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(x + 4)(x + 7) (x + 14)(x + 2) = x2 + 11x + 28 = x2 + 16x + 28

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Presentation on theme: "(x + 4)(x + 7) (x + 14)(x + 2) = x2 + 11x + 28 = x2 + 16x + 28"— Presentation transcript:

1 (x + 4)(x + 7) (x + 14)(x + 2) = x2 + 11x + 28 = x2 + 16x + 28
Warm-up Find the product. (x + 4)(x + 7) (x + 14)(x + 2) = x2 + 11x + 28 = x2 + 16x + 28 Factor. 3. 10x + 25 4. 28x2 + 35x 5. 6n2 + 15n = 5(2x + 5) = 7x(4x + 5) = 3n(2n + 5)

2 Homework Questions?

3 Skills Check

4 How do we factor trinomials?
GSE Algebra UNIT QUESTION: In what ways can algebraic methods be used in problems solving? Standard: MM1A2 Today’s Question: How do we factor trinomials? Standard: MM1A2f

5 Sign Rule: When the last term is POSITIVE…
The signs inside the parenthesis will be the SAME as the middle number’s sign

6 Figuring out the Numbers
Check to see… What multiplies to give you the last number AND adds to give you the middle number?

7 x2 +7x + 6 x2 +7x + 6 ( )( ) x x + 6 + 1

8 x2 + 9x + 14 x2 + 9x + 14 ( )( ) x x + 7 + 2

9 x2 – 6x + 8 x2 – 6x + 8 ( )( ) x x – 4 – 2

10 x2 – 10x + 16 x2 – 10x + 16 ( )( ) x x – 8 – 2

11 Sometimes you can factor out a GCF 1st!

12 2x2 – 16x + 24 2(x2 – 8x +12) 2( )( ) x x – 6 – 2

13 You Try... 3y2 + 36y + 60 3(y +10)(y +2) 4x2 +24x + 32 4(x + 2)(x + 4)

14 Sign Rule: When the last term is NEGATIVE…
The parenthesis will have DIFFERENT SIGNS. The larger factor will have the SAME sign as the middle number

15 n2 + 2n – 48 ( )( ) n n + 8 – 6

16 x2 + 8x – 20 ( )( ) x x – 2 + 10

17 x2 – 4x – 21 ( )( ) x x + 3 – 7

18 x2 – 9x – 36 ( )( ) x x + 3 – 12

19 Homework Stupid Puzzle Sheet


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