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Agenda 1/9/16 1. Quick review 2. Stoichiometry Notes

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Presentation on theme: "Agenda 1/9/16 1. Quick review 2. Stoichiometry Notes"— Presentation transcript:

1 Agenda 1/9/16 1. Quick review 2. Stoichiometry Notes
Welcome Back!! Agenda 1/9/16 1. Quick review 2. Stoichiometry Notes

2 Stoichiometric Calculations
Stoichiometry Stoichiometric Calculations

3 A. Proportional Relationships
2 1/4 c. flour 1 tsp. baking soda 1 tsp. salt 1 c. butter 3/4 c. sugar 3/4 c. brown sugar 1 tsp vanilla extract 2 eggs 2 c. chocolate chips Makes 5 dozen cookies. I have 5 eggs. How many cookies can I make? Ratio of eggs to cookies 5 eggs 5 doz. 2 eggs = 12.5 dozen cookies

4 A. Proportional Relationships
Stoichiometry relationships between substances in a chemical reaction based on the mole ratio Mole Ratio indicated by coefficients in a balanced equation 2 Mg + O2  2 MgO

5 What can we do with Stoichiometry?
For the generic equation: RA +RB → P1 + P2 Given the… …one can find the… Amount of one reactant Amount of other reactant that is needed to react with it Amount of reactant Amount of product that will be produced Amount of product you need to produce Amount of reactant you must use

6 B. Stoichiometry Steps 1. Write a balanced equation.
2. Identify the given and find. 3. Line up conversion factors. Mole ratio - moles  moles Convert amount of Substance A into moles (if needed) Use a Mole ratio (must be included in ALL stoichiometry problems) Convert moles of Substance B into desired unit 4. Check answer.

7 Given the equation… 2TiO2 + 4Cl2 + 3C → 2TiCl4 + CO2 + 2CO
How many mol chlorine will react with 4.55 mol carbon? Given: 4.55 mole C Find: mole Cl2 6.07 mol Cl2

8 Given the same equation…
2TiO2 + 4Cl2 + 3C → 2TiCl4 + CO2 + 2CO What mass titanium (IV) oxide will react with 4.55 mol carbon? given = 4.55 mol C find = mass of TiO2 g TiO2

9 D. Stoichiometry Problems
How many moles of KClO3 must decompose in order to produce 9 moles of oxygen gas? 2KClO3  2KCl + 3O2 ? mol 9 mol 9 mol O2 2 mol KClO3 3 mol O2 = 6 mol KClO3

10 D. Stoichiometry Problems
How many grams of KClO3 are req’d to produce 9.00 L of O2 at STP? 2KClO3  2KCl + 3O2 ? g 9.00 L 9.00 L O2 1 mol O2 22.4 L 2 mol KClO3 3 mol O2 122.55 g KClO3 1 mol KClO3 = 32.8 g KClO3

11 D. Stoichiometry Problems
How many grams of silver will be formed from 12.0 g copper? Cu + 2AgNO3  2Ag + Cu(NO3)2 12.0 g ? g 12.0 g Cu 1 mol Cu 63.55 g Cu 2 mol Ag 1 mol Cu 107.87 g Ag 1 mol Ag = 40.7 g Ag

12 D. Stoichiometry Problems
How many grams of Cu are required to react with 1.5 L of 0.10M AgNO3? Cu + 2AgNO3  2Ag + Cu(NO3)2 ? g 1.5L 0.10M 1.5 L .10 mol AgNO3 1 L 1 mol Cu 2 mol AgNO3 63.55 g Cu 1 mol Cu = 4.8 g Cu

13 The Limiting Reactant A balanced equation for making a Big Mac® might be: 3 B M + EE  B3M2EE With… …and… …one can make… 30 M excess B and excess EE 15 B3M2EE 30 B excess M and excess EE 10 B3M2EE 30 B and excess EE

14 A balanced equation for making a tricycle might be:
3 W P + S + H + F  W3P2SHF With… …and… …one can make… 50 P excess of all other reactants 25 W3P2SHF 50 S 50 W3P2SHF 50 S and excess of all other reactants

15 Solid aluminum reacts w/chlorine gas to yield solid aluminum chloride.
Al(s) Cl2(g)  AlCl3(s) If 125 g aluminum react w/excess chlorine, how many g aluminum chloride are made? = g AlCl3

16 If 125 g chlorine react w/excess aluminum, how many g aluminum chloride are made?
= g AlCl3 If 125 g aluminum react w/125 g chlorine, how many g aluminum chloride are made? g AlCl3 We’re out of Cl2.

17 limiting reactant (LR): the reactant that runs out first
Amount of product is based on LR. Any reactant you don’t run out of is an excess reactant (ER).

18 Example Limiting Reactant Excess Reactant(s) Big Macs buns meat tricycles pedals W, S, H, F Al / Cl2 / AlCl3 Cl2 Al

19 How to Find the Limiting Reactant
For the generic reaction RA RB  P Assume that the amounts of RA and RB are given. Should you use RA or RB in your calculations?

20 How to find LR steps… 1. Calc. # of mol of RA and RB you have.
2. Divide by the respective coefficients in balanced equation. 3. Reactant having the smaller result is the LR.


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