1. a. DNA ligase
b. DNA polymerase
c. RNA polymerase
d. Restriction enzyme
e. Reverse transcriptase
f. Transformation
Enzyme found in retroviruses that produce
DNA from an RNA template.
Enzyme used during replication to attach
Okazaki fragments to each other.
Our bacteria that produced biolumescent
proteins.
Answer: e
Answer: a
Answer: f

2. Which of these is a true statement?
Both plasmids and viruses can serve as
vectors.
b. Plasmids can carry recombinant DNA but
viruses cannot.
c. Vectors carry only the foreign gene into the
host cell.
d. All of these statements are true.
Answer: a

3. Put the following phrases in order to form a
plasmid carrying recombinant DNA.
1. use restriction enzyme
2. use DNA ligase
3. remove plasmid from parent bacterium
4. introduce plasmid into new host bacterium
1, 2, 3, 4
4, 3, 2, 1
3, 1, 2, 4
2, 3, 1, 4
Answer: c

4. Restriction endonucleases (enzymes) cut DNA.
are naturally found in prokaryotic cells.
are naturally found in eukaryotic cells.
both a and b
all of the above
Mrs. Ohlsen is the best Biology teacher in HISTORY! Eat Mor Chikin
Answer: d

5. The separation of DNA fragments by gel
electrophoresis is primarily achieved by
differential
sizes of fragments.
charges of fragments.
solubilities of fragments.
cleavage points of fragments.
radioactivity of fragments.
Answer: a

6. Which of the following is used for amplification?
Transformation
Polymerase chain reaction (PCR)
Restriction fragment length polymorphism
(RFLP)
d. Recombinant DNA technology
e. All of these
Answer: b

7. Which of the following is NOT needed to
make a recombinant DNA molecule?
foreign DNA
vector DNA
restriction enzymes
DNA ligase
DNA polymerase
Answer: e

8. Genetically engineered plants have or will
be used to
resist insects
resist herbicides
produce protein-enhanced beans, corn, and
wheat
d. produce animal neuropeptides, blood factors,
and growth hormones.
e. All of these are correct.
Answer: e

9. DNA that is made from mRNA is called
nonsense DNA (nDNA)
antisense DNA (aDNA)
complementary DNA (cDNA)
uncomplementary DNA (uDNA)
recombinant DNA (rDNA)
Answer: c

10. Foreign DNA can be inserted into vector DNA
because both DNA molecules
have the same genes.
have the same bases.
have “sticky ends”.
are not complementary to each other.
All of these are correct.
Answer: c

11. Which enzyme is used to seal breaks in a
DNA molecule?
DNA polymerase
RNA polymerase
restriction enzymes
DNA ligase
RNA ligase
Answer: d

12. Which of the following is NOT a form of
genetic recombination in bacteria?
binary fission
conjugation
transduction
transformation
All are forms of recombination.
Answer: a

13. In a transformation experiment, a sample of E
In a transformation experiment, a sample of E. coli bacteria was mixed with a plasmid containing the gene for resistance to the antibiotic ampicillin (ampr). Plasmid was not added to a second sample. Samples were plated on nutrient agar plates, some of which were supplemented with the antibiotic ampicillin. The results of E. coli growth are summarized below. The shaded area represents extensive growth of bacteria; dots represent individual colonies of bacteria.
Plates that have only ampicillin-resistant bacteria growing include which of the following?
I only
III only
IV only
I and II
Answer: c
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14. Answer: A Nutrient agar inhibits E. coli growth.
In a transformation experiment, a sample of E. coli bacteria was mixed with a plasmid containing the gene for resistance to the antibiotic ampicillin (ampr). Plasmid was not added to a second sample. Samples were plated on nutrient agar plates, some of which were supplemented with the antibiotic ampicillin. The results of E. coli growth are summarized below. The shaded area represents extensive growth of bacteria; dots represent individual colonies of bacteria.
Which of the following best explains why there is no growth on plate II?
The initial E. coli culture was not ampicillin resistant.
The transformation procedure killed the bacteria.
Nutrient agar inhibits E. coli growth.
The bacteria on the plate were transformed.
Answer: A
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15. In a transformation experiment, a sample of E
In a transformation experiment, a sample of E. coli bacteria was mixed with a plasmid containing the gene for resistance to the antibiotic ampicillin (ampr). Plasmid was not added to a second sample. Samples were plated on nutrient agar plates, some of which were supplemented with the antibiotic ampicillin. The results of E. coli growth are summarized below. The shaded area represents extensive growth of bacteria; dots represent individual colonies of bacteria.
Plates I and III were included in the experimental design in order to
demonstrate that the E. coli cultures were viable.
demonstrate that the plasmid can lose its ampr gene.
demonstrate that the plasmid is needed for E. coli growth.
prepare the E. coli for transformation.
Answer: a
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16. In a transformation experiment, a sample of E
In a transformation experiment, a sample of E. coli bacteria was mixed with a plasmid containing the gene for resistance to the antibiotic ampicillin (ampr). Plasmid was not added to a second sample. Samples were plated on nutrient agar plates, some of which were supplemented with the antibiotic ampicillin. The results of E. coli growth are summarized below. The shaded area represents extensive growth of bacteria; dots represent individual colonies of bacteria.
Which of the following statements best explains why there are fewer colonies on plate IV than on plate III?
Plate IV is the positive control.
Not all E. coli cells are successfully transformed.
The bacteria on plate III did not mutate.
The plasmid inhibits E. coli growth.
Answer: B
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17. The picture above represents some stages in the early development of an embryo. Which of
these stages shows
1. the end of morulation.
2. blastulation.
3. the beginning of gastrulation.
Answer: 3
Answer: 4
Answer: 5

18. The DNA fragment indicated is approximately ____ base pairs in size.
bp?

19. Does suspect A have more or less repeats at TPO than the crime scene DNA?
The same
L – ladder; CS – crime scene
L CS A B B
100
TH01 90 80 70 60 50 40
TPOX

20. Which suspect likely committed the crime?A. B.

21. What is the chance that someone might have 5 and 7 repeats for the STR THO1 just by accident?
STR THO1 allele
frequencies 5 6 7 8 9
9.3 10
1/200
1/4
1/6
1/7
1/3
1/100
A: 1/200
B: 1/206
C: 1/600
D: 1/1200
E: 1/2600