direction of force on the conductor

21. Describe the path of current through the conductor, brushes, commutator, and coil by adding arrows. Identify the magnetic polarity of the armature and the rotation direction of the motor.

22. Textbook: 8.2 Homework: pg. 396 # 3 – 5 pg. 402 # 1 – 3 , 10
Magnetic Forces
Textbook: 8.2
Homework: pg. 396 # 3 – 5
pg. 402 # 1 – 3 , 10
Demo: Jumping electric wires

23. Magnetic Forces
The magnetic force, FM [N], on a particle of charge q [C] moving through a magnetic field strength B [T, teslas] at a velocity v [m/s] is found by:
Where  is the angle between B and v
Pg. 396 #2, 3, 4

24. Pg 396 # 2
Determine the magnitude and direction of the magnetic force on a proton moving horizontally northward at 8.6 x 104 m/s, as it enters a magnetic field of 1.2 T directed vertically upward.
1.7 x 10^-14 N [E]

25. (c) Calculate the radius of the electron’s circular path.
An electron accelerates from rest in a horizontally directed electric field through a potential difference of 46 V. The electron then leaves the electric field, entering a magnetic field of magnitude 0.20 T directed into the page (Figure 7).
(a) Calculate the initial speed of the electron upon entering the magnetic field.
(b) Calculate the magnitude and direction of the magnetic force on the electron.
(c) Calculate the radius of the electron’s circular path.
4.0 x 10^6 m/s
1.3 x 10^-13 [down]
1.1 x 10^-4 m

26. Motion in Magnetic Fields
A charged particle moving through a constant magnetic field moves in a circular path
J.J. Thomson and the e/m ratio
e/m = 1.76 x 1011 C/kg
The Van Allen Belt (Aurora)
Particle Accelerators

27. Textbook: 8.3, 8.4, 8.5 Homework: pg. 407 #1 – 5 pg. 414 #1 - 4, 6, 9
Magnetic Force on a Conductor, Ampere’s Law & Electromagnetic Induction
Textbook: 8.3, 8.4, 8.5
Homework: pg. 407 #1 – pg. 414 #1 - 4, 6, 9
pg. 419 #1, 3, 8

28. FM on a Conductor in a Magnetic field:
The magnetic force FM [N] on a conductor of length l [m] carrying a current I [A] through a magnetic field B [T] is:
Where  is the angle between I and B
RHR: Thumb points in direction of +ve I, fingers in direction of B, palm pushes in direction of FM

29. Review - around a conductor:
Magnetic field strength is proportional to current:
Magnetic field strength is inversely proportional to radius:
Therefore:

30. Ampère’s Law
Along any closed path through a magnetic field, the sum of the products of the scalar component of B, parallel to the path segment with the length of the segment, is directly proportional to the net electric current passing through the area enclosed by the path.

31. Ampere’s Law Take a closed path in B Add up B||l around path
Sum equals 0I
Permeability of free space 0 = 4 x 10-7 Tm/A

32. FM between TWO CONDUCTORS

33. Two parallel straight conductors 5
Two parallel straight conductors 5.0 m long and 12 cm apart are to have equal currents. The force each conductor experiences from the other is not to exceed 2.0 x 10-2 N. What is the maximum possible current in each conductor?
49 A

34. Applications Coaxial Cable (see pg. 410) Definition of Ampere/Coulomb
Electric Shielding
Magnetic Shielding
Definition of Ampere/Coulomb
A current of 1 A in parallel wires 1 m apart in a vacuum creates a force of 2 x 10-7 N per meter
1 C is the charge transported by 1 A in 1 s

35. Maglev Trains Opposite poles levitate train
Guide magnets change polarity to push and pull train
Very little friction leads to very high speeds (World Record is 581 km/h)

36. Electromagnetic Induction
A changing electric field (i.e. a current) induces a magnetic field
A changing magnetic field induces a current in nearby conductors
Examples:
Electric Generators
Transformers
Guitar Pickups

37. Lenz’s Law
The direction of an induced current is such that it opposes the changing magnetic field that created it

38. Magnitude of the magnetic field strength in the core of the solenoid
B is the magnitude of the magnetic field strength in the core of the solenoid, in teslas;
I is the current flowing through the coil, in amperes;
L is the length of the solenoid, in metres;
N is the number of turns on the coil.

39. Pg 418 # 3
Two magnets are dropped through thin metal rings (Figure 11). One of the rings has a small gap.
(a) Will both magnets experience a retarding force? Explain your reasoning
(b) Will your answers change if the rings are replaced with long cylinders, one with a long thin gap down one side?