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“ENERGY PRINCIPLE:UNIT LOAD FOR DETERMINATE STRUCTURE”

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Presentation on theme: "“ENERGY PRINCIPLE:UNIT LOAD FOR DETERMINATE STRUCTURE”"— Presentation transcript:

1 “ENERGY PRINCIPLE:UNIT LOAD FOR DETERMINATE STRUCTURE”
Narnarayan Shastri Institute of Technology STRUCTURE ANALYSIS-ǁ “ENERGY PRINCIPLE:UNIT LOAD FOR DETERMINATE STRUCTURE” Prepared by, Harsh Patel( ) Satyam Bhimani( ) Vidhi Patel( ) Prachi Shah( ) Guided By, Samir Gami Asst. Prof. of Civil Engginerring NSIT, Jetalpur

2 Energy principle of unit load for determinate structure
δ= ……deflection Ѳ = …………Slope Where, M=moment at section X due to applied load m=Moment at section X due to unit force or unit moment.

3 Example 1:compute deflection at point C of cantilever beam shown in the figure. For the beam E= I = Solution : To find deflection at C. apply unit load 1 kN at C.

4 ( Segment ORIGIN Limits M m BC B 0 to 3 CA C 0 to 3 -20(x+3) -1(x)
CA C 0 to 3 -20(x+3) -1(x) ( =7.5 mm

5 Example 2: Determine deflection at free end of a cantilever beam using unit load method. Solution:
Segment ORIGIN Limits M m BC B 0 to 4 -20x CA C 0 to 4 -20(x+3) -1(x)

6 To find deflection at C. apply unit load 1 kN at C.

7 Example: 3 Determinate deflection at the free end C of a beam ABC shawn in figure.Take
Segment Origin Limits M m AD A 0 to 4 10x -0.25x DB D 10(x-4)-30x -0.25(x+4) CB C 0 to 2 -20x -1.x

8 Solution: Taking moments about A. To find δ,apply unit load at C

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10 Example 4: Find vertical and horizontal displacement at C for a cantilever frame using unit load method. Solution: Segment Origin Limits M m1 m2 I CB C 0 to 2 -1 x BA B 0 to 6 -4 x 2 x 1 -2 -1x 2I

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13 Thank You


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