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Geometry 11.5 Solar Eclipses
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11.5 Tangents and Secants Objectives
Determine the relationship between a tangent line and a radius. Determine the relationship between congruent tangent segments. Prove the Tangent Segment Theorem. Prove the Secant Segment Theorem. Prove the Secant Tangent Theorem.
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Problem 2: Tangent Segments
Tangent Segment: A segment formed from an exterior point of the circle to the point of tangency. Together 1-3
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Problem 2: Tangent Segments
Tangent Segment Theorem: If two tangent segments are drawn from the same point on the exterior of a circle, then the tangent segments are congruent. Sketchpad Demo Tangent-Tangent Segments πππ πππππππ‘=πππ πππππππ‘ Collaborate 5-6 (3 Minutes)
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Problem 3: Secant Segments
Secant Segment: Formed when two secants intersect in the exterior of a circle. Secant Segment: Begins at the point of intersection between two secants, continues into the circle, and ends at a point at which the secant intersects the circle. External Secant Segment: Part of the secant segment that lies outside the circle.
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Problem 3: Secant Segments
Together #1
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Problem 3: Secant Segments
Secant Segment Theorem: If two secants intersect in the exterior of a circle, then the product of the lengths of the secant segment and its external secant segment is equal to the product of the lengths of the second secant segment and its external secant segment. Sketchpad Demo Secant-Secant Segments πππ 1 β πΈπ₯π‘ 1 = πππ 2 β πΈπ₯π‘ 2
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Problem 3: Secant Segments
Together #3
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Problem 3: Secant Segments
Secant Tangent Theorem: If a tangent and a secant intersect in the exterior of a circle, then the product of the lengths of the secant segment and its external secant segment is equal to the square of the length of the tangent segment. Sketchpad Demo Secant-Tangent Segments πππβπΈπ₯π‘= πππ 2
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Check for Understanding
What kinds of lines do we have? πππβπΈπ₯π‘= πππ 2 8βπ= 4 2 8π=16 π=2 πππβππ
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Formative Assessment Skills Practice 11.5 Vocabulary Pg. 817 (1-6) Pg (2-42) Even Due Today Tangent-Tangent Segments πππ πππππππ‘=πππ πππππππ‘ Secant-Tangent Segments πππβπΈπ₯π‘= πππ 2 Secant-Secant Segments πππ 1 β πΈπ₯π‘ 1 = πππ 2 β πΈπ₯π‘ 2
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