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Section 9.3—Analysis of a Chemical Formula

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1 Section 9.3—Analysis of a Chemical Formula
How can we determine a chemical formula?

2 Percent Composition How is percent composition found?

3 What is Percent Composition?

4 Example #1 Example: A 8.5 g sample is composed of carbon and hydrogen. If 5.5 g of the sample is found to be carbon, what is the percent composition by mass of the sample?

5 Example #1 If total = 8.5 g and C = 5.5 g - then H = 3.0 g Example:
A 8.5 g sample is composed of carbon and hydrogen. If 5.5 g of the sample is found to be carbon, what is the percent composition by mass of the sample? If total = g and C = g - then H = 3.0 g

6 Let’s Practice #1 A sample is 57.0% by mass chlorine, how many grams of chlorine are present in a 27.5 g sample?

7 Let’s Practice #1 A sample is 57.0% by mass chlorine, how many grams of chlorine are present in a 27.5 g sample? 27.5 g   27.5 g 100 100

8 Example #2 Percent composition can also be determined from a chemical formula Example: Find the percent composition, by mass, of CaCl2

9 Example #2 Percent composition can also be determined from a chemical formula Example: Find the percent composition, by mass, of CaCl2 Ca Cl 1 2 40.08 g/mole 35.45 g/mole = 70.90 g/mole + g/mole So for 1 mole: total = g Ca = g Cl = 70.90 g

10 Let’s Practice #2 Find the percent composition, by mass, of NaNO3

11 Find the percent composition, by mass, of NaNO3
Let’s Practice #2 Find the percent composition, by mass, of NaNO3 Na N 1 22.99 g/mole 14.01 g/mole = + 85.00 g/mole O 3 16.00 g/mole 48.00 g/mole

12 Empirical Formulas

13 What’s an Empirical Formula?
Empirical Formula –Lowest possible ratio of atoms CH2 is the lowest ratio (and empirical formula) of the molecule C3H6

14 Ratio of Atoms in a Molecule
Subscripts in a chemical formula show the ratio of atoms (or ions) in a molecule a sample of CaCl2 has 1 calcium ion : 2 chlorine ions If the subscripts give the ratio of atoms, then they also give the ratio of moles of atoms a sample of CaCl2 has 1 mole of calcium ions : 2 moles of chlorine ions We can use the unit “mole” to count things Atoms and ions can be counted by “moles”

15 Using Mole Ratio of Atoms in a Molecule
Therefore, if the ratio of moles of each atom is found… then the subscripts of the chemical formula are known 1 mole C 2 mole H CH2

16 Example #3 If given percents, use those percents as grams (as if you assume you have a 100 g sample)—Remember %’s add up to 100! 1 2 Change grams to moles for each atom Divide all moles by the smallest # of moles. We do this to find the lowest possible whole number ratios of the atoms 3 4 Use the ratio as subscripts for writing the chemical formula Example: Find the empirical formula if a sample contains Ca and Cl and is 36.1% Ca

17 Example #3 If given percents, use those percents as grams (as if you assume you have a 100 g sample)—Remember %’s add up to 100! 1 2 Change grams to moles for each atom Find the lowest possible whole number ratio of the atom (divide all moles by the smallest # of moles) 3 4 Use the ratio as subscripts for writing the chemical formula Example: Find the empirical formula if a sample contains Ca and Cl and is 36.1% Ca 36.1 g Ca 1 mol Ca = _____ mol Ca 0.901 40.08 g Ca CaCl2 63.9 g Cl 1 mol Cl = _____ mol Cl 1.80 35.45 g Cl 0.901 mol Ca = 1 mol Ca 0.901 1.80 mol Cl = 2 mol Cl 0.901

18 Find the empirical formula if a sample contains
Let’s Practice #3 Find the empirical formula if a sample contains 40.92 g C, 4.58 g H and 54.5 g O 40.92 g C = _____ mol C g C mol C 1 12.01 3.41 4.58 g H = _____ mol H g H mol H 1 1.01 4.53 54.5 g O = _____ mol O g O mol O 1 16.00 3.41 C3H4O3 3.41 mol C = 1 mol C 3.41 4.53 mol H = 1.33 mol H 3.41 3.41 mol O = 1 mol O 3.41 Multiply the ratio (1 : 1.33 : 1) by 3 to make a whole number ratio (3 : 4: 3)

19 Molecular Formulas

20 What’s a Molecular Formula?
Empirical Formula –Lowest possible ratio of atoms Molecular Formula – Actual ratio of atoms in a molecule

21 Empirical versus Molecular Formula
The empirical formula is the lowest possible ratio. The molecular formula is the actual ratio A molecule with the empirical formula: Could have one of the following molecular formulas: NO2 NO2, N2O4, N4O8… CH2 CH2, C2H4, C4H8…

22 Find the molecular formula.
Example #4 1 Find the empirical formula, if not given 2 Find the molar mass of the empirical formula Find the ratio of the molecular formula’s molar mass (must be given to you) to the empirical formula’s molar mass 3 Multiply the empirical formula’s subscripts by the ratio found in step 3. 4 Example: Empirical formula = C3H4O3. The molecular formula’s molar mass = g/mole. Find the molecular formula.

23 Find the molecular formula.
Example #4 1 Find the empirical formula, if not given 2 Find the molar mass of the empirical formula Find the ratio of the molecular formula’s molar mass (must be given to you) to the empirical formula’s molar mass 3 Multiply the empirical formula’s subscripts by the ratio found in step 3. 4 Example: Empirical formula = C3H4O3. The molecular formula’s molar mass = g/mole. Find the molecular formula. g/mole = 2 88.07 g/mole C 3 12.01 g/mole = 36.03 g/mole H 4 1.01 g/mole = 4.04 g/mole C3H4O3  2 O 3 16.00 g/mole = + 48.00 g/mole C6H8O6 88.07 g/mole

24 Hydrate Formulas

25 What’s a Hydrate? Hydrate – Molecule that has water physically attached to it It’s not dissolved in water…hydrates can be solid, liquid or gas! The Crystal would look dry! The water is trapped within the crystal! BaI2  2 H2O This means there are 2 water molecules attached to each BaI2 molecules

26 Hydrate & anhydride Hydrate = molecule with water molecules physically attached anhydride = molecule with water removed The water can be removed by heating the hydrate Hydrate anhydride + water heat Finding the ratio of anhydride molecules to water molecules gives you the hydrate formula

27 Example #5 Example: What is the percent mass of water on the following hydrate? MgSO4•7H2O Percent Mass of Water = The part of the mass that is water X 100 The Whole mass of the hydrate = __7(H2O) x 100 MgSO4•7H2O = (18) x 100 246.38 =51.2%


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